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jishanBest ResponseYou've already chosen the best response.0
zarkon brother help me.
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.1
take the log and use l'hospitals rule
 11 months ago

shubhamsrgBest ResponseYou've already chosen the best response.0
in (1+ f(x))^(g(x)) , where f(x) >0 and g(x) > inf, mug it up that the final ans is e^( (f(x) g(x) )
 11 months ago

jishanBest ResponseYou've already chosen the best response.0
solve step by step i m not understand.
 11 months ago

RolyPolyBest ResponseYou've already chosen the best response.0
Let \[\large y = ( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = \ln ( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = (tan\frac{\pi a}{2x})\ln( 2\frac{ a}{x})\]Take limit on both sides\[\lim_{x\rightarrow a}(\ln\large y) = \lim_{x\rightarrow a}[(tan\frac{\pi a}{2x})\ln( 2\frac{ a}{x})]\]Evaluate the limit on the right by l'hopital's rule. Then\[ \lim_{x\rightarrow a}( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}} = \lim_{x\rightarrow a} y = e^{\lim_{x\rightarrow a}lny}\], which is e^(the things you get after evaluating that limit)
 11 months ago
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