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jishan Group TitleBest ResponseYou've already chosen the best response.0
dw:1368908835547:dw
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
zarkon brother help me.
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
take the log and use l'hospitals rule
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
furher explain bro.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
in (1+ f(x))^(g(x)) , where f(x) >0 and g(x) > inf, mug it up that the final ans is e^( (f(x) g(x) )
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
solve step by step i m not understand.
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
what is ans.
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Let \[\large y = ( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = \ln ( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = (tan\frac{\pi a}{2x})\ln( 2\frac{ a}{x})\]Take limit on both sides\[\lim_{x\rightarrow a}(\ln\large y) = \lim_{x\rightarrow a}[(tan\frac{\pi a}{2x})\ln( 2\frac{ a}{x})]\]Evaluate the limit on the right by l'hopital's rule. Then\[ \lim_{x\rightarrow a}( 2\frac{ a}{x})^{tan\frac{\pi a}{2x}} = \lim_{x\rightarrow a} y = e^{\lim_{x\rightarrow a}lny}\], which is e^(the things you get after evaluating that limit)
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
ans is what????
 one year ago
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