Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jishan

  • 2 years ago

evaluate lim x->a ( 2- a/x)^tanpia/2x

  • This Question is Closed
  1. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1368908835547:dw|

  2. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    zarkon brother help me.

  3. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    take the log and use l'hospitals rule

  4. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    furher explain bro.

  5. shubhamsrg
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in (1+ f(x))^(g(x)) , where f(x) ->0 and g(x) -> inf, mug it up that the final ans is e^( (f(x) g(x) )

  6. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    solve step by step i m not understand.

  7. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is ans.

  8. RolyPoly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let \[\large y = ( 2-\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = \ln ( 2-\frac{ a}{x})^{tan\frac{\pi a}{2x}}\]\[\ln\large y = (tan\frac{\pi a}{2x})\ln( 2-\frac{ a}{x})\]Take limit on both sides\[\lim_{x\rightarrow a}(\ln\large y) = \lim_{x\rightarrow a}[(tan\frac{\pi a}{2x})\ln( 2-\frac{ a}{x})]\]Evaluate the limit on the right by l'hopital's rule. Then\[ \lim_{x\rightarrow a}( 2-\frac{ a}{x})^{tan\frac{\pi a}{2x}} = \lim_{x\rightarrow a} y = e^{\lim_{x\rightarrow a}lny}\], which is e^(the things you get after evaluating that limit)

  9. jishan
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ans is what????

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy