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ikoreanx3
 one year ago
For the functions given, find a) (f*g)(x) b) (f*g)(2)
f(x)=x3, g(x)=x+6
a) (f*g)(x) = ?
b) (f*g)(2)= ?
ikoreanx3
 one year ago
For the functions given, find a) (f*g)(x) b) (f*g)(2) f(x)=x3, g(x)=x+6 a) (f*g)(x) = ? b) (f*g)(2)= ?

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jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0so, multiply them then

johnanon93
 one year ago
Best ResponseYou've already chosen the best response.1so here, you literally just plug in those functions wherever you see f(x) and g(x) example (f*g)(x) you have an f(x), and you have a g(x)...plug them in (x  3) * (x + 6) can you do this?

johnanon93
 one year ago
Best ResponseYou've already chosen the best response.1correct...that would be your a) now for b) you have (f*g)(2) ....notice how the (2) is where the (x) was before....so what do you think you do with that 2?

ikoreanx3
 one year ago
Best ResponseYou've already chosen the best response.0so it is written (x3)*(x+6)(2)?

johnanon93
 one year ago
Best ResponseYou've already chosen the best response.1no not quite...where you see that (2) is exactly where you saw the (x) ....did you write the other one as (x3)*(x+6)(x)? no because that wouldn't have worked. instead you used that (x) and you plugged it in for every x you saw in the equation a.k.a (x  3)*(x + 6) **same right? so now....you would plug (2) in for EVERY "x" you see in the equation you derived from finding (f*g)(x) remember how you had gotten x² + 3x  18 now...you would plug 2 into that equation wherever you see an "x"

ikoreanx3
 one year ago
Best ResponseYou've already chosen the best response.0So then... it would be (2)^2+3(2)18 =

ikoreanx3
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much :)
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