For the functions given, find a) (f*g)(x) b) (f*g)(2)
a) (f*g)(x) = ?
b) (f*g)(2)= ?
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so, multiply them then
so here, you literally just plug in those functions wherever you see f(x) and g(x)
you have an f(x), and you have a g(x)...plug them in
(x - 3) * (x + 6)
can you do this?
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correct...that would be your a)
now for b) you have (f*g)(2) ....notice how the (2) is where the (x) was before....so what do you think you do with that 2?
so it is written (x-3)*(x+6)(2)?
no not quite...where you see that (2) is exactly where you saw the (x) ....did you write the other one as
(x-3)*(x+6)(x)? no because that wouldn't have worked.
instead you used that (x) and you plugged it in for every x you saw in the equation a.k.a
(x - 3)*(x + 6) **same right?
so now....you would plug (2) in for EVERY "x" you see in the equation you derived from finding (f*g)(x)
remember how you had gotten
x² + 3x - 18
now...you would plug 2 into that equation wherever you see an "x"