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ikoreanx3
 2 years ago
For the functions given, find a) (f*g)(x) b) (f*g)(2)
f(x)=x3, g(x)=x+6
a) (f*g)(x) = ?
b) (f*g)(2)= ?
ikoreanx3
 2 years ago
For the functions given, find a) (f*g)(x) b) (f*g)(2) f(x)=x3, g(x)=x+6 a) (f*g)(x) = ? b) (f*g)(2)= ?

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jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0so, multiply them then

johnanon93
 2 years ago
Best ResponseYou've already chosen the best response.1so here, you literally just plug in those functions wherever you see f(x) and g(x) example (f*g)(x) you have an f(x), and you have a g(x)...plug them in (x  3) * (x + 6) can you do this?

johnanon93
 2 years ago
Best ResponseYou've already chosen the best response.1correct...that would be your a) now for b) you have (f*g)(2) ....notice how the (2) is where the (x) was before....so what do you think you do with that 2?

ikoreanx3
 2 years ago
Best ResponseYou've already chosen the best response.0so it is written (x3)*(x+6)(2)?

johnanon93
 2 years ago
Best ResponseYou've already chosen the best response.1no not quite...where you see that (2) is exactly where you saw the (x) ....did you write the other one as (x3)*(x+6)(x)? no because that wouldn't have worked. instead you used that (x) and you plugged it in for every x you saw in the equation a.k.a (x  3)*(x + 6) **same right? so now....you would plug (2) in for EVERY "x" you see in the equation you derived from finding (f*g)(x) remember how you had gotten x² + 3x  18 now...you would plug 2 into that equation wherever you see an "x"

ikoreanx3
 2 years ago
Best ResponseYou've already chosen the best response.0So then... it would be (2)^2+3(2)18 =
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