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johnanon93 Group TitleBest ResponseYou've already chosen the best response.0
what's another way of writing square root 2x? *hint...think of exponents*
 one year ago

johnanon93 Group TitleBest ResponseYou've already chosen the best response.0
Right....now, use the power rule to find the derivative...
 one year ago

lawls Group TitleBest ResponseYou've already chosen the best response.0
do you get 1/square root (x)
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
dw:1368922493050:dw
 one year ago

lawls Group TitleBest ResponseYou've already chosen the best response.0
yeah i got that and then do you get my answer
 one year ago

lawls Group TitleBest ResponseYou've already chosen the best response.0
after simplifying?
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Is the question (i) \(\int \sqrt{2x} dx\) or (ii) \(\int 2\sqrt{x}dx\) ?
 one year ago

lukethibodeau Group TitleBest ResponseYou've already chosen the best response.0
dw:1369180489303:dw
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ d }{dx }\sqrt{2x}=\sqrt{2}\frac{ d }{dx }\sqrt{x}=\sqrt{2}\frac{ d }{dx }x ^{\frac{ 1 }{2 }}\] \[=\sqrt{2}\frac{ 1 }{ 2 }x ^{^{\frac{ 1 }{ 2 }1}}\] \[=\frac{ 1 }{\sqrt{2} }x ^{\frac{ 1 }{2 }}\]
 one year ago
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