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burhan101

  • 2 years ago

Determine f(x) for this derivative

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  1. burhan101
    • 2 years ago
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    \[\large f'(x)=(-12x^2+8)(2x^2-4x)+(-4x^3+8x)(4x-4)\]

  2. jishan
    • 2 years ago
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    bro just intigrate

  3. Luigi0210
    • 2 years ago
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    Wait are you finding the anti derivative..?

  4. burhan101
    • 2 years ago
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    @Luigi0210 yes :S & @jishan i am not allowed to integrate

  5. DDCamp
    • 2 years ago
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    First, simplify. Then you should just be able to use the power rule for anti-derivatives.

  6. galacticwavesXX
    • 2 years ago
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    then how do you find the original function if you can't integrate

  7. Jhannybean
    • 2 years ago
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    @DDCamp can you elaborate? :D Sprinkle on us your wisdom!

  8. burhan101
    • 2 years ago
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    hmm, still confused

  9. jishan
    • 2 years ago
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    |dw:1368925422997:dw|

  10. Jhannybean
    • 2 years ago
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    oh dear lord your writing...

  11. Luigi0210
    • 2 years ago
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    Distrubute and then combine like terms

  12. galacticwavesXX
    • 2 years ago
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    simplify the function given then integrate to get f(x)

  13. Jhannybean
    • 2 years ago
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    But he says he's not allowed to integrate? That's what's confusing me. how to you find F(x) without integrating?

  14. galacticwavesXX
    • 2 years ago
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    lol idk anymore

  15. Jhannybean
    • 2 years ago
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    My mind r gone.

  16. jishan
    • 2 years ago
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    |dw:1368925643123:dw|

  17. jishan
    • 2 years ago
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    burhan

  18. bahrom7893
    • 2 years ago
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    Is there a party going on here?

  19. .Sam.
    • 2 years ago
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    Yes

  20. jishan
    • 2 years ago
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    thanks bahrom

  21. Jhannybean
    • 2 years ago
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    Haha. I'd be able to understand how to solve this problem if only i could make out jishan's writing =_=

  22. galacticwavesXX
    • 2 years ago
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    i think he simplified the problem but its soo unclear and he also integrated

  23. jishan
    • 2 years ago
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    burhan u understand brother

  24. Jhannybean
    • 2 years ago
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    I see his integral sign but i cant make out the numbers :(

  25. .Sam.
    • 2 years ago
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    \[\large f(x)=\int\limits\limits (-12x^2+8)(2x^2-4x)+(-4x^3+8x)(4x-4) dx\] \[=\int\limits\limits (4 x-4) \left(8 x-4 x^3\right) \, dx+\int\limits\limits \left(8-12 x^2\right) \left(2 x^2-4 x\right) \, dx\] Expand and integrate using power rule for each term \[\int\limits x^ndx=\frac{x^{n+1}}{n+1}+c\] \[f(x)=\left(-8 x^5+16 x^4+16 x^3-32 x^2\right)+c\]

  26. Jhannybean
    • 2 years ago
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    Oh I see. Thank you.

  27. galacticwavesXX
    • 2 years ago
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    now @.Sam. has shed light on what was unseen but i think @burhan101 misinterpreted the question

  28. love_jessika15
    • 2 years ago
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    http://www.youtube.com/watch?v=QHaVc5i-Dzs

  29. love_jessika15
    • 2 years ago
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    |dw:1368926205410:dw|

  30. .Sam.
    • 2 years ago
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    I don't think you can find f(x) without integrating @galacticwavesXX

  31. galacticwavesXX
    • 2 years ago
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    that's what i was thinking

  32. Jemurray3
    • 2 years ago
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    You don't need to go through anything elaborate, just look at it. It's fairly clearly a product-rule derivative, so just take the second part of the first term times the first part of the second term. You can add in a constant for good measure.

  33. Jemurray3
    • 2 years ago
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    If you assume f(x) = g(x) * h(x), then f'(x) = g'(x)h(x) + g(x)h'(x). You can just look at the problem and go from there.

  34. burhan101
    • 2 years ago
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    I am not allowed to integrate whatsoever for this question !!

  35. Jemurray3
    • 2 years ago
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    I'm not talking about any integrating. Look at what I wrote, then look at the question. You can clearly see what h is, and what g is, so you know what f is.

  36. RolyPoly
    • 2 years ago
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    "... are you finding the anti derivative..?" "yes :S" I suppose finding anti-derivative is the same as integrating. If you don't like the integral sign, then you may take the limit of a sum: \[\lim_{x\rightarrow \infty}\sum_{k=1}^{n} y(x_k)\Delta x\], which is the same as integrating the function. For your reference: http://www3.ul.ie/~mlc/support/Loughborough%20website/chap15/15_1.pdf

  37. mathstudent55
    • 2 years ago
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    |dw:1368942664902:dw|

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