## anonymous 3 years ago what is the derivative of 7arcsin(10x^2+15x-9)

1. anonymous

differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2)

2. anonymous

Let $y=7sin^{-1}(10x^2+15x-9)$ $\frac{y}{7}=sin^{-1}(10x^2+15x-9)$$sin(\frac{y}{7})=(10x^2+15x-9)$Differentiate both sides with respect to x.

3. anonymous

@_@ i don't see any of those answers as a choice.

4. zepdrix

lol he didn't give you the answer, he was giving you a way to solve the problem -_-

5. zepdrix

To start, do you know this derivative?$\large y=\arcsin x \qquad \qquad y'=?$

6. anonymous

differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2) i did this

7. anonymous

i know it's something like 1/sqrt(1-u)^2

8. anonymous

|dw:1368923334862:dw|

9. anonymous

that's what I was saying

10. zepdrix

Yes that sounds right bee, $\large y=\arcsin x \qquad \qquad y'=\frac{1}{\sqrt{1-x^2}}$

11. anonymous

12. anonymous

I did the thing he told me and none of those answers matched @_@

13. anonymous

@klllerbee look at my first post...............

14. anonymous

I looked at your post, 7/sqrt(1-(stuff inside arcsin)^2) But the only one I see is 7/1+(10x^2+15x-9)^2 since it's a plus there i know i'm doing something wrong

15. anonymous

I said sqrt.....meaning square root

16. anonymous

sqrt(1-(stuff inside arcsin)^2)

17. anonymous

$7/\sqrt(1-(10x^2+15x-9))^2$

18. anonymous

ok, cool. Thanks guys

19. anonymous

How do i give you metals for helping :D i'm new here

20. anonymous

no, that's not the final answer.......

21. anonymous

still got to multiply it by the derivative

22. anonymous

oh so the final answer is 7x(20x+15)/sqrt(1-(10x^2+15x-9)^2

23. anonymous

yeah.....ze medal?

24. anonymous

where is the metal button?

25. anonymous

:( i don't know what i'm doing with this software