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what is the derivative of 7arcsin(10x^2+15x-9)

Calculus1
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differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2)
Let \[y=7sin^{-1}(10x^2+15x-9)\] \[\frac{y}{7}=sin^{-1}(10x^2+15x-9)\]\[sin(\frac{y}{7})=(10x^2+15x-9)\]Differentiate both sides with respect to x.
@_@ i don't see any of those answers as a choice.

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Other answers:

lol he didn't give you the answer, he was giving you a way to solve the problem -_-
To start, do you know this derivative?\[\large y=\arcsin x \qquad \qquad y'=?\]
differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2) i did this
i know it's something like 1/sqrt(1-u)^2
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that's what I was saying
Yes that sounds right bee, \[\large y=\arcsin x \qquad \qquad y'=\frac{1}{\sqrt{1-x^2}}\]
I did the thing he told me and none of those answers matched @_@
@klllerbee look at my first post...............
I looked at your post, 7/sqrt(1-(stuff inside arcsin)^2) But the only one I see is 7/1+(10x^2+15x-9)^2 since it's a plus there i know i'm doing something wrong
I said sqrt.....meaning square root
sqrt(1-(stuff inside arcsin)^2)
\[7/\sqrt(1-(10x^2+15x-9))^2\]
ok, cool. Thanks guys
How do i give you metals for helping :D i'm new here
no, that's not the final answer.......
still got to multiply it by the derivative
oh so the final answer is 7x(20x+15)/sqrt(1-(10x^2+15x-9)^2
yeah.....ze medal?
where is the metal button?
:( i don't know what i'm doing with this software

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