Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

primeralph Group TitleBest ResponseYou've already chosen the best response.1
differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1(stuff inside arcsin)^2)
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Let \[y=7sin^{1}(10x^2+15x9)\] \[\frac{y}{7}=sin^{1}(10x^2+15x9)\]\[sin(\frac{y}{7})=(10x^2+15x9)\]Differentiate both sides with respect to x.
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
@_@ i don't see any of those answers as a choice.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
lol he didn't give you the answer, he was giving you a way to solve the problem _
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
To start, do you know this derivative?\[\large y=\arcsin x \qquad \qquad y'=?\]
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1(stuff inside arcsin)^2) i did this
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
i know it's something like 1/sqrt(1u)^2
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
dw:1368923334862:dw
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
that's what I was saying
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Yes that sounds right bee, \[\large y=\arcsin x \qquad \qquad y'=\frac{1}{\sqrt{1x^2}}\]
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
I did the thing he told me and none of those answers matched @_@
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
@klllerbee look at my first post...............
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
I looked at your post, 7/sqrt(1(stuff inside arcsin)^2) But the only one I see is 7/1+(10x^2+15x9)^2 since it's a plus there i know i'm doing something wrong
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
I said sqrt.....meaning square root
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
sqrt(1(stuff inside arcsin)^2)
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
\[7/\sqrt(1(10x^2+15x9))^2\]
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
ok, cool. Thanks guys
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
How do i give you metals for helping :D i'm new here
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
no, that's not the final answer.......
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
still got to multiply it by the derivative
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
oh so the final answer is 7x(20x+15)/sqrt(1(10x^2+15x9)^2
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
yeah.....ze medal?
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
where is the metal button?
 one year ago

klllerbee Group TitleBest ResponseYou've already chosen the best response.0
:( i don't know what i'm doing with this software
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.