klllerbee
what is the derivative of 7arcsin(10x^2+15x-9)
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primeralph
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differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2)
RolyPoly
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Let \[y=7sin^{-1}(10x^2+15x-9)\]
\[\frac{y}{7}=sin^{-1}(10x^2+15x-9)\]\[sin(\frac{y}{7})=(10x^2+15x-9)\]Differentiate both sides with respect to x.
klllerbee
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@_@ i don't see any of those answers as a choice.
zepdrix
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lol he didn't give you the answer, he was giving you a way to solve the problem -_-
zepdrix
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To start, do you know this derivative?\[\large y=\arcsin x \qquad \qquad y'=?\]
klllerbee
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differentiate the stuff inside the arcsin, then multiply that by 7/sqrt(1-(stuff inside arcsin)^2) i did this
klllerbee
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i know it's something like
1/sqrt(1-u)^2
primeralph
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|dw:1368923334862:dw|
primeralph
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that's what I was saying
zepdrix
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Yes that sounds right bee, \[\large y=\arcsin x \qquad \qquad y'=\frac{1}{\sqrt{1-x^2}}\]
klllerbee
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klllerbee
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I did the thing he told me and none of those answers matched
@_@
primeralph
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@klllerbee look at my first post...............
klllerbee
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I looked at your post, 7/sqrt(1-(stuff inside arcsin)^2) But the only one I see is 7/1+(10x^2+15x-9)^2 since it's a plus there i know i'm doing something wrong
primeralph
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I said sqrt.....meaning square root
primeralph
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sqrt(1-(stuff inside arcsin)^2)
klllerbee
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\[7/\sqrt(1-(10x^2+15x-9))^2\]
klllerbee
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ok, cool. Thanks guys
klllerbee
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How do i give you metals for helping :D
i'm new here
primeralph
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no, that's not the final answer.......
primeralph
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still got to multiply it by the derivative
klllerbee
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oh
so the final answer is 7x(20x+15)/sqrt(1-(10x^2+15x-9)^2
primeralph
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yeah.....ze medal?
klllerbee
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where is the metal button?
klllerbee
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:( i don't know what i'm doing with this software