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RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
What is Rr and what is \(\Delta\) here represents??
 one year ago

RangO!! Group TitleBest ResponseYou've already chosen the best response.0
radius and delta
 one year ago

RangO!! Group TitleBest ResponseYou've already chosen the best response.0
Δ is the sign of delta !
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Do you have a diagram for this question?
 one year ago

RangO!! Group TitleBest ResponseYou've already chosen the best response.0
the question written above is the exact question from the book :) The whole question is this : Prove for any Δ ABC : Δ=4.Rr cos a/2.cos b/2. cos y/2, where all the symbols have thier usual meaning.
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
I understand that a, b are the angles, but not y, and delta. Δ in ΔABC means triangle Δ itself have the meaning of change, or discriminant. But I don't know the meaning of delta in this case, i.e. Δ = 4 r cos....
 one year ago

RangO!! Group TitleBest ResponseYou've already chosen the best response.0
a, b , c are the sides _
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
No c in your question...
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
But I guess I'd better go, since I don't know how to solve your problem. I'm sorry!!
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
What is the radius of a triangle?
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
I mean radius is for circle right?
 one year ago

genius12 Group TitleBest ResponseYou've already chosen the best response.0
Can you type that out in latex/equation editor?
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.0
There is a lot of ambiguity with the symbols used here, but I'll try to interpret what I understand to be the question? \( \displaystyle \triangle = 4 R r \cos \frac{\alpha}{2} \cos \frac{\beta}{2} \cos \frac{\gamma}{2}\) Triangle, which I assume is area of the triangle ABC, is equal to 4 times R (the circumradius) times r (the inradius) times the cosine of each angle (where the y is an attempted translation of gamma. I've never seen this identity so I don't know for sure if it is correct, but I'll try to research it more.
 one year ago
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