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RangO!!
 one year ago
Prove that: Δ=4.Rr cos a/2.cos b/2. cos y/2
RangO!!
 one year ago
Prove that: Δ=4.Rr cos a/2.cos b/2. cos y/2

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RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0What is Rr and what is \(\Delta\) here represents??

RangO!!
 one year ago
Best ResponseYou've already chosen the best response.0Δ is the sign of delta !

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a diagram for this question?

RangO!!
 one year ago
Best ResponseYou've already chosen the best response.0the question written above is the exact question from the book :) The whole question is this : Prove for any Δ ABC : Δ=4.Rr cos a/2.cos b/2. cos y/2, where all the symbols have thier usual meaning.

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0I understand that a, b are the angles, but not y, and delta. Δ in ΔABC means triangle Δ itself have the meaning of change, or discriminant. But I don't know the meaning of delta in this case, i.e. Δ = 4 r cos....

RangO!!
 one year ago
Best ResponseYou've already chosen the best response.0a, b , c are the sides _

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0No c in your question...

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0But I guess I'd better go, since I don't know how to solve your problem. I'm sorry!!

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0What is the radius of a triangle?

RolyPoly
 one year ago
Best ResponseYou've already chosen the best response.0I mean radius is for circle right?

genius12
 one year ago
Best ResponseYou've already chosen the best response.0Can you type that out in latex/equation editor?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.0There is a lot of ambiguity with the symbols used here, but I'll try to interpret what I understand to be the question? \( \displaystyle \triangle = 4 R r \cos \frac{\alpha}{2} \cos \frac{\beta}{2} \cos \frac{\gamma}{2}\) Triangle, which I assume is area of the triangle ABC, is equal to 4 times R (the circumradius) times r (the inradius) times the cosine of each angle (where the y is an attempted translation of gamma. I've never seen this identity so I don't know for sure if it is correct, but I'll try to research it more.
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