A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Prove that: Δ=4.Rr cos a/2.cos b/2. cos y/2
anonymous
 3 years ago
Prove that: Δ=4.Rr cos a/2.cos b/2. cos y/2

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is Rr and what is \(\Delta\) here represents??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Δ is the sign of delta !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you have a diagram for this question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the question written above is the exact question from the book :) The whole question is this : Prove for any Δ ABC : Δ=4.Rr cos a/2.cos b/2. cos y/2, where all the symbols have thier usual meaning.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I understand that a, b are the angles, but not y, and delta. Δ in ΔABC means triangle Δ itself have the meaning of change, or discriminant. But I don't know the meaning of delta in this case, i.e. Δ = 4 r cos....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a, b , c are the sides _

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No c in your question...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But I guess I'd better go, since I don't know how to solve your problem. I'm sorry!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the radius of a triangle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I mean radius is for circle right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you type that out in latex/equation editor?

AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.0There is a lot of ambiguity with the symbols used here, but I'll try to interpret what I understand to be the question? \( \displaystyle \triangle = 4 R r \cos \frac{\alpha}{2} \cos \frac{\beta}{2} \cos \frac{\gamma}{2}\) Triangle, which I assume is area of the triangle ABC, is equal to 4 times R (the circumradius) times r (the inradius) times the cosine of each angle (where the y is an attempted translation of gamma. I've never seen this identity so I don't know for sure if it is correct, but I'll try to research it more.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.