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trumpetmaster7777

  • 2 years ago

Given the sequence –3, 0, 3, which of the following is equivalent to:

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  1. trumpetmaster7777
    • 2 years ago
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    \[\sum_{n=5}^{8}A -subscript- N\]

  2. trumpetmaster7777
    • 2 years ago
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    54 102 144 162

  3. trumpetmaster7777
    • 2 years ago
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    @primeralph @terenzreignz

  4. trumpetmaster7777
    • 2 years ago
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    @Zarkon

  5. RolyPoly
    • 2 years ago
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    First term is -3, common difference is 0-(-3) = 3 So, the sequence is \[a_n = -3+3(n-1)\]

  6. trumpetmaster7777
    • 2 years ago
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    so, we can do that plugging n-2, n-3 etc. into the next equations?

  7. trumpetmaster7777
    • 2 years ago
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    [-3+3(n-1)]+[-3+3(n-2)] etc.?

  8. RolyPoly
    • 2 years ago
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    You need to find sum from the fifth term to the eighth term, so, find a5, a6, a7, a8 and add them together.

  9. RolyPoly
    • 2 years ago
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    n is the number of term

  10. trumpetmaster7777
    • 2 years ago
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    that's right we start on 5 right? so like this?

  11. RolyPoly
    • 2 years ago
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    e.g. \[a_5 = -3+3(5-1)=...\]

  12. RolyPoly
    • 2 years ago
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    Start from 5, yes.

  13. trumpetmaster7777
    • 2 years ago
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    [-3+3(n-5)]+[-3+3(n-6)]+[-3+3(n-7)]+[-3+3(n-8)]?

  14. trumpetmaster7777
    • 2 years ago
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    (-3+3n-15)+(-3+3n-18)+ (-3+3n-21)+ (-3+3n-24)?

  15. trumpetmaster7777
    • 2 years ago
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    am I doing this right?

  16. trumpetmaster7777
    • 2 years ago
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    (3n-18)+(3n-21)+(3n-24)+(3n-x)+(3n-27)

  17. trumpetmaster7777
    • 2 years ago
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    i'm not sure what to do from there

  18. RolyPoly
    • 2 years ago
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    No

  19. RolyPoly
    • 2 years ago
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    \[a_5 = -3+3(5-1)\]\[a_6 = -3+3(6-1)\]\[a_7 = -3+3(7-1)\]... Then, find \(a_5+a_6+a_7+a_8\)

  20. trumpetmaster7777
    • 2 years ago
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    =−3+3(5−1) =−3+3(6−1) =−3+3(7−1) =-3+3(8-1)

  21. trumpetmaster7777
    • 2 years ago
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    =-6+15 =-6+18 =-6+21 =-6+24 =9 =12 =15 =18 9+12+15+18

  22. trumpetmaster7777
    • 2 years ago
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    54

  23. trumpetmaster7777
    • 2 years ago
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    thank you so much guys

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