anonymous
  • anonymous
The base of a cone has a radius of 6 cm. The slant height of the cone is 15 cm. What is the height of the cone?
Geometry
schrodinger
  • schrodinger
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anonymous
  • anonymous
@jim_thompson5910
GoldPhenoix
  • GoldPhenoix
You have to use the pythagorean theorem.
anonymous
  • anonymous
225=36+x so189 13.75?

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anonymous
  • anonymous
l=|dw:1368934202007:dw|
GoldPhenoix
  • GoldPhenoix
Or you can use the formula that jishan gave you.
anonymous
  • anonymous
is my answer right
anonymous
  • anonymous
yeah bro
anonymous
  • anonymous
h= height of cone r= radius & l=slant height
anonymous
  • anonymous
thank you
anonymous
  • anonymous
always welcome bros.
jim_thompson5910
  • jim_thompson5910
Let r = radius s = slant height h = height \[\large r^2 + h^2 = s^2\] \[\large 6^2 + h^2 = 15^2\] \[\large 36 + h^2 = 225\] \[\large h^2 = 225-36\] \[\large h^2 = 189\] \[\large h = \sqrt{189}\] \[\large h = \sqrt{9*21}\] \[\large h = \sqrt{9}*\sqrt{21}\] \[\large h = 3\sqrt{21}\] \[\large h \approx 13.747727\] \[\large h \approx 13.75\]
geerky42
  • geerky42
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jim_thompson5910
  • jim_thompson5910
you're very helpful and mature...

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