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adillie

  • 2 years ago

The base of a cone has a radius of 6 cm. The slant height of the cone is 15 cm. What is the height of the cone?

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  1. adillie
    • 2 years ago
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    @jim_thompson5910

  2. GoldPhenoix
    • 2 years ago
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    You have to use the pythagorean theorem.

  3. adillie
    • 2 years ago
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    225=36+x so189 13.75?

  4. jishan
    • 2 years ago
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    l=|dw:1368934202007:dw|

  5. GoldPhenoix
    • 2 years ago
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    Or you can use the formula that jishan gave you.

  6. adillie
    • 2 years ago
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    is my answer right

  7. jishan
    • 2 years ago
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    yeah bro

  8. jishan
    • 2 years ago
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    h= height of cone r= radius & l=slant height

  9. adillie
    • 2 years ago
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    thank you

  10. jishan
    • 2 years ago
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    always welcome bros.

  11. jim_thompson5910
    • 2 years ago
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    Let r = radius s = slant height h = height \[\large r^2 + h^2 = s^2\] \[\large 6^2 + h^2 = 15^2\] \[\large 36 + h^2 = 225\] \[\large h^2 = 225-36\] \[\large h^2 = 189\] \[\large h = \sqrt{189}\] \[\large h = \sqrt{9*21}\] \[\large h = \sqrt{9}*\sqrt{21}\] \[\large h = 3\sqrt{21}\] \[\large h \approx 13.747727\] \[\large h \approx 13.75\]

  12. geerky42
    • 2 years ago
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  13. jim_thompson5910
    • 2 years ago
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    you're very helpful and mature...

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