anonymous
  • anonymous
(sinA+cosAtanB)/(cosA-sinAtanB)=tan(a+b)
Mathematics
jamiebookeater
  • jamiebookeater
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AravindG
  • AravindG
Multiply with cos B on numerator and denominator.
anonymous
  • anonymous
explain?
AravindG
  • AravindG
you will se that you get something similar to previous question

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AravindG
  • AravindG
(sinA+cosAtanB) X cos B ________________________ (cosA-sinAtanB) X cos B
AravindG
  • AravindG
Try opening up the brackets .
anonymous
  • anonymous
ok, so you get this: \[(sinAcosB+cosAcosBtanB)/(cosAcosB-sinAcosBtanB)\] so what next?
AravindG
  • AravindG
tan B X cos B = ?
anonymous
  • anonymous
?
AravindG
  • AravindG
\[\tan B \times \cos B= .....\] Can you find that ?
AravindG
  • AravindG
@hothand621 ?
anonymous
  • anonymous
ummmm no, i suck at harder trig
anonymous
  • anonymous
Hint: tan B = sinB / cosB
AravindG
  • AravindG
^^
anonymous
  • anonymous
yes and that doesnt equal tan(a+b)
anonymous
  • anonymous
it equals sinB
anonymous
  • anonymous
Simplify it first :) No need to be hurry :)
AravindG
  • AravindG
yep replace it in your question
anonymous
  • anonymous
replace what though
AravindG
  • AravindG
(sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !
AravindG
  • AravindG
Seen that somewhere?
anonymous
  • anonymous
yes
AravindG
  • AravindG
Can you do it now ?
anonymous
  • anonymous
ummm give me a minute
anonymous
  • anonymous
i think so
anonymous
  • anonymous
what happens to the denominator?
AravindG
  • AravindG
Open up the brackets !
AravindG
  • AravindG
(cosA-sinAtanB) X cos B=.........
anonymous
  • anonymous
thanks man, solved :)
AravindG
  • AravindG
Great ! yw :)

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