hothand621
(sinA+cosAtanB)/(cosAsinAtanB)=tan(a+b)



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AravindG
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Multiply with cos B on numerator and denominator.

hothand621
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explain?

AravindG
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you will se that you get something similar to previous question

AravindG
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(sinA+cosAtanB) X cos B
________________________
(cosAsinAtanB) X cos B

AravindG
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Try opening up the brackets .

hothand621
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ok, so you get this:
\[(sinAcosB+cosAcosBtanB)/(cosAcosBsinAcosBtanB)\]
so what next?

AravindG
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tan B X cos B = ?

hothand621
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?

AravindG
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\[\tan B \times \cos B= .....\]
Can you find that ?

AravindG
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@hothand621 ?

hothand621
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ummmm no, i suck at harder trig

RolyPoly
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Hint: tan B = sinB / cosB

AravindG
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^^

hothand621
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yes
and that doesnt equal tan(a+b)

hothand621
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it equals sinB

RolyPoly
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Simplify it first :)
No need to be hurry :)

AravindG
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yep replace it in your question

hothand621
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replace what though

AravindG
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(sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !

AravindG
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Seen that somewhere?

hothand621
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yes

AravindG
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Can you do it now ?

hothand621
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ummm give me a minute

hothand621
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i think so

hothand621
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what happens to the denominator?

AravindG
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Open up the brackets !

AravindG
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(cosAsinAtanB) X cos B=.........

hothand621
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thanks man, solved :)

AravindG
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Great ! yw :)