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anonymous
 3 years ago
(sinA+cosAtanB)/(cosAsinAtanB)=tan(a+b)
anonymous
 3 years ago
(sinA+cosAtanB)/(cosAsinAtanB)=tan(a+b)

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AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2Multiply with cos B on numerator and denominator.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2you will se that you get something similar to previous question

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2(sinA+cosAtanB) X cos B ________________________ (cosAsinAtanB) X cos B

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2Try opening up the brackets .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, so you get this: \[(sinAcosB+cosAcosBtanB)/(cosAcosBsinAcosBtanB)\] so what next?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2\[\tan B \times \cos B= .....\] Can you find that ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ummmm no, i suck at harder trig

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hint: tan B = sinB / cosB

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes and that doesnt equal tan(a+b)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Simplify it first :) No need to be hurry :)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2yep replace it in your question

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2(sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ummm give me a minute

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what happens to the denominator?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2Open up the brackets !

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2(cosAsinAtanB) X cos B=.........

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks man, solved :)
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