(sinA+cosAtanB)/(cosA-sinAtanB)=tan(a+b)

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(sinA+cosAtanB)/(cosA-sinAtanB)=tan(a+b)

Mathematics
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Multiply with cos B on numerator and denominator.
explain?
you will se that you get something similar to previous question

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Other answers:

(sinA+cosAtanB) X cos B ________________________ (cosA-sinAtanB) X cos B
Try opening up the brackets .
ok, so you get this: \[(sinAcosB+cosAcosBtanB)/(cosAcosB-sinAcosBtanB)\] so what next?
tan B X cos B = ?
?
\[\tan B \times \cos B= .....\] Can you find that ?
ummmm no, i suck at harder trig
Hint: tan B = sinB / cosB
^^
yes and that doesnt equal tan(a+b)
it equals sinB
Simplify it first :) No need to be hurry :)
yep replace it in your question
replace what though
(sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !
Seen that somewhere?
yes
Can you do it now ?
ummm give me a minute
i think so
what happens to the denominator?
Open up the brackets !
(cosA-sinAtanB) X cos B=.........
thanks man, solved :)
Great ! yw :)

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