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hothand621

  • 2 years ago

(sinA+cosAtanB)/(cosA-sinAtanB)=tan(a+b)

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  1. AravindG
    • 2 years ago
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    Multiply with cos B on numerator and denominator.

  2. hothand621
    • 2 years ago
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    explain?

  3. AravindG
    • 2 years ago
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    you will se that you get something similar to previous question

  4. AravindG
    • 2 years ago
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    (sinA+cosAtanB) X cos B ________________________ (cosA-sinAtanB) X cos B

  5. AravindG
    • 2 years ago
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    Try opening up the brackets .

  6. hothand621
    • 2 years ago
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    ok, so you get this: \[(sinAcosB+cosAcosBtanB)/(cosAcosB-sinAcosBtanB)\] so what next?

  7. AravindG
    • 2 years ago
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    tan B X cos B = ?

  8. hothand621
    • 2 years ago
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    ?

  9. AravindG
    • 2 years ago
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    \[\tan B \times \cos B= .....\] Can you find that ?

  10. AravindG
    • 2 years ago
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    @hothand621 ?

  11. hothand621
    • 2 years ago
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    ummmm no, i suck at harder trig

  12. RolyPoly
    • 2 years ago
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    Hint: tan B = sinB / cosB

  13. AravindG
    • 2 years ago
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    ^^

  14. hothand621
    • 2 years ago
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    yes and that doesnt equal tan(a+b)

  15. hothand621
    • 2 years ago
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    it equals sinB

  16. RolyPoly
    • 2 years ago
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    Simplify it first :) No need to be hurry :)

  17. AravindG
    • 2 years ago
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    yep replace it in your question

  18. hothand621
    • 2 years ago
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    replace what though

  19. AravindG
    • 2 years ago
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    (sinA+cosAtanB) X cos B = sin A cos B+cos A sin B !

  20. AravindG
    • 2 years ago
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    Seen that somewhere?

  21. hothand621
    • 2 years ago
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    yes

  22. AravindG
    • 2 years ago
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    Can you do it now ?

  23. hothand621
    • 2 years ago
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    ummm give me a minute

  24. hothand621
    • 2 years ago
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    i think so

  25. hothand621
    • 2 years ago
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    what happens to the denominator?

  26. AravindG
    • 2 years ago
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    Open up the brackets !

  27. AravindG
    • 2 years ago
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    (cosA-sinAtanB) X cos B=.........

  28. hothand621
    • 2 years ago
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    thanks man, solved :)

  29. AravindG
    • 2 years ago
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    Great ! yw :)

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