anonymous
  • anonymous
In triangle ABC, angleA=60 degree, prove that BC2=AB2+AC2+AB.AC
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Can you please double check the question? Is it "-AB.AC" instead of "+AB.AC" ?
RadEn
  • RadEn
use the cosine rule : |dw:1368950431568:dw| cos60 = (AB^2 + AC^2 - BC^2)/2ABAC
RadEn
  • RadEn
1/2 = (AB^2 + AC^2 - BC^2)/2*AB*AC multiplify by 2 to both side, giving us 1 = (AB^2 + AC^2 - BC^2)/AB*AC

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RadEn
  • RadEn
cross product out! AB * AC = AB^2 + AC^2 - BC^2
RadEn
  • RadEn
and actually, Rolypoly is right, that should "-AB.AC" not +AB AC i think there is a bit typo from u, @kumar69

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