anonymous
  • anonymous
a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
hey help please?
yrelhan4
  • yrelhan4
well i just got confused.. give me a minute.
anonymous
  • anonymous
okay the title of lesson is combinations i got no idea how to do it lol

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anonymous
  • anonymous
@ganeshie8
Zarkon
  • Zarkon
are you sampling with or without replacement?
anonymous
  • anonymous
without i think
Zarkon
  • Zarkon
then this is a hypergeometric distribution
anonymous
  • anonymous
a what????? lol explain
Zarkon
  • Zarkon
suppose you have a box with a red and b green balls. you grab k balls the prob you get r red and g green balls (r+g=k) is given by \[\frac{ _aC_r _bC_g}{_{(a+b)}C_k}\]
anonymous
  • anonymous
yeah i dont get it
Zarkon
  • Zarkon
\[\frac{_aC_r\cdot_b C_g}{_{a+b}C_k}\]
Zarkon
  • Zarkon
do you know what \[_nC_r\] is ?
anonymous
  • anonymous
not at all
Zarkon
  • Zarkon
\[{n\choose r}\]?
anonymous
  • anonymous
nope i dont know any of this stuff
Zarkon
  • Zarkon
permutations/combinations?
yrelhan4
  • yrelhan4
i think it would be easier if we dont use combinations, zarkon.. it would be easier if if we do it like this.. for 1 green ball. 4/16.. 1 blue ball after 1 green ball hass been selected.. 7/15. and then multiply them.. whats your view?
anonymous
  • anonymous
i knwo thats what this unit is called combinations
yrelhan4
  • yrelhan4
eh right. so it would be like 4/16*7/15 + 7/16*4/15.. right?
anonymous
  • anonymous
id think s if that was the case
anonymous
  • anonymous
wait but youd get the same thing right 7/60 + 7/60
yrelhan4
  • yrelhan4
yup.
yrelhan4
  • yrelhan4
then for the second part.. 5/16*4/15.. you get why?
anonymous
  • anonymous
which would equal 14/60 right because you dont change the denominator right or would it be 14/120
yrelhan4
  • yrelhan4
yeah.
anonymous
  • anonymous
so it is 14/120
yrelhan4
  • yrelhan4
am i right with the second part @RolyPoly ?
yrelhan4
  • yrelhan4
it should be 14/120..
Zarkon
  • Zarkon
no
yrelhan4
  • yrelhan4
14/60.. lol
Zarkon
  • Zarkon
the answer is 7/30
anonymous
  • anonymous
well idk how to do this thn i am so lost im gonna fail lol
Zarkon
  • Zarkon
or 14/60 if you like
anonymous
  • anonymous
how
Zarkon
  • Zarkon
the solution is written above
anonymous
  • anonymous
okay so will you help by showing work on two three and four maybe if i see it on three ill be able to do it
anonymous
  • anonymous
P(blue first, then green) = P(blue) x P(green after drawing a blue) = 7/16 x 4/(16-1) = a P(green first, then blue) = P(green) x P(blue after drawing a green) = 4/16 x 7/(16-1) = b P(1 blue and 1 green) =P(blue first, then green) + P(green first, then blue) = a + b
anonymous
  • anonymous
now im deffinately confused i just ned a simple explanation
anonymous
  • anonymous
2 red, similar, despite the order of picking a red doesn't matter this time, since you don't the red ones are identical
anonymous
  • anonymous
what omg i need a tutor
anonymous
  • anonymous
Which part are you confused at?
anonymous
  • anonymous
2 BLUE
anonymous
  • anonymous
2 red actually all of it really
anonymous
  • anonymous
u gonna help k?
anonymous
  • anonymous
no thats not the question @phi help please

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