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a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting :
1. 1 green and 1 blue
2. 2 red
3. 1 blue and 1 red
4. 2 blue
 11 months ago
 11 months ago
a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue
 11 months ago
 11 months ago

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yrelhan4Best ResponseYou've already chosen the best response.0
well i just got confused.. give me a minute.
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
okay the title of lesson is combinations i got no idea how to do it lol
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
are you sampling with or without replacement?
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
then this is a hypergeometric distribution
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
a what????? lol explain
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
suppose you have a box with a red and b green balls. you grab k balls the prob you get r red and g green balls (r+g=k) is given by \[\frac{ _aC_r _bC_g}{_{(a+b)}C_k}\]
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
yeah i dont get it
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
\[\frac{_aC_r\cdot_b C_g}{_{a+b}C_k}\]
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
do you know what \[_nC_r\] is ?
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
nope i dont know any of this stuff
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
permutations/combinations?
 11 months ago

yrelhan4Best ResponseYou've already chosen the best response.0
i think it would be easier if we dont use combinations, zarkon.. it would be easier if if we do it like this.. for 1 green ball. 4/16.. 1 blue ball after 1 green ball hass been selected.. 7/15. and then multiply them.. whats your view?
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
i knwo thats what this unit is called combinations
 11 months ago

yrelhan4Best ResponseYou've already chosen the best response.0
eh right. so it would be like 4/16*7/15 + 7/16*4/15.. right?
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
id think s if that was the case
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
wait but youd get the same thing right 7/60 + 7/60
 11 months ago

yrelhan4Best ResponseYou've already chosen the best response.0
then for the second part.. 5/16*4/15.. you get why?
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
which would equal 14/60 right because you dont change the denominator right or would it be 14/120
 11 months ago

yrelhan4Best ResponseYou've already chosen the best response.0
am i right with the second part @RolyPoly ?
 11 months ago

yrelhan4Best ResponseYou've already chosen the best response.0
it should be 14/120..
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
well idk how to do this thn i am so lost im gonna fail lol
 11 months ago

ZarkonBest ResponseYou've already chosen the best response.0
the solution is written above
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
okay so will you help by showing work on two three and four maybe if i see it on three ill be able to do it
 11 months ago

RolyPolyBest ResponseYou've already chosen the best response.2
P(blue first, then green) = P(blue) x P(green after drawing a blue) = 7/16 x 4/(161) = a P(green first, then blue) = P(green) x P(blue after drawing a green) = 4/16 x 7/(161) = b P(1 blue and 1 green) =P(blue first, then green) + P(green first, then blue) = a + b
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
now im deffinately confused i just ned a simple explanation
 11 months ago

RolyPolyBest ResponseYou've already chosen the best response.2
2 red, similar, despite the order of picking a red doesn't matter this time, since you don't the red ones are identical
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
what omg i need a tutor
 11 months ago

RolyPolyBest ResponseYou've already chosen the best response.2
Which part are you confused at?
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
2 red actually all of it really
 11 months ago

kittenbalmBest ResponseYou've already chosen the best response.0
no thats not the question @phi help please
 11 months ago
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