a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue

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a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue

Mathematics
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hey help please?
well i just got confused.. give me a minute.
okay the title of lesson is combinations i got no idea how to do it lol

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Other answers:

are you sampling with or without replacement?
without i think
then this is a hypergeometric distribution
a what????? lol explain
suppose you have a box with a red and b green balls. you grab k balls the prob you get r red and g green balls (r+g=k) is given by \[\frac{ _aC_r _bC_g}{_{(a+b)}C_k}\]
yeah i dont get it
\[\frac{_aC_r\cdot_b C_g}{_{a+b}C_k}\]
do you know what \[_nC_r\] is ?
not at all
\[{n\choose r}\]?
nope i dont know any of this stuff
permutations/combinations?
i think it would be easier if we dont use combinations, zarkon.. it would be easier if if we do it like this.. for 1 green ball. 4/16.. 1 blue ball after 1 green ball hass been selected.. 7/15. and then multiply them.. whats your view?
i knwo thats what this unit is called combinations
eh right. so it would be like 4/16*7/15 + 7/16*4/15.. right?
id think s if that was the case
wait but youd get the same thing right 7/60 + 7/60
yup.
then for the second part.. 5/16*4/15.. you get why?
which would equal 14/60 right because you dont change the denominator right or would it be 14/120
yeah.
so it is 14/120
am i right with the second part @RolyPoly ?
it should be 14/120..
no
14/60.. lol
the answer is 7/30
well idk how to do this thn i am so lost im gonna fail lol
or 14/60 if you like
how
the solution is written above
okay so will you help by showing work on two three and four maybe if i see it on three ill be able to do it
P(blue first, then green) = P(blue) x P(green after drawing a blue) = 7/16 x 4/(16-1) = a P(green first, then blue) = P(green) x P(blue after drawing a green) = 4/16 x 7/(16-1) = b P(1 blue and 1 green) =P(blue first, then green) + P(green first, then blue) = a + b
now im deffinately confused i just ned a simple explanation
2 red, similar, despite the order of picking a red doesn't matter this time, since you don't the red ones are identical
what omg i need a tutor
Which part are you confused at?
2 BLUE
2 red actually all of it really
u gonna help k?
no thats not the question @phi help please

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