Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
kittenbalm
Group Title
a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting :
1. 1 green and 1 blue
2. 2 red
3. 1 blue and 1 red
4. 2 blue
 one year ago
 one year ago
kittenbalm Group Title
a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue
 one year ago
 one year ago

This Question is Closed

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
hey help please?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
well i just got confused.. give me a minute.
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
okay the title of lesson is combinations i got no idea how to do it lol
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
@ganeshie8
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
are you sampling with or without replacement?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
without i think
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
then this is a hypergeometric distribution
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
a what????? lol explain
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
suppose you have a box with a red and b green balls. you grab k balls the prob you get r red and g green balls (r+g=k) is given by \[\frac{ _aC_r _bC_g}{_{(a+b)}C_k}\]
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
yeah i dont get it
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{_aC_r\cdot_b C_g}{_{a+b}C_k}\]
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
do you know what \[_nC_r\] is ?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
not at all
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
\[{n\choose r}\]?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
nope i dont know any of this stuff
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
permutations/combinations?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
i think it would be easier if we dont use combinations, zarkon.. it would be easier if if we do it like this.. for 1 green ball. 4/16.. 1 blue ball after 1 green ball hass been selected.. 7/15. and then multiply them.. whats your view?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
i knwo thats what this unit is called combinations
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
eh right. so it would be like 4/16*7/15 + 7/16*4/15.. right?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
id think s if that was the case
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
wait but youd get the same thing right 7/60 + 7/60
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
then for the second part.. 5/16*4/15.. you get why?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
which would equal 14/60 right because you dont change the denominator right or would it be 14/120
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
so it is 14/120
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
am i right with the second part @RolyPoly ?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
it should be 14/120..
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
14/60.. lol
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
the answer is 7/30
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
well idk how to do this thn i am so lost im gonna fail lol
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
or 14/60 if you like
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.0
the solution is written above
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
okay so will you help by showing work on two three and four maybe if i see it on three ill be able to do it
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.2
P(blue first, then green) = P(blue) x P(green after drawing a blue) = 7/16 x 4/(161) = a P(green first, then blue) = P(green) x P(blue after drawing a green) = 4/16 x 7/(161) = b P(1 blue and 1 green) =P(blue first, then green) + P(green first, then blue) = a + b
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
now im deffinately confused i just ned a simple explanation
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.2
2 red, similar, despite the order of picking a red doesn't matter this time, since you don't the red ones are identical
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
what omg i need a tutor
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.2
Which part are you confused at?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
2 red actually all of it really
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
u gonna help k?
 one year ago

kittenbalm Group TitleBest ResponseYou've already chosen the best response.0
no thats not the question @phi help please
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.