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kittenbalm

a jar contains 4 green marbles, 5 red marbles, and 7 blue marbles. If two balls are selected randomly what is the probability of getting : 1. 1 green and 1 blue 2. 2 red 3. 1 blue and 1 red 4. 2 blue

  • 11 months ago
  • 11 months ago

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  1. kittenbalm
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    hey help please?

    • 11 months ago
  2. yrelhan4
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    well i just got confused.. give me a minute.

    • 11 months ago
  3. kittenbalm
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    okay the title of lesson is combinations i got no idea how to do it lol

    • 11 months ago
  4. kittenbalm
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    @ganeshie8

    • 11 months ago
  5. Zarkon
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    are you sampling with or without replacement?

    • 11 months ago
  6. kittenbalm
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    without i think

    • 11 months ago
  7. Zarkon
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    then this is a hypergeometric distribution

    • 11 months ago
  8. kittenbalm
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    a what????? lol explain

    • 11 months ago
  9. Zarkon
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    suppose you have a box with a red and b green balls. you grab k balls the prob you get r red and g green balls (r+g=k) is given by \[\frac{ _aC_r _bC_g}{_{(a+b)}C_k}\]

    • 11 months ago
  10. kittenbalm
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    yeah i dont get it

    • 11 months ago
  11. Zarkon
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    \[\frac{_aC_r\cdot_b C_g}{_{a+b}C_k}\]

    • 11 months ago
  12. Zarkon
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    do you know what \[_nC_r\] is ?

    • 11 months ago
  13. kittenbalm
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    not at all

    • 11 months ago
  14. Zarkon
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    \[{n\choose r}\]?

    • 11 months ago
  15. kittenbalm
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    nope i dont know any of this stuff

    • 11 months ago
  16. Zarkon
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    permutations/combinations?

    • 11 months ago
  17. yrelhan4
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    i think it would be easier if we dont use combinations, zarkon.. it would be easier if if we do it like this.. for 1 green ball. 4/16.. 1 blue ball after 1 green ball hass been selected.. 7/15. and then multiply them.. whats your view?

    • 11 months ago
  18. kittenbalm
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    i knwo thats what this unit is called combinations

    • 11 months ago
  19. yrelhan4
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    eh right. so it would be like 4/16*7/15 + 7/16*4/15.. right?

    • 11 months ago
  20. kittenbalm
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    id think s if that was the case

    • 11 months ago
  21. kittenbalm
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    wait but youd get the same thing right 7/60 + 7/60

    • 11 months ago
  22. yrelhan4
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    yup.

    • 11 months ago
  23. yrelhan4
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    then for the second part.. 5/16*4/15.. you get why?

    • 11 months ago
  24. kittenbalm
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    which would equal 14/60 right because you dont change the denominator right or would it be 14/120

    • 11 months ago
  25. yrelhan4
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    yeah.

    • 11 months ago
  26. kittenbalm
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    so it is 14/120

    • 11 months ago
  27. yrelhan4
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    am i right with the second part @RolyPoly ?

    • 11 months ago
  28. yrelhan4
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    it should be 14/120..

    • 11 months ago
  29. Zarkon
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    no

    • 11 months ago
  30. yrelhan4
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    14/60.. lol

    • 11 months ago
  31. Zarkon
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    the answer is 7/30

    • 11 months ago
  32. kittenbalm
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    well idk how to do this thn i am so lost im gonna fail lol

    • 11 months ago
  33. Zarkon
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    or 14/60 if you like

    • 11 months ago
  34. kittenbalm
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    how

    • 11 months ago
  35. Zarkon
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    the solution is written above

    • 11 months ago
  36. kittenbalm
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    okay so will you help by showing work on two three and four maybe if i see it on three ill be able to do it

    • 11 months ago
  37. RolyPoly
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    P(blue first, then green) = P(blue) x P(green after drawing a blue) = 7/16 x 4/(16-1) = a P(green first, then blue) = P(green) x P(blue after drawing a green) = 4/16 x 7/(16-1) = b P(1 blue and 1 green) =P(blue first, then green) + P(green first, then blue) = a + b

    • 11 months ago
  38. kittenbalm
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    now im deffinately confused i just ned a simple explanation

    • 11 months ago
  39. RolyPoly
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    2 red, similar, despite the order of picking a red doesn't matter this time, since you don't the red ones are identical

    • 11 months ago
  40. kittenbalm
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    what omg i need a tutor

    • 11 months ago
  41. RolyPoly
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    Which part are you confused at?

    • 11 months ago
  42. kbrece1
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    2 BLUE

    • 11 months ago
  43. kittenbalm
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    2 red actually all of it really

    • 11 months ago
  44. kittenbalm
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    u gonna help k?

    • 11 months ago
  45. kittenbalm
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    no thats not the question @phi help please

    • 11 months ago
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