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 one year ago
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
 one year ago
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

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hba
 one year ago
Best ResponseYou've already chosen the best response.0@brookester6 can help you on this :P

blossomemerald
 one year ago
Best ResponseYou've already chosen the best response.0wow a lot of people on one question lol party

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0well, I did tag a lot of people. I really need help.

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0:( everyone gone.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1I witnessed many people stopped by to help you, why did they go all?

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0they, left, It's too hard of a question

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0@brookester6 said just a second, and then left.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0:( aw man, i just need an equation

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0Let's start from scratch again

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0lol using a website, but I just need an equation, I already have a website to use

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0no, i need to have the numbers put into an equation, I don't know how to do that

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1shoot.what is your equation? for hyperbola?

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1remember that foci (0,+c) and vertices (0,+a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}\frac{x^2}{b^2}=1\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1and draw the asymptotes by \[y= (+)\frac{a}{b}*x\]

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.010^2=8^2+b^2

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1remember that if your foci is (0,+ c) your hyperbola has the shape likedw:1369325453179:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1so b^2 = 100  64 = 36 so ?

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0100=64+b^2 36=b^2 6=b

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{y^2}{64}\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0ok, but how do i find x or y?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1why you have to know x, y?

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0oh wait, that's it

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0I got the graph

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0But, I have online class

trumpetmaster7777
 one year ago
Best ResponseYou've already chosen the best response.0no you say girl at the end of sentence, I CONFUSE

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1i think you are a girl
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