## trumpetmaster7777 2 years ago Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

1. hba

2. brookester6

umm yeah JAS!

3. blossomemerald

wow a lot of people on one question lol party

4. trumpetmaster7777

well, I did tag a lot of people. I really need help.

5. trumpetmaster7777

:( everyone gone.

6. Loser66

I witnessed many people stopped by to help you, why did they go all?

7. trumpetmaster7777

they, left, It's too hard of a question

8. trumpetmaster7777

@brookester6 said just a second, and then left.

9. Loser66

not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

10. trumpetmaster7777

:( aw man, i just need an equation

11. trumpetmaster7777

Let's start from scratch again

12. Loser66

ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

13. trumpetmaster7777

lol using a website, but I just need an equation, I already have a website to use

14. Loser66

so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

15. trumpetmaster7777

no, i need to have the numbers put into an equation, I don't know how to do that

16. Loser66

shoot.what is your equation? for hyperbola?

17. trumpetmaster7777

foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

18. Loser66

remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

19. Loser66

and draw the asymptotes by $y= (+-)\frac{a}{b}*x$

20. Loser66

that's it

21. trumpetmaster7777

10^2=8^2+b^2

22. Loser66

remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|

23. Loser66

so b^2 = 100 - 64 = 36 so ?

24. trumpetmaster7777

100=64+b^2 36=b^2 6=b

25. Loser66

$\frac{y^2}{64}-\frac{x^2}{36}=1$ your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

26. Loser66

got what i mean?

27. trumpetmaster7777

ok, but how do i find x or y?

28. Loser66

why you have to know x, y?

29. trumpetmaster7777

oh wait, that's it

30. Loser66

yeap!!!

31. Loser66

if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

32. trumpetmaster7777

I got the graph

33. trumpetmaster7777
34. trumpetmaster7777

But, I have online class

35. trumpetmaster7777

girl?

36. trumpetmaster7777

no you say girl at the end of sentence, I CONFUSE

37. Loser66

i think you are a girl

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