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Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
 11 months ago
 11 months ago
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
 11 months ago
 11 months ago

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hbaBest ResponseYou've already chosen the best response.0
@brookester6 can help you on this :P
 11 months ago

blossomemeraldBest ResponseYou've already chosen the best response.0
wow a lot of people on one question lol party
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
well, I did tag a lot of people. I really need help.
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
:( everyone gone.
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
I witnessed many people stopped by to help you, why did they go all?
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
they, left, It's too hard of a question
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
@brookester6 said just a second, and then left.
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
:( aw man, i just need an equation
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
Let's start from scratch again
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
lol using a website, but I just need an equation, I already have a website to use
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
no, i need to have the numbers put into an equation, I don't know how to do that
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
shoot.what is your equation? for hyperbola?
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
foci at (0, ±10) and vertices at (0, ±8) Make this into an equation
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
remember that foci (0,+c) and vertices (0,+a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}\frac{x^2}{b^2}=1\]
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
and draw the asymptotes by \[y= (+)\frac{a}{b}*x\]
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
10^2=8^2+b^2
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
remember that if your foci is (0,+ c) your hyperbola has the shape likedw:1369325453179:dw
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
so b^2 = 100  64 = 36 so ?
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
100=64+b^2 36=b^2 6=b
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
\[\frac{y^2}{64}\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
ok, but how do i find x or y?
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
why you have to know x, y?
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
oh wait, that's it
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
I got the graph
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
But, I have online class
 11 months ago

trumpetmaster7777Best ResponseYou've already chosen the best response.0
no you say girl at the end of sentence, I CONFUSE
 11 months ago

Loser66Best ResponseYou've already chosen the best response.1
i think you are a girl
 11 months ago
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