## anonymous 3 years ago Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

1. hba

2. anonymous

umm yeah JAS!

3. anonymous

wow a lot of people on one question lol party

4. anonymous

well, I did tag a lot of people. I really need help.

5. anonymous

:( everyone gone.

6. Loser66

I witnessed many people stopped by to help you, why did they go all?

7. anonymous

they, left, It's too hard of a question

8. anonymous

@brookester6 said just a second, and then left.

9. Loser66

not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

10. anonymous

:( aw man, i just need an equation

11. anonymous

Let's start from scratch again

12. Loser66

ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

13. anonymous

lol using a website, but I just need an equation, I already have a website to use

14. Loser66

so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

15. anonymous

no, i need to have the numbers put into an equation, I don't know how to do that

16. Loser66

shoot.what is your equation? for hyperbola?

17. anonymous

foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

18. Loser66

remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

19. Loser66

and draw the asymptotes by $y= (+-)\frac{a}{b}*x$

20. Loser66

that's it

21. anonymous

10^2=8^2+b^2

22. Loser66

remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|

23. Loser66

so b^2 = 100 - 64 = 36 so ?

24. anonymous

100=64+b^2 36=b^2 6=b

25. Loser66

$\frac{y^2}{64}-\frac{x^2}{36}=1$ your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

26. Loser66

got what i mean?

27. anonymous

ok, but how do i find x or y?

28. Loser66

why you have to know x, y?

29. anonymous

oh wait, that's it

30. Loser66

yeap!!!

31. Loser66

if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

32. anonymous

I got the graph

33. anonymous
34. anonymous

But, I have online class

35. anonymous

girl?

36. anonymous

no you say girl at the end of sentence, I CONFUSE

37. Loser66

i think you are a girl