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anonymous
 3 years ago
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
anonymous
 3 years ago
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

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hba
 3 years ago
Best ResponseYou've already chosen the best response.0@brookester6 can help you on this :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow a lot of people on one question lol party

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, I did tag a lot of people. I really need help.

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1I witnessed many people stopped by to help you, why did they go all?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0they, left, It's too hard of a question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@brookester6 said just a second, and then left.

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:( aw man, i just need an equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let's start from scratch again

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol using a website, but I just need an equation, I already have a website to use

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, i need to have the numbers put into an equation, I don't know how to do that

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1shoot.what is your equation? for hyperbola?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1remember that foci (0,+c) and vertices (0,+a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}\frac{x^2}{b^2}=1\]

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1and draw the asymptotes by \[y= (+)\frac{a}{b}*x\]

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1remember that if your foci is (0,+ c) your hyperbola has the shape likedw:1369325453179:dw

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1so b^2 = 100  64 = 36 so ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0100=64+b^2 36=b^2 6=b

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{y^2}{64}\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, but how do i find x or y?

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1why you have to know x, y?

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.1if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But, I have online class

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no you say girl at the end of sentence, I CONFUSE
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