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Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

Mathematics
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  • hba
@brookester6 can help you on this :P
umm yeah JAS!
wow a lot of people on one question lol party

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Other answers:

well, I did tag a lot of people. I really need help.
:( everyone gone.
I witnessed many people stopped by to help you, why did they go all?
they, left, It's too hard of a question
@brookester6 said just a second, and then left.
not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa
:( aw man, i just need an equation
Let's start from scratch again
ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"
lol using a website, but I just need an equation, I already have a website to use
so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe
no, i need to have the numbers put into an equation, I don't know how to do that
shoot.what is your equation? for hyperbola?
foci at (0, ±10) and vertices at (0, ±8) Make this into an equation
remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}-\frac{x^2}{b^2}=1\]
and draw the asymptotes by \[y= (+-)\frac{a}{b}*x\]
that's it
10^2=8^2+b^2
remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|
so b^2 = 100 - 64 = 36 so ?
100=64+b^2 36=b^2 6=b
\[\frac{y^2}{64}-\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far
got what i mean?
ok, but how do i find x or y?
why you have to know x, y?
oh wait, that's it
yeap!!!
if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.
I got the graph
http://www3.wolframalpha.com/Calculate/MSP/MSP52421f29bdchhib18c60000436031h3b4eaa8g7?MSPStoreType=image/gif&s=37&w=200.&h=204.&cdf=RangeControl
But, I have online class
girl?
no you say girl at the end of sentence, I CONFUSE
i think you are a girl

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