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@brookester6 can help you on this :P

umm yeah JAS!

wow a lot of people on one question lol party

well, I did tag a lot of people. I really need help.

:( everyone gone.

I witnessed many people stopped by to help you, why did they go all?

they, left, It's too hard of a question

@brookester6 said just a second, and then left.

:( aw man, i just need an equation

Let's start from scratch again

lol using a website, but I just need an equation, I already have a website to use

no, i need to have the numbers put into an equation, I don't know how to do that

shoot.what is your equation? for hyperbola?

foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

and draw the asymptotes by
\[y= (+-)\frac{a}{b}*x\]

that's it

10^2=8^2+b^2

remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|

so b^2 = 100 - 64 = 36
so ?

100=64+b^2
36=b^2
6=b

got what i mean?

ok, but how do i find x or y?

why you have to know x, y?

oh wait, that's it

yeap!!!

I got the graph

But, I have online class

girl?

no you say girl at the end of sentence, I CONFUSE

i think you are a girl