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trumpetmaster7777
Group Title
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
 one year ago
 one year ago
trumpetmaster7777 Group Title
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
 one year ago
 one year ago

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hba Group TitleBest ResponseYou've already chosen the best response.0
@brookester6 can help you on this :P
 one year ago

brookester6 Group TitleBest ResponseYou've already chosen the best response.0
umm yeah JAS!
 one year ago

blossomemerald Group TitleBest ResponseYou've already chosen the best response.0
wow a lot of people on one question lol party
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
well, I did tag a lot of people. I really need help.
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
:( everyone gone.
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
I witnessed many people stopped by to help you, why did they go all?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
they, left, It's too hard of a question
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
@brookester6 said just a second, and then left.
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
:( aw man, i just need an equation
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
Let's start from scratch again
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
lol using a website, but I just need an equation, I already have a website to use
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
no, i need to have the numbers put into an equation, I don't know how to do that
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
shoot.what is your equation? for hyperbola?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
foci at (0, ±10) and vertices at (0, ±8) Make this into an equation
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
remember that foci (0,+c) and vertices (0,+a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}\frac{x^2}{b^2}=1\]
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
and draw the asymptotes by \[y= (+)\frac{a}{b}*x\]
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
10^2=8^2+b^2
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
remember that if your foci is (0,+ c) your hyperbola has the shape likedw:1369325453179:dw
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
so b^2 = 100  64 = 36 so ?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
100=64+b^2 36=b^2 6=b
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{y^2}{64}\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
got what i mean?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
ok, but how do i find x or y?
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
why you have to know x, y?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
oh wait, that's it
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
I got the graph
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
But, I have online class
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
girl?
 one year ago

trumpetmaster7777 Group TitleBest ResponseYou've already chosen the best response.0
no you say girl at the end of sentence, I CONFUSE
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
i think you are a girl
 one year ago
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