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trumpetmaster7777

  • one year ago

Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.

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  1. hba
    • one year ago
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    @brookester6 can help you on this :P

  2. brookester6
    • one year ago
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    umm yeah JAS!

  3. blossomemerald
    • one year ago
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    wow a lot of people on one question lol party

  4. trumpetmaster7777
    • one year ago
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    well, I did tag a lot of people. I really need help.

  5. trumpetmaster7777
    • one year ago
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    :( everyone gone.

  6. Loser66
    • one year ago
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    I witnessed many people stopped by to help you, why did they go all?

  7. trumpetmaster7777
    • one year ago
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    they, left, It's too hard of a question

  8. trumpetmaster7777
    • one year ago
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    @brookester6 said just a second, and then left.

  9. Loser66
    • one year ago
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    not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

  10. trumpetmaster7777
    • one year ago
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    :( aw man, i just need an equation

  11. trumpetmaster7777
    • one year ago
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    Let's start from scratch again

  12. Loser66
    • one year ago
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    ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

  13. trumpetmaster7777
    • one year ago
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    lol using a website, but I just need an equation, I already have a website to use

  14. Loser66
    • one year ago
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    so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

  15. trumpetmaster7777
    • one year ago
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    no, i need to have the numbers put into an equation, I don't know how to do that

  16. Loser66
    • one year ago
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    shoot.what is your equation? for hyperbola?

  17. trumpetmaster7777
    • one year ago
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    foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

  18. Loser66
    • one year ago
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    remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola \[\frac{y^2}{a^2}-\frac{x^2}{b^2}=1\]

  19. Loser66
    • one year ago
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    and draw the asymptotes by \[y= (+-)\frac{a}{b}*x\]

  20. Loser66
    • one year ago
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    that's it

  21. trumpetmaster7777
    • one year ago
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    10^2=8^2+b^2

  22. Loser66
    • one year ago
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    remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|

  23. Loser66
    • one year ago
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    so b^2 = 100 - 64 = 36 so ?

  24. trumpetmaster7777
    • one year ago
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    100=64+b^2 36=b^2 6=b

  25. Loser66
    • one year ago
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    \[\frac{y^2}{64}-\frac{x^2}{36}=1\] your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

  26. Loser66
    • one year ago
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    got what i mean?

  27. trumpetmaster7777
    • one year ago
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    ok, but how do i find x or y?

  28. Loser66
    • one year ago
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    why you have to know x, y?

  29. trumpetmaster7777
    • one year ago
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    oh wait, that's it

  30. Loser66
    • one year ago
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    yeap!!!

  31. Loser66
    • one year ago
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    if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

  32. trumpetmaster7777
    • one year ago
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    I got the graph

  33. trumpetmaster7777
    • one year ago
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    But, I have online class

  34. trumpetmaster7777
    • one year ago
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    girl?

  35. trumpetmaster7777
    • one year ago
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    no you say girl at the end of sentence, I CONFUSE

  36. Loser66
    • one year ago
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    i think you are a girl

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