trumpetmaster7777
Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology.
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hba
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@brookester6 can help you on this :P
brookester6
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umm yeah JAS!
blossomemerald
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wow a lot of people on one question lol party
trumpetmaster7777
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well, I did tag a lot of people. I really need help.
trumpetmaster7777
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:( everyone gone.
Loser66
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I witnessed many people stopped by to help you, why did they go all?
trumpetmaster7777
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they, left, It's too hard of a question
trumpetmaster7777
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@brookester6 said just a second, and then left.
Loser66
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not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa
trumpetmaster7777
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:( aw man, i just need an equation
trumpetmaster7777
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Let's start from scratch again
Loser66
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ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"
trumpetmaster7777
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lol using a website, but I just need an equation, I already have a website to use
Loser66
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so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe
trumpetmaster7777
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no, i need to have the numbers put into an equation, I don't know how to do that
Loser66
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shoot.what is your equation? for hyperbola?
trumpetmaster7777
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foci at (0, ±10) and vertices at (0, ±8) Make this into an equation
Loser66
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remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola
\[\frac{y^2}{a^2}-\frac{x^2}{b^2}=1\]
Loser66
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and draw the asymptotes by
\[y= (+-)\frac{a}{b}*x\]
Loser66
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that's it
trumpetmaster7777
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10^2=8^2+b^2
Loser66
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remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|
Loser66
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so b^2 = 100 - 64 = 36
so ?
trumpetmaster7777
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100=64+b^2
36=b^2
6=b
Loser66
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\[\frac{y^2}{64}-\frac{x^2}{36}=1\]
your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far
Loser66
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got what i mean?
trumpetmaster7777
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ok, but how do i find x or y?
Loser66
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why you have to know x, y?
trumpetmaster7777
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oh wait, that's it
Loser66
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yeap!!!
Loser66
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if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.
trumpetmaster7777
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I got the graph
trumpetmaster7777
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But, I have online class
trumpetmaster7777
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no you say girl at the end of sentence, I CONFUSE
Loser66
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i think you are a girl