## trumpetmaster7777 Group Title Graph a hyperbola with foci at (0, ±10) and vertices at (0, ±8) using graphing technology. one year ago one year ago

1. hba Group Title

2. brookester6 Group Title

umm yeah JAS!

3. blossomemerald Group Title

wow a lot of people on one question lol party

4. trumpetmaster7777 Group Title

well, I did tag a lot of people. I really need help.

5. trumpetmaster7777 Group Title

:( everyone gone.

6. Loser66 Group Title

I witnessed many people stopped by to help you, why did they go all?

7. trumpetmaster7777 Group Title

they, left, It's too hard of a question

8. trumpetmaster7777 Group Title

@brookester6 said just a second, and then left.

9. Loser66 Group Title

not that girl!! I think because you called too many people. so, this one thinks that the other's duty. hahahaa

10. trumpetmaster7777 Group Title

:( aw man, i just need an equation

11. trumpetmaster7777 Group Title

Let's start from scratch again

12. Loser66 Group Title

ok, my question is " what does graphing technology?" I always graph by hand, don't know how to use "technology"

13. trumpetmaster7777 Group Title

lol using a website, but I just need an equation, I already have a website to use

14. Loser66 Group Title

so, you can solve it by yourself? no need to stay ? right? actually, I am a super lazy guy. If you don't need help anymore, I glad to hear that. hehehe

15. trumpetmaster7777 Group Title

no, i need to have the numbers put into an equation, I don't know how to do that

16. Loser66 Group Title

shoot.what is your equation? for hyperbola?

17. trumpetmaster7777 Group Title

foci at (0, ±10) and vertices at (0, ±8) Make this into an equation

18. Loser66 Group Title

remember that foci (0,+-c) and vertices (0,+-a) and c^2 = a^2 + b^2( use this form to find out b) and put everything into the standard form of hyperbola $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

19. Loser66 Group Title

and draw the asymptotes by $y= (+-)\frac{a}{b}*x$

20. Loser66 Group Title

that's it

21. trumpetmaster7777 Group Title

10^2=8^2+b^2

22. Loser66 Group Title

remember that if your foci is (0,+- c) your hyperbola has the shape like|dw:1369325453179:dw|

23. Loser66 Group Title

so b^2 = 100 - 64 = 36 so ?

24. trumpetmaster7777 Group Title

100=64+b^2 36=b^2 6=b

25. Loser66 Group Title

$\frac{y^2}{64}-\frac{x^2}{36}=1$ your equation form is a^2 and b^2 , you need a, b when you have to figure out the asymptotes only. to get the form of hyperbola, no need to get that far

26. Loser66 Group Title

got what i mean?

27. trumpetmaster7777 Group Title

ok, but how do i find x or y?

28. Loser66 Group Title

why you have to know x, y?

29. trumpetmaster7777 Group Title

oh wait, that's it

30. Loser66 Group Title

yeap!!!

31. Loser66 Group Title

if you have to sketch the graph, you have to sketch the asymptotes, too. but it's quite easy when you have a, b, just draw the lines out.

32. trumpetmaster7777 Group Title

I got the graph

33. trumpetmaster7777 Group Title
34. trumpetmaster7777 Group Title

But, I have online class

35. trumpetmaster7777 Group Title

girl?

36. trumpetmaster7777 Group Title

no you say girl at the end of sentence, I CONFUSE

37. Loser66 Group Title

i think you are a girl