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What is \(p\)?

I tried to use logarithmic properties to find an answer but it just kept running me in circles

Am I right? O_O

Definitely not the reasoning I'd pick...

Knew it.

correct answer but wrong logic ... think about the opposite e^n/n^p and n->infinity

0

Sorry (1/e^n)

Relax... you can either use L'Hôpital
or one of my favourite theorems~ pick one

Approaching infinity, not really infinity.
I tried to use l'hopital: didn't work. :-|

The almighty Squeeze~

Isnt the answer 0?

ARMAGERD. How could I forget the squeeze

Ok I tried lopitals and it did not work nor did logarithmic properties

What's the inequality BTW?

@DLS the answer is zero

Yes,its easy.

Use LH

@DLS how?

My favouraite technique is \[ a = e^{\log a} \\ n^{p} = e^{p \log n } \]

@experimentX why would that help?

L'hopital works use it least floor(p + 1)

Why deviate from the norm, @experimentX ? :D
Just use ceiling :3

Don't understand what you mean @experimentX

@chrisplusian |dw:1369325101292:dw|

And then squeezing :)

@terenzreignz yes ceil

@chrisplusian my reply should probably clear it off.
@experimentX does it seem right?

the solutions guide says =0 when p>0, and bless than or equal to 2