At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

What is \(p\)?

I tried to use logarithmic properties to find an answer but it just kept running me in circles

Am I right? O_O

Definitely not the reasoning I'd pick...

Knew it.

correct answer but wrong logic ... think about the opposite e^n/n^p and n->infinity

0

Sorry (1/e^n)

Relax... you can either use L'Hôpital
or one of my favourite theorems~ pick one

Approaching infinity, not really infinity.
I tried to use l'hopital: didn't work. :-|

The almighty Squeeze~

Isnt the answer 0?

ARMAGERD. How could I forget the squeeze

Ok I tried lopitals and it did not work nor did logarithmic properties

What's the inequality BTW?

@DLS the answer is zero

Yes,its easy.

Use LH

@DLS how?

My favouraite technique is \[ a = e^{\log a} \\ n^{p} = e^{p \log n } \]

@experimentX why would that help?

L'hopital works use it least floor(p + 1)

Why deviate from the norm, @experimentX ? :D
Just use ceiling :3

Don't understand what you mean @experimentX

@chrisplusian |dw:1369325101292:dw|

And then squeezing :)

@terenzreignz yes ceil

@chrisplusian my reply should probably clear it off.
@experimentX does it seem right?

the solutions guide says =0 when p>0, and bless than or equal to 2