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DLS Group TitleBest ResponseYou've already chosen the best response.2
\[\LARGE \lim_{x \rightarrow 0} \frac{(1+x)^\frac{1}{x} e}{x}\]
 one year ago

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@yrelhan4 @shubhamsrg
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.2
first time in life :O
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Taylor Series expansion?
 one year ago

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Use whatever you want.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
Taylor series works
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Weird. The Taylor Series expansion is in the terms of \(e\) and \(x\). The first term is \(e\)
 one year ago

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Taylor series gives 0?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
gives e/2 if you calculate correctly
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Oh wait! lol, yeah. I forgot to consider that e/2 which had no \(x\)
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.2
How about a different way rather than taylor series?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Definition of derivative? :
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I was just thinking how this might be the definition of a derivative in disguise.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
Binomial expansion might work ... but that's too long
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
DLS Use whatever you want. 15 minutes ago DLS How about a different way rather than taylor series? 9 minutes ago
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.2
You are right,still investigating for more methods,I wrote so to specify that you are not bound to any particular method,just asking if you know anything alternate :)
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
L'hopital works
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=Limit%5B%281+%2B+x%29%5E%281%2Fx%29+%281%2F%28x+%281+%2B+x%29%29++Log%5B1+%2B+x%5D%2Fx%5E2%29%2C+x+%3E+0%5D after using L'hopital you get this expression. The first term tends to e .. if you again apply L'hopital on the second term, you will get 1/2
 one year ago
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