help please !!
if 20% of the balls produced by the machine are defective find the probability that out of the 4 balls selected at random
(i) 2 are defective
(ii) not more than 2 are defective
i have done part (i) i got 0.1536 but i need help with part (ii)

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this might be better suited to a binomial setup

thats what i did for part i and i got that i'm just not sure what to do for the other part

\[P(2~out~of~4)=\binom{4}{2}~(bad)^2~(good)^2\]
\[P(2~out~of~4)=6~(.20)^2~(.80)^2\]

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