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AonZ
Group Title
Help me year 11 trig question
(a) prove(i have done this part already)
cos3a = 4cos^3 a  3cosa
(b) Show that cos40 is a root of the equation 8x^3  6x +1 = 0
I need help with part (b) only
 one year ago
 one year ago
AonZ Group Title
Help me year 11 trig question (a) prove(i have done this part already) cos3a = 4cos^3 a  3cosa (b) Show that cos40 is a root of the equation 8x^3  6x +1 = 0 I need help with part (b) only
 one year ago
 one year ago

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AonZ Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 @ParthKohli help please :)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
well you have part a) already done, so why not replace 'a' with 40 and see what happens cos3a = 4cos^3 a  3cosa cos(3*40) = 4cos^3(40)  3cos(40) cos(120) = 4cos^3(40)  3cos(40) 1/2 = 4cos^3(40)  3cos(40)
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
You could just plug in x=cos40
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
all you need to do is find the cosine of 40 degrees and replace x in the equation. cos40=0.7660
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
Now multiply both sides of the last equation by 2 to get 1/2 = 4cos^3(40)  3cos(40) 2*(1/2) = 2*(4cos^3(40)  3cos(40) ) 1 = 8cos^3(40)  6cos(40) 0 = 8cos^3(40)  6cos(40) + 1 8cos^3(40)  6cos(40) + 1 = 0 so that confirms x = cos(40) is a root of 8x^3  6x +1 = 0
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.0
oh :) thank you so much. didnt have any clue what to do :)
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 nice ... @AonZ we can also find by replacing x with cos40(0.7660) but this is very long method. when you replace x in your equation with the stored value of .7660, the result is 0 indicating that cosine of 40 degrees is a root of the equation. and by this, jim had proven this!!! good job @jim_thompson5910
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
ty
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 way is the best :) cause it uses trig which is the topic i am currently doing :D
 one year ago
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