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Euler271 Group TitleBest ResponseYou've already chosen the best response.0
you can divide both sides by 6x since they have that in common
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
What do you get if you divide both sides by any common factors?
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.0
this is what i got when i did the problem x=0, x=3 @whpalmer4 @Euler271
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
Are you sure about the sign in x=3
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.0
no i ment 3
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
dw:1369421161689:dw
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.0
thank you
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
You are welcome, good luck.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
More more better: \[6x^2  18x = 0\]\[6x(x3) = 0\]\[6x = 0\]\[x3= 0\]
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.0
so the 3 is negitive?
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
No when solving x3=0 you would add 3 to both sides of the equal sign getting: x=3
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
dw:1369421554316:dw
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
dw:1369421678905:dw
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.2
dw:1369421748128:dw
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
One thing that we haven't exactly made clear here: if you did just divide both sides by 6x as suggested at first: \[6x^2 = 18x\]\[x=3\]You might get the impression that your work is done. However, there's an important thing to know, which is if your polynomial has \(x^n\) as its highest power, you must have \(n\) solutions! Some of them may be identical, but you will have that many. That would be a clue here that \(x=3\) isn't the entire story.
 one year ago
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