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allie_bear22

what are the solutions to 6x^2=18x?

  • 11 months ago
  • 11 months ago

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  1. Euler271
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    you can divide both sides by 6x since they have that in common

    • 11 months ago
  2. whpalmer4
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    What do you get if you divide both sides by any common factors?

    • 11 months ago
  3. allie_bear22
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    this is what i got when i did the problem x=0, x=-3 @whpalmer4 @Euler271

    • 11 months ago
  4. radar
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    Are you sure about the sign in x=-3

    • 11 months ago
  5. allie_bear22
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    no i ment 3

    • 11 months ago
  6. radar
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    |dw:1369421161689:dw|

    • 11 months ago
  7. radar
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    More better

    • 11 months ago
  8. allie_bear22
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    thank you

    • 11 months ago
  9. radar
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    You are welcome, good luck.

    • 11 months ago
  10. whpalmer4
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    More more better: \[6x^2 - 18x = 0\]\[6x(x-3) = 0\]\[6x = 0\]\[x-3= 0\]

    • 11 months ago
  11. allie_bear22
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    so the 3 is negitive?

    • 11 months ago
  12. radar
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    No when solving x-3=0 you would add 3 to both sides of the equal sign getting: x=3

    • 11 months ago
  13. radar
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    |dw:1369421554316:dw|

    • 11 months ago
  14. radar
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    |dw:1369421678905:dw|

    • 11 months ago
  15. radar
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    |dw:1369421748128:dw|

    • 11 months ago
  16. whpalmer4
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    One thing that we haven't exactly made clear here: if you did just divide both sides by 6x as suggested at first: \[6x^2 = 18x\]\[x=3\]You might get the impression that your work is done. However, there's an important thing to know, which is if your polynomial has \(x^n\) as its highest power, you must have \(n\) solutions! Some of them may be identical, but you will have that many. That would be a clue here that \(x=3\) isn't the entire story.

    • 11 months ago
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