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allie_bear22

  • one year ago

what are the solutions to 6x^2=18x?

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  1. Euler271
    • one year ago
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    you can divide both sides by 6x since they have that in common

  2. whpalmer4
    • one year ago
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    What do you get if you divide both sides by any common factors?

  3. allie_bear22
    • one year ago
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    this is what i got when i did the problem x=0, x=-3 @whpalmer4 @Euler271

  4. radar
    • one year ago
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    Are you sure about the sign in x=-3

  5. allie_bear22
    • one year ago
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    no i ment 3

  6. radar
    • one year ago
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    |dw:1369421161689:dw|

  7. radar
    • one year ago
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    More better

  8. allie_bear22
    • one year ago
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    thank you

  9. radar
    • one year ago
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    You are welcome, good luck.

  10. whpalmer4
    • one year ago
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    More more better: \[6x^2 - 18x = 0\]\[6x(x-3) = 0\]\[6x = 0\]\[x-3= 0\]

  11. allie_bear22
    • one year ago
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    so the 3 is negitive?

  12. radar
    • one year ago
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    No when solving x-3=0 you would add 3 to both sides of the equal sign getting: x=3

  13. radar
    • one year ago
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    |dw:1369421554316:dw|

  14. radar
    • one year ago
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    |dw:1369421678905:dw|

  15. radar
    • one year ago
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    |dw:1369421748128:dw|

  16. whpalmer4
    • one year ago
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    One thing that we haven't exactly made clear here: if you did just divide both sides by 6x as suggested at first: \[6x^2 = 18x\]\[x=3\]You might get the impression that your work is done. However, there's an important thing to know, which is if your polynomial has \(x^n\) as its highest power, you must have \(n\) solutions! Some of them may be identical, but you will have that many. That would be a clue here that \(x=3\) isn't the entire story.

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