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DEVESHkishore
Dear friends while asking the solution plz put down your question rather saying homework or h8p what ever.. if u give proper question we will try to solve for u
See my response to prateekbansal first question. Gives reason why you should do this and examples
he asked about exercise 1-2 which i am nt able 2 find where is the problem is?
dear kenl.jw i can not see ur response help me with this will try to response to it
I didn't response to problem 1.2 because it wasn't asked appropriately. I gave example of how should ask questions to get answers. Problem 1.2 - How to arrange 4 1K ohm resistors to get 3/5 K, 5/3 K
i will really appreciate if you put the link.. it will help me a lot
Go to MIT OCW, then to electrical engineering, then circuit and electronics
Produced Rule - R1||R2 = R!R2/(R!+R2) I prefer to leave in original form(short hand) until entire circuit is analyzed. Also in the case where R2 has a factor R1 R1||aR1 = R1(1||a) = R1 a/(1+a) This should help in solving problem 1.2
|dw:1369543319826:dw| in F1 parallel resistor value is 1.5 which is in series with 1st resitor and parallel to last one.. solve this u get 3/5 similar concept in F2 solve box resistor then seris with outer resistor hope it will help you..
|dw:1369544408893:dw| F2
I would start out like this 1+1+1+1=4 1||1+1+1=2 1/2 1||1||1 +1=5/3 Not sure how to get 3/5
see you last step and solve again you will get ans as 4/3 which is nt correct
error 1||1||1+1=4/3 2||1+1=5/3
2 parelle 1 gives 2/3 now it is in series with 1 thus 2/3+1=5/3
hope this has helped you..
I didn't ask the question, you should go to the one that asked it. 3/5?
What wye/delta formula are you using to get 3/5
it not star/delta its simple series/parallel method
I discovered the answer! (1+1/2)||1 = (3/2)||1= 3/5 therefore the two answers are 2||1+1=5/3 (3/2)||1=3/5 I really couldn't follow your drawings. I prefer this terminology. Thank You
Anyone who did Hmework 11
can you put ur problem over here...