Here's the question you clicked on:
Micheellexox
Which is the simplified form of
\[\frac{ 18q^2r^4 }{ 3q^3r}= (\frac{ 18 }{ 3 })(\frac{ 1 }{ q ^{3-2} })(r ^{4-1})\]
Try solving it that way. you'll get your simplified answer :)
Well if you just divide it out and know tjhat when your divide exponents...you subtract you have 18q^2r^4 --------- 3 q^3 r 3 goes into 18 6 times q^2 ---- = q^(2-3) = q^-1 q^3 r^4 ---- = r^(4-1) = r^3 r so altogether you have 6 q^-1 r^3 q^-1 gets moved to the bottom (^-1 means 1/that number) so you have 6 r^3 ----- q
... but i explained it so well :( haha
lol you did! just gave her another optional way to look at it :)
Pff. winning over the audience due to my lack in response time!:P
Imsorry! They were both good. I just needed the answer ASAP. On my FINAL exam. <3333 @Jhannybean @johnweldon1993
Hahaha no worries :P Good luck on your final!
And like i said don't stress it you'll do great! :) and me and @Jhannybean will be here to help right Jhannybean! :P ...if you need it :)