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Micheellexox

  • one year ago

Algebra help please??

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  1. Micheellexox
    • one year ago
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  2. johnweldon1993
    • one year ago
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    HA finally got the first one! lol hang on

  3. johnweldon1993
    • one year ago
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    \[\sqrt{16c^4} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4c^2}\] when you break it all down it'll look like \[\sqrt{16}\sqrt{c^2}\sqrt{c^2} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4}\sqrt{c^2}\] so simplifying it more 4(c)(c) - c + 3(c) + 2(c) 4c² -c + 3c + 2c 4x² + 4c :)

  4. johnweldon1993
    • one year ago
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    *edit that last part 4c² + 4c * :)

  5. johnweldon1993
    • one year ago
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    And the explanation for the second one: \[\sqrt{3}(2b \sqrt{49} -b)\] You know the √49 is 7 so \[\sqrt{3}(2b(7) - b)\] \[\sqrt{3}(14b - b)\] so that becomes √3(13b) :)

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