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anonymous
 3 years ago
Algebra help please??
anonymous
 3 years ago
Algebra help please??

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johnweldon1993
 3 years ago
Best ResponseYou've already chosen the best response.1HA finally got the first one! lol hang on

johnweldon1993
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{16c^4}  \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4c^2}\] when you break it all down it'll look like \[\sqrt{16}\sqrt{c^2}\sqrt{c^2}  \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4}\sqrt{c^2}\] so simplifying it more 4(c)(c)  c + 3(c) + 2(c) 4c² c + 3c + 2c 4x² + 4c :)

johnweldon1993
 3 years ago
Best ResponseYou've already chosen the best response.1*edit that last part 4c² + 4c * :)

johnweldon1993
 3 years ago
Best ResponseYou've already chosen the best response.1And the explanation for the second one: \[\sqrt{3}(2b \sqrt{49} b)\] You know the √49 is 7 so \[\sqrt{3}(2b(7)  b)\] \[\sqrt{3}(14b  b)\] so that becomes √3(13b) :)
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