## Micheellexox Group Title Algebra help please?? one year ago one year ago

1. Micheellexox

2. johnweldon1993

HA finally got the first one! lol hang on

3. johnweldon1993

$\sqrt{16c^4} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4c^2}$ when you break it all down it'll look like $\sqrt{16}\sqrt{c^2}\sqrt{c^2} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4}\sqrt{c^2}$ so simplifying it more 4(c)(c) - c + 3(c) + 2(c) 4c² -c + 3c + 2c 4x² + 4c :)

4. johnweldon1993

*edit that last part 4c² + 4c * :)

5. johnweldon1993

And the explanation for the second one: $\sqrt{3}(2b \sqrt{49} -b)$ You know the √49 is 7 so $\sqrt{3}(2b(7) - b)$ $\sqrt{3}(14b - b)$ so that becomes √3(13b) :)