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Christos

  • 2 years ago

Factor this http://screencast.com/t/7oezPour5cV

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  1. ganeshie8
    • 2 years ago
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    you dont knw how to factor

  2. chocobo907
    • 2 years ago
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    2x^2+x-3 factored would be (2x+3)(x-1)

  3. ganeshie8
    • 2 years ago
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    you have the answer there. @Christos something u dont understand in how to factor that ?

  4. Christos
    • 2 years ago
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    @ganeshie8 certainly I don't understand how I should start? Will you guys be willing to show me the first step? Thee are certain expressions that just dont ring a bell on me, it's not that I cant factor, just some specific ones

  5. ganeshie8
    • 2 years ago
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    i understand, let me guide u factor this

  6. Christos
    • 2 years ago
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    ty man

  7. ganeshie8
    • 2 years ago
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    \(2x^2 + x - 3 \)

  8. ganeshie8
    • 2 years ago
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    compare it wid \(ax^2 + bx + c\)

  9. Christos
    • 2 years ago
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    ok

  10. ganeshie8
    • 2 years ago
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    we need to pick two numbers whose product equals \(ac\), and sum equals \(b\)

  11. ganeshie8
    • 2 years ago
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    a=2 b=1 c=-3

  12. ganeshie8
    • 2 years ago
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    can you pick two numbers whose product equals -6, and sum equals 1 ?

  13. surjithayer
    • 2 years ago
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    \[2x ^{2}+x-3=2x ^{2}+3x-2x-3\] (2*-3=-6,3-2=1) \[=x \left( 2x+3 \right)-1\left( 2x+3 \right)=\left( 2x+3 \right)\left( x-1 \right)\]

  14. Christos
    • 2 years ago
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    I dont think I can :(

  15. ganeshie8
    • 2 years ago
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    tell me what are the factors of -6

  16. Christos
    • 2 years ago
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    -1 -2 -3

  17. ganeshie8
    • 2 years ago
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    and 1, 2, 3 also

  18. Christos
    • 2 years ago
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    ooh ok

  19. ganeshie8
    • 2 years ago
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    so, 3 * -2 = -6

  20. ganeshie8
    • 2 years ago
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    3 + -2 = 1

  21. ganeshie8
    • 2 years ago
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    3 and -2 are our numbers !

  22. Christos
    • 2 years ago
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    So we dont take into considaration b ? We just add and multiply a and c?

  23. ganeshie8
    • 2 years ago
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    \(2x^2 + x - 3\) you need to rewrite x as 3x-2x

  24. ganeshie8
    • 2 years ago
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    we did consider b, the numbers we pick must multiply to ac, and addup to b

  25. Christos
    • 2 years ago
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    "3 * -2 = -6" "3 + -2 = 1" Where is b ?

  26. ganeshie8
    • 2 years ago
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    we picked 3 and -2, cuz they multiply to ac, and addup to b

  27. ganeshie8
    • 2 years ago
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    look at the given expression, b = 1

  28. Christos
    • 2 years ago
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    hm the second expression ye

  29. ganeshie8
    • 2 years ago
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    \(2x^2 + x - 3\) can be written as : \(2x^2 + 1x - 3\)

  30. ganeshie8
    • 2 years ago
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    compare it wid ax^2 + bx + c, and tell me whats b ?

  31. Christos
    • 2 years ago
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    yea I know it's 1, I just dont know what do it with it :D

  32. Christos
    • 2 years ago
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    lol

  33. ganeshie8
    • 2 years ago
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    so when you're asking where is b, you knw now that its there, and it is 1 :)

  34. Christos
    • 2 years ago
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    from my understanding we take a*c = whatever it gives then a+c = whatever it gives

  35. ganeshie8
    • 2 years ago
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    not exactly

  36. Christos
    • 2 years ago
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    hm

  37. ganeshie8
    • 2 years ago
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    we take a*c, tell whats a*c, in our current example ?

  38. Christos
    • 2 years ago
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    its -6

  39. ganeshie8
    • 2 years ago
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    so we take that -6, and find its factors. that addup to b

  40. ganeshie8
    • 2 years ago
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    -6 = 3*-2

  41. Christos
    • 2 years ago
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    when you say "add up" what do you mean exactly?

  42. ganeshie8
    • 2 years ago
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    when u add both the numbers, you must get b

  43. ganeshie8
    • 2 years ago
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    we picked 3 and -2, add them and see if u get b or not

  44. ganeshie8
    • 2 years ago
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    if p, q are the two numbers, you should pick them in a way such that :- pq = ac p+q = b

  45. ganeshie8
    • 2 years ago
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    thats all

  46. Christos
    • 2 years ago
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    I see now

  47. ganeshie8
    • 2 years ago
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    great :) you do few more problems u wil see more clearly

  48. Christos
    • 2 years ago
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    Ok so, we have a*c = -6 a-b = 1 but how do I proceed with this information in hand?

  49. ganeshie8
    • 2 years ago
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    heres the full solution, go through \(2x^2 + x - 3\) \(2x^2 + 3x - 2x - 3\) \(x(2x + 3) - 1(2x + 3)\) \((2x + 3)(x - 1)\)

  50. Christos
    • 2 years ago
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    a-c ***

  51. ganeshie8
    • 2 years ago
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    no

  52. Christos
    • 2 years ago
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    /facepalm I am such a dummy some times, I can see it clearly now, thanks again

  53. ganeshie8
    • 2 years ago
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    its, pq = ac p+q = b

  54. ganeshie8
    • 2 years ago
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    cool all geniuses have few dummy corners ;p

  55. Christos
    • 2 years ago
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    yea yea I see, I get you now

  56. Christos
    • 2 years ago
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    hihi xP

  57. ganeshie8
    • 2 years ago
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    good :)

  58. Christos
    • 2 years ago
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    ty dude

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