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Christos

Factor this http://screencast.com/t/7oezPour5cV

  • 10 months ago
  • 10 months ago

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  1. ganeshie8
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    you dont knw how to factor

    • 10 months ago
  2. chocobo907
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    2x^2+x-3 factored would be (2x+3)(x-1)

    • 10 months ago
  3. ganeshie8
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    you have the answer there. @Christos something u dont understand in how to factor that ?

    • 10 months ago
  4. Christos
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    @ganeshie8 certainly I don't understand how I should start? Will you guys be willing to show me the first step? Thee are certain expressions that just dont ring a bell on me, it's not that I cant factor, just some specific ones

    • 10 months ago
  5. ganeshie8
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    i understand, let me guide u factor this

    • 10 months ago
  6. Christos
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    ty man

    • 10 months ago
  7. ganeshie8
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    \(2x^2 + x - 3 \)

    • 10 months ago
  8. ganeshie8
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    compare it wid \(ax^2 + bx + c\)

    • 10 months ago
  9. Christos
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    ok

    • 10 months ago
  10. ganeshie8
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    we need to pick two numbers whose product equals \(ac\), and sum equals \(b\)

    • 10 months ago
  11. ganeshie8
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    a=2 b=1 c=-3

    • 10 months ago
  12. ganeshie8
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    can you pick two numbers whose product equals -6, and sum equals 1 ?

    • 10 months ago
  13. surjithayer
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    \[2x ^{2}+x-3=2x ^{2}+3x-2x-3\] (2*-3=-6,3-2=1) \[=x \left( 2x+3 \right)-1\left( 2x+3 \right)=\left( 2x+3 \right)\left( x-1 \right)\]

    • 10 months ago
  14. Christos
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    I dont think I can :(

    • 10 months ago
  15. ganeshie8
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    tell me what are the factors of -6

    • 10 months ago
  16. Christos
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    -1 -2 -3

    • 10 months ago
  17. ganeshie8
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    and 1, 2, 3 also

    • 10 months ago
  18. Christos
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    ooh ok

    • 10 months ago
  19. ganeshie8
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    so, 3 * -2 = -6

    • 10 months ago
  20. ganeshie8
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    3 + -2 = 1

    • 10 months ago
  21. ganeshie8
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    3 and -2 are our numbers !

    • 10 months ago
  22. Christos
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    So we dont take into considaration b ? We just add and multiply a and c?

    • 10 months ago
  23. ganeshie8
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    \(2x^2 + x - 3\) you need to rewrite x as 3x-2x

    • 10 months ago
  24. ganeshie8
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    we did consider b, the numbers we pick must multiply to ac, and addup to b

    • 10 months ago
  25. Christos
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    "3 * -2 = -6" "3 + -2 = 1" Where is b ?

    • 10 months ago
  26. ganeshie8
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    we picked 3 and -2, cuz they multiply to ac, and addup to b

    • 10 months ago
  27. ganeshie8
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    look at the given expression, b = 1

    • 10 months ago
  28. Christos
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    hm the second expression ye

    • 10 months ago
  29. ganeshie8
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    \(2x^2 + x - 3\) can be written as : \(2x^2 + 1x - 3\)

    • 10 months ago
  30. ganeshie8
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    compare it wid ax^2 + bx + c, and tell me whats b ?

    • 10 months ago
  31. Christos
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    yea I know it's 1, I just dont know what do it with it :D

    • 10 months ago
  32. Christos
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    lol

    • 10 months ago
  33. ganeshie8
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    so when you're asking where is b, you knw now that its there, and it is 1 :)

    • 10 months ago
  34. Christos
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    from my understanding we take a*c = whatever it gives then a+c = whatever it gives

    • 10 months ago
  35. ganeshie8
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    not exactly

    • 10 months ago
  36. Christos
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    hm

    • 10 months ago
  37. ganeshie8
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    we take a*c, tell whats a*c, in our current example ?

    • 10 months ago
  38. Christos
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    its -6

    • 10 months ago
  39. ganeshie8
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    so we take that -6, and find its factors. that addup to b

    • 10 months ago
  40. ganeshie8
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    -6 = 3*-2

    • 10 months ago
  41. Christos
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    when you say "add up" what do you mean exactly?

    • 10 months ago
  42. ganeshie8
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    when u add both the numbers, you must get b

    • 10 months ago
  43. ganeshie8
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    we picked 3 and -2, add them and see if u get b or not

    • 10 months ago
  44. ganeshie8
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    if p, q are the two numbers, you should pick them in a way such that :- pq = ac p+q = b

    • 10 months ago
  45. ganeshie8
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    thats all

    • 10 months ago
  46. Christos
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    I see now

    • 10 months ago
  47. ganeshie8
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    great :) you do few more problems u wil see more clearly

    • 10 months ago
  48. Christos
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    Ok so, we have a*c = -6 a-b = 1 but how do I proceed with this information in hand?

    • 10 months ago
  49. ganeshie8
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    heres the full solution, go through \(2x^2 + x - 3\) \(2x^2 + 3x - 2x - 3\) \(x(2x + 3) - 1(2x + 3)\) \((2x + 3)(x - 1)\)

    • 10 months ago
  50. Christos
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    a-c ***

    • 10 months ago
  51. ganeshie8
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    no

    • 10 months ago
  52. Christos
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    /facepalm I am such a dummy some times, I can see it clearly now, thanks again

    • 10 months ago
  53. ganeshie8
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    its, pq = ac p+q = b

    • 10 months ago
  54. ganeshie8
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    cool all geniuses have few dummy corners ;p

    • 10 months ago
  55. Christos
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    yea yea I see, I get you now

    • 10 months ago
  56. Christos
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    hihi xP

    • 10 months ago
  57. ganeshie8
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    good :)

    • 10 months ago
  58. Christos
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    ty dude

    • 10 months ago
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