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you dont knw how to factor

2x^2+x-3 factored would be (2x+3)(x-1)

i understand, let me guide u factor this

ty man

\(2x^2 + x - 3 \)

compare it wid
\(ax^2 + bx + c\)

ok

we need to pick two numbers whose product equals \(ac\), and sum equals \(b\)

a=2
b=1
c=-3

can you pick two numbers whose product equals -6, and sum equals 1 ?

I dont think I can :(

tell me what are the factors of -6

-1 -2 -3

and 1, 2, 3 also

ooh ok

so, 3 * -2 = -6

3 + -2 = 1

3 and -2 are our numbers !

So we dont take into considaration b ? We just add and multiply a and c?

\(2x^2 + x - 3\)
you need to rewrite x as 3x-2x

we did consider b, the numbers we pick must multiply to ac, and addup to b

"3 * -2 = -6"
"3 + -2 = 1"
Where is b ?

we picked 3 and -2, cuz they multiply to ac, and addup to b

look at the given expression, b = 1

hm the second expression ye

\(2x^2 + x - 3\)
can be written as :
\(2x^2 + 1x - 3\)

compare it wid ax^2 + bx + c, and tell me whats b ?

yea I know it's 1, I just dont know what do it with it :D

lol

so when you're asking where is b, you knw now that its there, and it is 1 :)

from my understanding
we take a*c = whatever it gives
then a+c = whatever it gives

not exactly

hm

we take a*c, tell whats a*c, in our current example ?

its -6

so we take that -6, and find its factors. that addup to b

-6 = 3*-2

when you say "add up" what do you mean exactly?

when u add both the numbers, you must get b

we picked 3 and -2, add them and see if u get b or not

if p, q are the two numbers, you should pick them in a way such that :-
pq = ac
p+q = b

thats all

I see now

great :) you do few more problems u wil see more clearly

Ok so, we have a*c = -6
a-b = 1
but how do I proceed with this information in hand?

a-c ***

no

/facepalm I am such a dummy some times, I can see it clearly now, thanks again

its,
pq = ac
p+q = b

cool all geniuses have few dummy corners ;p

yea yea I see, I get you now

hihi xP

good :)

ty dude