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Christos
 3 years ago
Can you help me find this limit:
http://screencast.com/t/6CD9ErAG3N9m
All I need is the first step, I am gonna climb from there easily. Sorry if it's a little unclear picture, it's from an old book
Christos
 3 years ago
Can you help me find this limit: http://screencast.com/t/6CD9ErAG3N9m All I need is the first step, I am gonna climb from there easily. Sorry if it's a little unclear picture, it's from an old book

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for reference, the answer is \[\sqrt3/2\] i do not remember the steps though, sorry

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0I know the answer too my friend, but I dont know how to find it, thanks though

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry i could not help :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0CANT EVEN SEE THE QUESTION

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0How Come?? The guy above you saw it , I posted a picture

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I can't see it either. what is the limit going to? Can't make it out after the arrow

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0+ infinity ***** I am sorry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lim of x going to positive infinity of sin((pi*x)/(23x))

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow +\infty}\sin (\frac{ \pi x }{ 23x })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you actually take the pic clearly?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow +\infty} Sin (\frac{ \pi x }{ 23x })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now Stewie can stop trolling, lol. xD

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I want to learn this too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You can divide by the highest power in the denominator which is x

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0But how does that lead you to the solution which is sqrt(3)/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can't you? \[\large \lim_{x \rightarrow +\infty}\sin(\frac{ \pi x/x }{ \frac{ 2 }{ x }\frac{ 3x }{ x } })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So what is \[\sin(\frac{ \pi }{ 3 })\]? Whcih quadrant is sine negative ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow +\infty} \sin \frac{ x }{ x }(\frac{ \pi }{ \frac{ 2 }{ x }  3 })\]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0@myko @timo86m @jim_thompson5910 @jhonyy9 @Hero @Euler271

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0The result is most likely engative yea

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0yes but HOW @rajee_sam

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sine is negative in quadrant 3 and 4, so if \[\sin \frac{ \pi }{ 3 } = \frac{ \sqrt{3} }{ 2 }\] then \[\sin \frac{ \pi }{ 3 }= \frac{ \sqrt{3} }{ 2 }\]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0Am I eligible to differantiate this thing ? because if we differantiate we get sin(pi/3)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369516434913:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You just need to find the positive radian measure, which is \[\frac{ \pi }{ }\] and then translate it accordingly to find which negative value is correlated with the positive radian measure

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sin ( \theta ) =  \sin (\theta)\]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get the x out @rajee_sam

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am taking a GCF for both numerator and denominator so that I can cancel them out and do not have any x multiplied with anything

phi
 3 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow +\infty}\sin \left(\frac{ \pi x }{ 23x }\right) = \sin\left( \lim_{x \rightarrow +\infty} \frac{ \pi x }{ 23x }\right)\] as noted above you can rewrite \[ \frac{ \pi x }{ 23x } = \frac{ \pi }{\frac{2}{x} 3} \]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0Alright! Alright! I solved it this way! By during the time I was trying to solve this I figured out a second way! Tell me if this is correct: Just taking the derivative of both denominator and numerator and then we are done. Can I apply this to ANY limit? Because here it works!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's what i did pi.... :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you're taking the derivative you'll have to use chain rule on the whole thing, sin (whatever's inside) and then * whatever is inside.

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes, you can use L'Hopital's rule http://en.wikipedia.org/wiki/L'Hôpital's_rule if you get 0/0 or inf/inf

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0I am talking about this specific problem

phi
 3 years ago
Best ResponseYou've already chosen the best response.1no, use chain rule. use \[ \lim_{x \rightarrow +\infty}\sin \left(\frac{ \pi x }{ 23x }\right) = \sin\left( \lim_{x \rightarrow +\infty} \frac{ \pi x }{ 23x }\right) \]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0but even if I dont use the chain rule we end up to the same result

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0Ohh so this formula you showed to me just now is only when we have 0/0 or infinite/infinite ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh I see, and you'd use LH rule to simplify it further and end up with the same result.

phi
 3 years ago
Best ResponseYou've already chosen the best response.1using L'Hopital's rule needs 0/0 or inf/inf use it on \[ \lim_{x \rightarrow +\infty} \frac{ \pi x }{ 23x } \]

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0ok and I get this http://screencast.com/t/jPlMQFrZ What now?

phi
 3 years ago
Best ResponseYou've already chosen the best response.1you can use L'Hopital d top/ d bottom = pi/3 or you can use algebra

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0and the lim(x>+infinity) goes away?

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0but still I am stuck on the lim thingy

phi
 3 years ago
Best ResponseYou've already chosen the best response.1then sin (pi/3) = sqrt{3}/2 *** and the lim(x>+infinity) goes away? if you use L'Hopital \[ \lim_{x \rightarrow +\infty} \frac{ \pi x }{ 23x } = \lim_{x \rightarrow +\infty} \frac{\pi}{3}= \frac{\pi}{3}\]
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