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satellite73
 one year ago
Best ResponseYou've already chosen the best response.1the square root grows slower so the limit will be zero

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Divide both numerator and denominator by x, to solve it algebraically.

Christos
 one year ago
Best ResponseYou've already chosen the best response.0I am sorry the actual epression is sort(x3/x)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x\to \infty}\sqrt{\frac{x3}{x}}\]?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1then it is one since \(x3\) and \(x\) grow at the same rate

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1think what it would be like if \(x\) was \(1,000\) you would have \[\sqrt{.993}\]

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large \lim_{x\to \infty}\sqrt{\frac{x3}{x}} = \sqrt {\lim_{x\to \infty}\frac{x3} {x}}\]

Christos
 one year ago
Best ResponseYou've already chosen the best response.0bro I am trying to solve this limit actually http://screencast.com/t/Yoo5IO0bRPjD And I ended up in the expression above, but what you give me isnt the final answer, something must be wrong :(

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2@Christos that's a completely different expression... break it up using limit laws.

Christos
 one year ago
Best ResponseYou've already chosen the best response.0ohh let me try hold on

Christos
 one year ago
Best ResponseYou've already chosen the best response.0What do you mean by limit laws?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large = \lim_{x \rightarrow \infty} \sqrt{x^2  3x} \lim_{x \rightarrow \infty} x\]

Christos
 one year ago
Best ResponseYou've already chosen the best response.0so thats infinity  infinity  infinity = +infinity?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2From a graph it looks like it'll be 1.5, I'm just trying to find a way to show that algebraically.

Christos
 one year ago
Best ResponseYou've already chosen the best response.0It's ok man dont brother I found it thank you

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Yeah i'm glad i didn't try to do it myself... wolfram gives a looooong solution: http://www3.wolframalpha.com/Calculate/MSP/MSP35891gdgbb0f2cc1ecie00005387i303c364idgg?MSPStoreType=image/png&s=42&w=433&h=1816
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