anonymous
  • anonymous
what is the simplified form of the expression (b/7)^2
Algebra
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1369532637410:dw|
anonymous
  • anonymous
@satellite73 I need help
anonymous
  • anonymous
please

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anonymous
  • anonymous
The choices are|dw:1369532959983:dw|
anonymous
  • anonymous
\[(\frac{b}{7})^2 = \frac{b^2}{7^2} = \frac{b^2}{49}\]
anonymous
  • anonymous
B
anonymous
  • anonymous
just square top and bottom on similar questions
anonymous
  • anonymous
Thanks so much I have 2 other questions if you guys don't mind
anonymous
  • anonymous
|dw:1369533436214:dw|
anonymous
  • anonymous
Pull out the coefficients and use \[x^ax^b=x^{a+b}\]
anonymous
  • anonymous
I don't know this at all I am a parent trying to give my 2 children some math for the summer so I am asking for the help because I have not done algebra in 25 years
anonymous
  • anonymous
Okay, well do you know what coefficients are?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay well then move those out so you get \[ 2*3x^6x^{1/2} \] and use the above formula.
anonymous
  • anonymous
the coefficients are the numbers in front of the variable whenever you are multiplying variables with powers you always must add the powers together
anonymous
  • anonymous
what will the final answer be?
anonymous
  • anonymous
6x^3
anonymous
  • anonymous
\[6x ^{3}\]
anonymous
  • anonymous
You need to add the powers, not multiply. so \[6x^{6+1/2}\]
anonymous
  • anonymous
ok so what is the answer
anonymous
  • anonymous
I will give you the choices
anonymous
  • anonymous
the answer would be\[6x^\frac{ 13 }{ 2 }\]
anonymous
  • anonymous
I have given you the answer, there is only one thing you need to do... Do you know how to add fractions with whole numbers?
anonymous
  • anonymous
that is 6x^13/2
anonymous
  • anonymous
so its \[5x \frac{ 13 }{2 }\]
anonymous
  • anonymous
Guys I feel so old doing this
anonymous
  • anonymous
all you need to do is add the powers which is 6+.5 and you get 6.5 which is 13/2 in fraction form so final answer would be 6x^13/2
anonymous
  • anonymous
the dean at my children school said they were cheating so I have to give this these math test so that can get ready to take the big test to passed algebra
anonymous
  • anonymous
this really means the world to me all the help from you guys
anonymous
  • anonymous
I have another if your up for it!
anonymous
  • anonymous
bring it on
anonymous
  • anonymous
|dw:1369534461113:dw|
anonymous
  • anonymous
on the top part is that C^9
anonymous
  • anonymous
yes
anonymous
  • anonymous
|dw:1369534620249:dw|
anonymous
  • anonymous
ok so this expression can be re-written as \[\frac{ x^9 }{ d^7 }/\frac{ x^14 }{ d^10 }\] which can be written as \[\frac{ x^9 }{ d^7 }*\frac{ d^10 }{ x^14 }\] the equation software on here is complexed but that is d^10 and x^-14
anonymous
  • anonymous
that is not a choice
anonymous
  • anonymous
now what we can do is simplify the expression easier this way and we do this by subtracting the powers of the variable x and subtract the powers of the variable d not finished yet
anonymous
  • anonymous
o sorry
anonymous
  • anonymous
\[\frac{ x^9 }{ x^14 }=\frac{ 1 }{ x^5 }\] andthe other one whic you get \[\frac{ d^10 }{ d^7 }=d^3\] combine and you get \[\frac{ d^3 }{ c^5 }\] sorry the x should have been a C
anonymous
  • anonymous
if you can't see that it is d^3/c^5
anonymous
  • anonymous
This one I tried but I got it wrong is it B
anonymous
  • anonymous
are you guys still with me?
anonymous
  • anonymous
yea my mom called for something but im back
anonymous
  • anonymous
Write the recursive formula for the geometric sequence. a1 = -2 a2 = 8 a3 = -32 A. an = -4 + an-1 B. an = -2 + an-1 C. an = -2 • an-1 D. an = -4 • an-1
anonymous
  • anonymous
do you want me to open this up in a new question so I can give you an award
anonymous
  • anonymous
no im ok but i am looking at the sequences and none of them can i derive from the formulas given
anonymous
  • anonymous
ohh never mind i got it the answer should be D
anonymous
  • anonymous
You rock
anonymous
  • anonymous
I am going to open up another question I want to give you an award for helping me
anonymous
  • anonymous
haha thank you

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