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Christos

Limits, Can you help me out with this please: http://screencast.com/t/lLsaUJErdX

  • 10 months ago
  • 10 months ago

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  1. satellite73
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    \[f(x)=2x^3+1\] \[f'(x)=3x^2\] \[f'(-1)=3\]

    • 10 months ago
  2. Christos
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    dude f'(x) = 6x^2

    • 10 months ago
  3. Christos
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    @satellite73

    • 10 months ago
  4. satellite73
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    oh right

    • 10 months ago
  5. satellite73
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    so \(f'(-1)=6\) is the slope

    • 10 months ago
  6. Christos
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    I know the slope, the rest is what I dont know

    • 10 months ago
  7. satellite73
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    you have the slope and the point use the point - slope formula

    • 10 months ago
  8. satellite73
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    slope is \(6\) and the point is \((-1,-2)\)

    • 10 months ago
  9. satellite73
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    oops \((-1,-1)\)

    • 10 months ago
  10. Christos
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    You see, I already have the solution. But I believe it's wrong http://screencast.com/t/2tjXXmjz9 That's why I asked you guys to cross over it

    • 10 months ago
  11. satellite73
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    \[y+1=6(x+1)\]

    • 10 months ago
  12. Christos
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    Is this wrong like I believe http://screencast.com/t/2tjXXmjz9 ?

    • 10 months ago
  13. satellite73
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    yeah that is wrong for sure

    • 10 months ago
  14. Christos
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    ty god

    • 10 months ago
  15. Christos
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    I knew it

    • 10 months ago
  16. aditya96
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    yes a=1 and not -1

    • 10 months ago
  17. satellite73
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    \[f(-1)=2\times (-1)^2+1=-2+1=-1\]

    • 10 months ago
  18. Christos
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    ty

    • 10 months ago
  19. aditya96
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    and f(a) =2

    • 10 months ago
  20. satellite73
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    its just wrong don't waste time thinking about it

    • 10 months ago
  21. Christos
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    My final result y = 6x + 7

    • 10 months ago
  22. aditya96
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    no y=6x+1

    • 10 months ago
  23. Christos
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    Kinda why

    • 10 months ago
  24. Christos
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    @aditya96

    • 10 months ago
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