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Christos

  • 2 years ago

Limits, Can you help me out with this please: http://screencast.com/t/lLsaUJErdX

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  1. anonymous
    • 2 years ago
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    \[f(x)=2x^3+1\] \[f'(x)=3x^2\] \[f'(-1)=3\]

  2. Christos
    • 2 years ago
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    dude f'(x) = 6x^2

  3. Christos
    • 2 years ago
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    @satellite73

  4. anonymous
    • 2 years ago
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    oh right

  5. anonymous
    • 2 years ago
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    so \(f'(-1)=6\) is the slope

  6. Christos
    • 2 years ago
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    I know the slope, the rest is what I dont know

  7. anonymous
    • 2 years ago
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    you have the slope and the point use the point - slope formula

  8. anonymous
    • 2 years ago
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    slope is \(6\) and the point is \((-1,-2)\)

  9. anonymous
    • 2 years ago
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    oops \((-1,-1)\)

  10. Christos
    • 2 years ago
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    You see, I already have the solution. But I believe it's wrong http://screencast.com/t/2tjXXmjz9 That's why I asked you guys to cross over it

  11. anonymous
    • 2 years ago
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    \[y+1=6(x+1)\]

  12. Christos
    • 2 years ago
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    Is this wrong like I believe http://screencast.com/t/2tjXXmjz9 ?

  13. anonymous
    • 2 years ago
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    yeah that is wrong for sure

  14. Christos
    • 2 years ago
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    ty god

  15. Christos
    • 2 years ago
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    I knew it

  16. aditya96
    • 2 years ago
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    yes a=1 and not -1

  17. anonymous
    • 2 years ago
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    \[f(-1)=2\times (-1)^2+1=-2+1=-1\]

  18. Christos
    • 2 years ago
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    ty

  19. aditya96
    • 2 years ago
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    and f(a) =2

  20. anonymous
    • 2 years ago
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    its just wrong don't waste time thinking about it

  21. Christos
    • 2 years ago
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    My final result y = 6x + 7

  22. aditya96
    • 2 years ago
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    no y=6x+1

  23. Christos
    • 2 years ago
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    Kinda why

  24. Christos
    • 2 years ago
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    @aditya96

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