Christos
  • Christos
Limits, Can you help me out with this please: http://screencast.com/t/lLsaUJErdX
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[f(x)=2x^3+1\] \[f'(x)=3x^2\] \[f'(-1)=3\]
Christos
  • Christos
dude f'(x) = 6x^2
Christos
  • Christos
@satellite73

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anonymous
  • anonymous
oh right
anonymous
  • anonymous
so \(f'(-1)=6\) is the slope
Christos
  • Christos
I know the slope, the rest is what I dont know
anonymous
  • anonymous
you have the slope and the point use the point - slope formula
anonymous
  • anonymous
slope is \(6\) and the point is \((-1,-2)\)
anonymous
  • anonymous
oops \((-1,-1)\)
Christos
  • Christos
You see, I already have the solution. But I believe it's wrong http://screencast.com/t/2tjXXmjz9 That's why I asked you guys to cross over it
anonymous
  • anonymous
\[y+1=6(x+1)\]
Christos
  • Christos
Is this wrong like I believe http://screencast.com/t/2tjXXmjz9 ?
anonymous
  • anonymous
yeah that is wrong for sure
Christos
  • Christos
ty god
Christos
  • Christos
I knew it
anonymous
  • anonymous
yes a=1 and not -1
anonymous
  • anonymous
\[f(-1)=2\times (-1)^2+1=-2+1=-1\]
Christos
  • Christos
ty
anonymous
  • anonymous
and f(a) =2
anonymous
  • anonymous
its just wrong don't waste time thinking about it
Christos
  • Christos
My final result y = 6x + 7
anonymous
  • anonymous
no y=6x+1
Christos
  • Christos
Kinda why
Christos
  • Christos
@aditya96

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