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anonymous
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\[f(x)=2x^3+1\]
\[f'(x)=3x^2\]
\[f'(1)=3\]

Christos
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dude f'(x) = 6x^2

Christos
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@satellite73

anonymous
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oh right

anonymous
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so \(f'(1)=6\) is the slope

Christos
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I know the slope, the rest is what I dont know

anonymous
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you have the slope and the point
use the point  slope formula

anonymous
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slope is \(6\) and the point is \((1,2)\)

anonymous
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oops \((1,1)\)

Christos
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You see, I already have the solution. But I believe it's wrong
http://screencast.com/t/2tjXXmjz9
That's why I asked you guys to cross over it

anonymous
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\[y+1=6(x+1)\]


anonymous
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yeah that is wrong for sure

Christos
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ty god

Christos
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I knew it

aditya96
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yes a=1 and not 1

anonymous
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\[f(1)=2\times (1)^2+1=2+1=1\]

Christos
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ty

aditya96
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and f(a) =2

anonymous
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its just wrong
don't waste time thinking about it

Christos
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My final result y = 6x + 7

aditya96
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no y=6x+1

Christos
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Kinda why

Christos
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@aditya96