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Christos

What's the derivative of sqrt(sqrt(x)) ?

  • 11 months ago
  • 11 months ago

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  1. Jhannybean
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    \[\large \sqrt{\sqrt{x}} = x ^{1/4}\]

    • 11 months ago
  2. primeralph
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    |dw:1369534488508:dw|

    • 11 months ago
  3. Christos
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    Just so you know I already solved it. I just need to verify my answer

    • 11 months ago
  4. Christos
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    Because this is my first time doing this type of sort

    • 11 months ago
  5. Christos
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    sqrt**

    • 11 months ago
  6. Jhannybean
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    \[\large x ^{1/4 }= x ^{n}= \frac{ nx ^{n-1} }{ n-1 }\]

    • 11 months ago
  7. Christos
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    is it x^(-3/4)/4 just tell me that

    • 11 months ago
  8. Christos
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    I already solved it and got this as a result.

    • 11 months ago
  9. Jhannybean
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    \[\frac{ 1 }{ 4 }x ^{-3/4}\] = \[\large \frac{ 1 }{ 4x ^{3/4}}\]

    • 11 months ago
  10. Christos
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    thanks a lot

    • 11 months ago
  11. Jhannybean
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    Yep.

    • 11 months ago
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