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Christos

  • 2 years ago

What's the derivative of sqrt(sqrt(x)) ?

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  1. Jhannybean
    • 2 years ago
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    \[\large \sqrt{\sqrt{x}} = x ^{1/4}\]

  2. primeralph
    • 2 years ago
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    |dw:1369534488508:dw|

  3. Christos
    • 2 years ago
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    Just so you know I already solved it. I just need to verify my answer

  4. Christos
    • 2 years ago
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    Because this is my first time doing this type of sort

  5. Christos
    • 2 years ago
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    sqrt**

  6. Jhannybean
    • 2 years ago
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    \[\large x ^{1/4 }= x ^{n}= \frac{ nx ^{n-1} }{ n-1 }\]

  7. Christos
    • 2 years ago
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    is it x^(-3/4)/4 just tell me that

  8. Christos
    • 2 years ago
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    I already solved it and got this as a result.

  9. Jhannybean
    • 2 years ago
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    \[\frac{ 1 }{ 4 }x ^{-3/4}\] = \[\large \frac{ 1 }{ 4x ^{3/4}}\]

  10. Christos
    • 2 years ago
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    thanks a lot

  11. Jhannybean
    • 2 years ago
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    Yep.

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