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Tabbiejack Group Title

What is the simplified form of the expression? x^8 2y^10 5x^5

  • one year ago
  • one year ago

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  1. Tabbiejack Group Title
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    \[x ^{8} 2y ^{10} 5x ^{5}\]

    • one year ago
  2. Tabbiejack Group Title
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    @galacticwavesXX

    • one year ago
  3. Compassionate Group Title
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    Add the coefficients and variables of your terms.

    • one year ago
  4. galacticwavesXX Group Title
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    you would have \[5x^5*x^8*2y^10\rightarrow (5x^13)(2y^10)\] x^5*x^8=x^13 that is how i got x^13 then just put everything back together and you get 5x^13*2y^10

    • one year ago
  5. galacticwavesXX Group Title
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    forgot to multiply the coefficients so you would get 10x^13*y^10

    • one year ago
  6. Tabbiejack Group Title
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    oh thanks I am trying to understand it a little is coming back thanks for explaining

    • one year ago
  7. Tabbiejack Group Title
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    here is another

    • one year ago
  8. galacticwavesXX Group Title
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    welcome anytime just remember that coefficients you multiply and variable with powers you add

    • one year ago
  9. Tabbiejack Group Title
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    What is the simplified form of the expression?|dw:1369536827542:dw|

    • one year ago
  10. galacticwavesXX Group Title
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    so we have \[k^3(k^\frac{ 7 }{ 3 })^-5 \rightarrow (k^\frac{ 16 }{ 3 })^-5\] so we have [k^(16/3)]^-5

    • one year ago
  11. Tabbiejack Group Title
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    that is not an option

    • one year ago
  12. galacticwavesXX Group Title
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    im not done im just seeing if i did it correctly but what are the options because i have a possible answer?

    • one year ago
  13. Tabbiejack Group Title
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    o ok

    • one year ago
  14. galacticwavesXX Group Title
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    can i see what are the possible answers?

    • one year ago
  15. Tabbiejack Group Title
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    |dw:1369537422248:dw|

    • one year ago
  16. galacticwavesXX Group Title
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    whattt....for the problem itself is the k^3*(k^7/3)^-5 ? cause i got a totally different answer

    • one year ago
  17. galacticwavesXX Group Title
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    for the problem you wrote down are we trying to simplify k^3*(k^7/3)^-5 ? or did i get it wrong because none of the answers you posted did i get

    • one year ago
  18. Tabbiejack Group Title
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    no that is right

    • one year ago
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