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Tabbiejack

  • 2 years ago

What is the simplified form of the expression? x^8 2y^10 5x^5

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  1. Tabbiejack
    • 2 years ago
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    \[x ^{8} 2y ^{10} 5x ^{5}\]

  2. Tabbiejack
    • 2 years ago
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    @galacticwavesXX

  3. Compassionate
    • 2 years ago
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    Add the coefficients and variables of your terms.

  4. galacticwavesXX
    • 2 years ago
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    you would have \[5x^5*x^8*2y^10\rightarrow (5x^13)(2y^10)\] x^5*x^8=x^13 that is how i got x^13 then just put everything back together and you get 5x^13*2y^10

  5. galacticwavesXX
    • 2 years ago
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    forgot to multiply the coefficients so you would get 10x^13*y^10

  6. Tabbiejack
    • 2 years ago
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    oh thanks I am trying to understand it a little is coming back thanks for explaining

  7. Tabbiejack
    • 2 years ago
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    here is another

  8. galacticwavesXX
    • 2 years ago
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    welcome anytime just remember that coefficients you multiply and variable with powers you add

  9. Tabbiejack
    • 2 years ago
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    What is the simplified form of the expression?|dw:1369536827542:dw|

  10. galacticwavesXX
    • 2 years ago
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    so we have \[k^3(k^\frac{ 7 }{ 3 })^-5 \rightarrow (k^\frac{ 16 }{ 3 })^-5\] so we have [k^(16/3)]^-5

  11. Tabbiejack
    • 2 years ago
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    that is not an option

  12. galacticwavesXX
    • 2 years ago
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    im not done im just seeing if i did it correctly but what are the options because i have a possible answer?

  13. Tabbiejack
    • 2 years ago
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    o ok

  14. galacticwavesXX
    • 2 years ago
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    can i see what are the possible answers?

  15. Tabbiejack
    • 2 years ago
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    |dw:1369537422248:dw|

  16. galacticwavesXX
    • 2 years ago
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    whattt....for the problem itself is the k^3*(k^7/3)^-5 ? cause i got a totally different answer

  17. galacticwavesXX
    • 2 years ago
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    for the problem you wrote down are we trying to simplify k^3*(k^7/3)^-5 ? or did i get it wrong because none of the answers you posted did i get

  18. Tabbiejack
    • 2 years ago
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    no that is right

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