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Tabbiejack

  • 2 years ago

Write the explicit formula for the geometric sequence. a1 = -5 a2 = 20 a3 = -80 A. an = -5 • (-4)n B. an = -5(-4)n-1 C. an = -4(-5)n-1 D. an = -5 • (4)n

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  1. bahrom7893
    • 2 years ago
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    look a1 = -5 n=1 a2=20 n=2, etc..

  2. Jhannybean
    • 2 years ago
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    It would be B because in a geometric sequence, you have \[\large ar ^{n-1}\] and in finding our r, we take \(\large\frac{ a _{2} }{ a _{1} }\) and that is -4

  3. bahrom7893
    • 2 years ago
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    This way you can eliminate A because term 2 doesn't match up... And I think Jhanny's right

  4. Tabbiejack
    • 2 years ago
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    thanks you that was heard

  5. Jhannybean
    • 2 years ago
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    So we have a1 = -5, our r = -4 and plug it into our formula \[\large ar ^{n-1}\]

  6. Jhannybean
    • 2 years ago
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    thanks bahrom :)

  7. Tabbiejack
    • 2 years ago
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    Can you help me with another

  8. Jhannybean
    • 2 years ago
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    sure

  9. Tabbiejack
    • 2 years ago
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    What is the simplified form of the expression?|dw:1369539526178:dw|

  10. Jhannybean
    • 2 years ago
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    Alright, for this one you have a variable with two different powers dividing eachother, and in this case, we can simply do this. \[\large \frac{ 1 }{ q ^{\color{red}{(33/4)-8} }}\]

  11. Jhannybean
    • 2 years ago
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    we you know to solve \[\color{fuchsia}{\frac{ 33 }{ 4 }}-\color{green}{8}\]

  12. Tabbiejack
    • 2 years ago
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    |dw:1369539985575:dw|

  13. Tabbiejack
    • 2 years ago
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    That is the choices

  14. Jhannybean
    • 2 years ago
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    hmm...something seems wrong here.

  15. Jhannybean
    • 2 years ago
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    \[\frac{ 33 }{ 4 }-8*(\frac{ \color{green}{4} }{ \color{green}{4} })= \frac{ 33 }{ 4 }-\frac{ \color{darkorchid}{32} }{ \color{darkorchid}{4} }\]

  16. Jhannybean
    • 2 years ago
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    Ohh I see. hm, well what do you get when you reduce 33/4- 32/4? :D

  17. Tabbiejack
    • 2 years ago
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    I am confused

  18. Jhannybean
    • 2 years ago
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    hm?

  19. Tabbiejack
    • 2 years ago
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    I have no Idea what the answer is

  20. Jhannybean
    • 2 years ago
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    solve (33/4)-(32/4) and we'll work from there, you'; get your answer, promise :)

  21. Tabbiejack
    • 2 years ago
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    I am the parent of 2 children that is failing

  22. Tabbiejack
    • 2 years ago
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    this looks like greek to me..

  23. Jhannybean
    • 2 years ago
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    ok, what is.... 3-2?

  24. Tabbiejack
    • 2 years ago
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    1

  25. Jhannybean
    • 2 years ago
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    good :) so 33-32 works the same way, it is also 1.

  26. Jhannybean
    • 2 years ago
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    So we now have \[\frac{ 1 }{ q ^{\color{blue}{1/4}} }\]

  27. Tabbiejack
    • 2 years ago
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    o ok

  28. Tabbiejack
    • 2 years ago
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    I thank you so much

  29. Tabbiejack
    • 2 years ago
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    algebra has always been my worst subject

  30. Jhannybean
    • 2 years ago
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    It'll get better with practice :) Practice makes people perfect in math ^_^

  31. Tabbiejack
    • 2 years ago
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    I remember hearing that when I was young

  32. Tabbiejack
    • 2 years ago
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    I have another quesiton if you are up to it?

  33. Jhannybean
    • 2 years ago
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    Of course :) Math is a lot about understanding a problem as a whole and finding a relation to a technique method in solving, it's all patterns.

  34. Jhannybean
    • 2 years ago
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    sure thing

  35. Tabbiejack
    • 2 years ago
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    I have 2 test to give to my children for the summer to help them prepare for summer school that is why I am getting the answers so I will be able to help them

  36. Jhannybean
    • 2 years ago
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    Interesting

  37. Tabbiejack
    • 2 years ago
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    What is the simplified form of the expression?|dw:1369541274406:dw|

  38. Jhannybean
    • 2 years ago
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    \[\large (3x ^{\color{forestgreen}{7/2}})^{\color{blue}{6}}(x ^{\color{green}{2}})^{\color{blue}{6}}\] here, we will start 1 part at a time. lets start with \(\large (3x ^{7/2})^{6}\)

  39. Tabbiejack
    • 2 years ago
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    ok what do we do next

  40. Jhannybean
    • 2 years ago
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    we're going to multiply 6 to the 3 AND the x^(7/2)

  41. Jhannybean
    • 2 years ago
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    Are you able to do that?

  42. Tabbiejack
    • 2 years ago
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    18 x

  43. Tabbiejack
    • 2 years ago
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    I suck

  44. Jhannybean
    • 2 years ago
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    Hm.. not exactly, we have \[\large(3^{\color{blue}{6}})(x ^{\color{blue}{(7/2)(6)}})\] which gives us \[\large(729x ^{21})\]

  45. Tabbiejack
    • 2 years ago
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    A. 729x33 B. 3x33 C. 729x29 D. 3x29

  46. Jhannybean
    • 2 years ago
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    Now that we've taken care of the first part, we can move onto the second part, which is \[\large (x ^{2})^{6} = x ^{\color{red}{6*2}}= x ^{\color{blue}{12}}\]

  47. Tabbiejack
    • 2 years ago
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    ok

  48. Jhannybean
    • 2 years ago
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    Now we can combine both parts together so we get \[\large (729x {^\color{green}{21}}) *(x ^{\color{green}{12}}) = 729x ^{\color{red}{21+12}}\]

  49. Jhannybean
    • 2 years ago
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    And adding 21 + 12 for the exponent, you'll get your answer. i've done the rest

  50. Jhannybean
    • 2 years ago
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    Good luck with your other problems!

  51. Tabbiejack
    • 2 years ago
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    33

  52. Tabbiejack
    • 2 years ago
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    729x^33

  53. Tabbiejack
    • 2 years ago
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    am I right?

  54. Tabbiejack
    • 2 years ago
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    thanks so much

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