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Write the explicit formula for the geometric sequence. a1 = -5 a2 = 20 a3 = -80 A. an = -5 • (-4)n B. an = -5(-4)n-1 C. an = -4(-5)n-1 D. an = -5 • (4)n

Mathematics
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look a1 = -5 n=1 a2=20 n=2, etc..
It would be B because in a geometric sequence, you have \[\large ar ^{n-1}\] and in finding our r, we take \(\large\frac{ a _{2} }{ a _{1} }\) and that is -4
This way you can eliminate A because term 2 doesn't match up... And I think Jhanny's right

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Other answers:

thanks you that was heard
So we have a1 = -5, our r = -4 and plug it into our formula \[\large ar ^{n-1}\]
thanks bahrom :)
Can you help me with another
sure
What is the simplified form of the expression?|dw:1369539526178:dw|
Alright, for this one you have a variable with two different powers dividing eachother, and in this case, we can simply do this. \[\large \frac{ 1 }{ q ^{\color{red}{(33/4)-8} }}\]
we you know to solve \[\color{fuchsia}{\frac{ 33 }{ 4 }}-\color{green}{8}\]
|dw:1369539985575:dw|
That is the choices
hmm...something seems wrong here.
\[\frac{ 33 }{ 4 }-8*(\frac{ \color{green}{4} }{ \color{green}{4} })= \frac{ 33 }{ 4 }-\frac{ \color{darkorchid}{32} }{ \color{darkorchid}{4} }\]
Ohh I see. hm, well what do you get when you reduce 33/4- 32/4? :D
I am confused
hm?
I have no Idea what the answer is
solve (33/4)-(32/4) and we'll work from there, you'; get your answer, promise :)
I am the parent of 2 children that is failing
this looks like greek to me..
ok, what is.... 3-2?
1
good :) so 33-32 works the same way, it is also 1.
So we now have \[\frac{ 1 }{ q ^{\color{blue}{1/4}} }\]
o ok
I thank you so much
algebra has always been my worst subject
It'll get better with practice :) Practice makes people perfect in math ^_^
I remember hearing that when I was young
I have another quesiton if you are up to it?
Of course :) Math is a lot about understanding a problem as a whole and finding a relation to a technique method in solving, it's all patterns.
sure thing
I have 2 test to give to my children for the summer to help them prepare for summer school that is why I am getting the answers so I will be able to help them
Interesting
What is the simplified form of the expression?|dw:1369541274406:dw|
\[\large (3x ^{\color{forestgreen}{7/2}})^{\color{blue}{6}}(x ^{\color{green}{2}})^{\color{blue}{6}}\] here, we will start 1 part at a time. lets start with \(\large (3x ^{7/2})^{6}\)
ok what do we do next
we're going to multiply 6 to the 3 AND the x^(7/2)
Are you able to do that?
18 x
I suck
Hm.. not exactly, we have \[\large(3^{\color{blue}{6}})(x ^{\color{blue}{(7/2)(6)}})\] which gives us \[\large(729x ^{21})\]
A. 729x33 B. 3x33 C. 729x29 D. 3x29
Now that we've taken care of the first part, we can move onto the second part, which is \[\large (x ^{2})^{6} = x ^{\color{red}{6*2}}= x ^{\color{blue}{12}}\]
ok
Now we can combine both parts together so we get \[\large (729x {^\color{green}{21}}) *(x ^{\color{green}{12}}) = 729x ^{\color{red}{21+12}}\]
And adding 21 + 12 for the exponent, you'll get your answer. i've done the rest
Good luck with your other problems!
33
729x^33
am I right?
thanks so much

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