Here's the question you clicked on:
u0860867
Urgent help needed Pls Help
Do u understand the concept of continuity?
Not completely @ allank
Okay. Lemme walk u through it..
If we have the graph of a function, it is continuous if it is differentiable at all points i.e. it has no breaks, sharp corners, etc.
if lim of f(x) as x approaches a from the left = the limit as x approaches a from the right, the limit exists. if the limit exists at a, then the function is continuous at a. [square brackets] mean that the number is included in the interval (round brackets) mean that the point is not included in the interval.
[-4,2),(-2,2),[2,4),(4,6),(6,8)
@allank so when u say sharp corners do you also mean by turning points where it slowly rises and then falls
No, the function is differentiable there. |dw:1369549739726:dw|
@allank so from this graph how do we determine where the graph is continous??? Sorry for hassling u again and again
@Euler271 do u think you could help me solve this question as well
No prob. So avoid intervals where we breaks like: |dw:1369550343320:dw|
And vertical asymptotes like: |dw:1369550390687:dw|
|dw:1369550623413:dw|