## u0860867 2 years ago Urgent help needed Pls Help

1. u0860867

2. allank

Do u understand the concept of continuity?

3. u0860867

Not completely @ allank

4. allank

Okay. Lemme walk u through it..

5. u0860867

@allank

6. allank

If we have the graph of a function, it is continuous if it is differentiable at all points i.e. it has no breaks, sharp corners, etc.

7. Euler271

if lim of f(x) as x approaches a from the left = the limit as x approaches a from the right, the limit exists. if the limit exists at a, then the function is continuous at a. [square brackets] mean that the number is included in the interval (round brackets) mean that the point is not included in the interval.

[-4,2),(-2,2),[2,4),(4,6),(6,8)

9. allank

Carry on @Euler271

10. u0860867

@allank so when u say sharp corners do you also mean by turning points where it slowly rises and then falls

11. allank

No, the function is differentiable there. |dw:1369549739726:dw|

12. u0860867

@allank so from this graph how do we determine where the graph is continous??? Sorry for hassling u again and again

13. u0860867

@Euler271 do u think you could help me solve this question as well

14. allank

No prob. So avoid intervals where we breaks like: |dw:1369550343320:dw|

15. allank

And vertical asymptotes like: |dw:1369550390687:dw|

16. RaphaelFilgueiras

|dw:1369550623413:dw|