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ln(x^2) = 2ln(x)
what is the integral of ln(x)?
no that's the derivative
hint: let u = ln(x) and let dv = 1 dx
try not to just give answers? we can go to wolfram for that
@zzr0ck3r still not the final answer; but I'll take it off
xln(x) ? I still refuse to go by the answer :D
@Christos xlnx is not the answer. Use integration by parts
if you are just guessing you can go to wolframalpha and get the answer
I am not guessing I though x has a power of 1 so -1 at the end and outside of ln whatever is inside
I saw it somewhere long time ago but im not sure if its correct
u need to do integration by parts
is that what you are doing in class?
What is this, can you give me an example?
I am learning alone.
do you know what the product rule is with derivatives?
it is like the inverse of that, it is how we undo that rule.
I would google it and read on it, it takes practice
do you know u substitution for integration?
ok that "undoes" the chain rule, so now you need to learn by parts. there are both crucial to learning integration http://tutorial.math.lamar.edu/Classes/CalcII/IntegrationByParts.aspx
Look at this please: That's specifically what am trying to solve. http://screencast.com/t/0N48E4lhqM9
e^(2*lnx) = e^ln(x^2) = x^2 so you need the integral of x^2 not ln(x^2)
I solved it now :D I know how to find this thing very easy (x^3)/3 without any actual formula