- Christos

Whats the integral of ln(x^2)
?

- katieb

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- zzr0ck3r

ln(x^2) = 2ln(x)

- zzr0ck3r

what is the integral of ln(x)?

- Christos

1/x ?

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## More answers

- zzr0ck3r

no that's the derivative

- Christos

wait

- zzr0ck3r

hint: let u = ln(x) and let dv = 1 dx

- zzr0ck3r

try not to just give answers? we can go to wolfram for that

- primeralph

@zzr0ck3r still not the final answer; but I'll take it off

- Christos

xln(x) ? I still refuse to go by the answer :D

- primeralph

@Christos xlnx is not the answer. Use integration by parts

- Christos

xln(x)-1

- zzr0ck3r

if you are just guessing you can go to wolframalpha and get the answer

- Christos

I am not guessing I though x has a power of 1 so -1 at the end and outside of ln whatever is inside

- Christos

I saw it somewhere long time ago but im not sure if its correct

- zzr0ck3r

u need to do integration by parts

- zzr0ck3r

is that what you are doing in class?

- Christos

What is this, can you give me an example?

- Christos

I am learning alone.

- zzr0ck3r

do you know what the product rule is with derivatives?

- Christos

I do

- zzr0ck3r

it is like the inverse of that, it is how we undo that rule.

- zzr0ck3r

I would google it and read on it, it takes practice

- Christos

the reverse?

- zzr0ck3r

sort of

- zzr0ck3r

do you know u substitution for integration?

- Christos

yes

- zzr0ck3r

ok that "undoes" the chain rule, so now you need to learn by parts.
there are both crucial to learning integration
http://tutorial.math.lamar.edu/Classes/CalcII/IntegrationByParts.aspx

- Christos

Look at this please: That's specifically what am trying to solve. http://screencast.com/t/0N48E4lhqM9

- zzr0ck3r

e^(2*lnx) = e^ln(x^2) = x^2
so you need the integral of x^2 not ln(x^2)

- Christos

I solved it now :D I know how to find this thing very easy
(x^3)/3 without any actual formula

- zzr0ck3r

yeah:)

- Christos

thanks

- zzr0ck3r

np

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