Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
ln(x^2) = 2ln(x)
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
what is the integral of ln(x)?
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
no that's the derivative
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
hint: let u = ln(x) and let dv = 1 dx
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
try not to just give answers? we can go to wolfram for that
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.0
@zzr0ck3r still not the final answer; but I'll take it off
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
xln(x) ? I still refuse to go by the answer :D
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.0
@Christos xlnx is not the answer. Use integration by parts
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
if you are just guessing you can go to wolframalpha and get the answer
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
I am not guessing I though x has a power of 1 so 1 at the end and outside of ln whatever is inside
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
I saw it somewhere long time ago but im not sure if its correct
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
u need to do integration by parts
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
is that what you are doing in class?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
What is this, can you give me an example?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
I am learning alone.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
do you know what the product rule is with derivatives?
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
it is like the inverse of that, it is how we undo that rule.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
I would google it and read on it, it takes practice
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
the reverse?
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
do you know u substitution for integration?
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
ok that "undoes" the chain rule, so now you need to learn by parts. there are both crucial to learning integration http://tutorial.math.lamar.edu/Classes/CalcII/IntegrationByParts.aspx
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
Look at this please: That's specifically what am trying to solve. http://screencast.com/t/0N48E4lhqM9
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
e^(2*lnx) = e^ln(x^2) = x^2 so you need the integral of x^2 not ln(x^2)
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.1
I solved it now :D I know how to find this thing very easy (x^3)/3 without any actual formula
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.