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Christos

  • 2 years ago

integral of 1/(u^3) ?

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  1. Christos
    • 2 years ago
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    @zzr0ck3r u there?

  2. Jhannybean
    • 2 years ago
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    \[\large \int\limits \frac{ 1 }{ u^3 }du= \int\limits u^{-3}du\] you know how to integrate that right.

  3. Christos
    • 2 years ago
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    to tell you the truth I already knew how to do it, I just think this exersise is wrong so I need to verify, look at the bottom http://screencast.com/t/XEJ9Dmj1S

  4. zzr0ck3r
    • 2 years ago
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    looks good

  5. Christos
    • 2 years ago
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    my result: (1/2)*((-1/18) + (1/72))

  6. zzr0ck3r
    • 2 years ago
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    what is the problem?

  7. Christos
    • 2 years ago
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    http://screencast.com/t/XEJ9Dmj1S this solution displays a different result

  8. Christos
    • 2 years ago
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    Just making sure I didnt miss anything lol

  9. anonymous
    • 2 years ago
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    where did the \(\frac{1}{18}\) come from ?

  10. zzr0ck3r
    • 2 years ago
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    the solution looks fine

  11. Christos
    • 2 years ago
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    3^2 = 9*2 = 18

  12. zzr0ck3r
    • 2 years ago
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    show us what you did, did u change your bounds when you substituted?

  13. zzr0ck3r
    • 2 years ago
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    3^2 = 3*3 = 9

  14. anonymous
    • 2 years ago
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    three squared is not equal to nine squared

  15. Christos
    • 2 years ago
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    9*2(denominator) = 18

  16. zzr0ck3r
    • 2 years ago
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    18 = 2*3^2

  17. Christos
    • 2 years ago
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    Right

  18. zzr0ck3r
    • 2 years ago
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    I m confused:)

  19. Christos
    • 2 years ago
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    ;p

  20. anonymous
    • 2 years ago
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    \[F(u)=-\frac{1}{4u^2}\] \[F(3)-F(6)=-\frac{1}{4}\left(\frac{1}{9}-\frac{1}{36}\right)\]

  21. Christos
    • 2 years ago
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    where did the 1/4 come from

  22. Christos
    • 2 years ago
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    there might be a probability that my solution and the other one are equal idk

  23. Christos
    • 2 years ago
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    :D

  24. anonymous
    • 2 years ago
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    the u - sub gave a factor of \(\frac{1}{2}\) and the anti derivative gave another \(-\frac{1}{2}\)

  25. Christos
    • 2 years ago
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    aah!

  26. Christos
    • 2 years ago
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    hold on

  27. Christos
    • 2 years ago
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    That was the trick, thank you

  28. anonymous
    • 2 years ago
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    yw

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