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JhannybeanBest ResponseYou've already chosen the best response.0
\[\large \int\limits \frac{ 1 }{ u^3 }du= \int\limits u^{3}du\] you know how to integrate that right.
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
to tell you the truth I already knew how to do it, I just think this exersise is wrong so I need to verify, look at the bottom http://screencast.com/t/XEJ9Dmj1S
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
my result: (1/2)*((1/18) + (1/72))
 11 months ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
what is the problem?
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
http://screencast.com/t/XEJ9Dmj1S this solution displays a different result
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
Just making sure I didnt miss anything lol
 11 months ago

satellite73Best ResponseYou've already chosen the best response.2
where did the \(\frac{1}{18}\) come from ?
 11 months ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
the solution looks fine
 11 months ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
show us what you did, did u change your bounds when you substituted?
 11 months ago

satellite73Best ResponseYou've already chosen the best response.2
three squared is not equal to nine squared
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
9*2(denominator) = 18
 11 months ago

satellite73Best ResponseYou've already chosen the best response.2
\[F(u)=\frac{1}{4u^2}\] \[F(3)F(6)=\frac{1}{4}\left(\frac{1}{9}\frac{1}{36}\right)\]
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
where did the 1/4 come from
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
there might be a probability that my solution and the other one are equal idk
 11 months ago

satellite73Best ResponseYou've already chosen the best response.2
the u  sub gave a factor of \(\frac{1}{2}\) and the anti derivative gave another \(\frac{1}{2}\)
 11 months ago

ChristosBest ResponseYou've already chosen the best response.0
That was the trick, thank you
 11 months ago
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