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Christos Group Title

integral of 1/(u^3) ?

  • one year ago
  • one year ago

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  1. Christos Group Title
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    @zzr0ck3r u there?

    • one year ago
  2. Jhannybean Group Title
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    \[\large \int\limits \frac{ 1 }{ u^3 }du= \int\limits u^{-3}du\] you know how to integrate that right.

    • one year ago
  3. Christos Group Title
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    to tell you the truth I already knew how to do it, I just think this exersise is wrong so I need to verify, look at the bottom http://screencast.com/t/XEJ9Dmj1S

    • one year ago
  4. zzr0ck3r Group Title
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    looks good

    • one year ago
  5. Christos Group Title
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    my result: (1/2)*((-1/18) + (1/72))

    • one year ago
  6. zzr0ck3r Group Title
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    what is the problem?

    • one year ago
  7. Christos Group Title
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    http://screencast.com/t/XEJ9Dmj1S this solution displays a different result

    • one year ago
  8. Christos Group Title
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    Just making sure I didnt miss anything lol

    • one year ago
  9. satellite73 Group Title
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    where did the \(\frac{1}{18}\) come from ?

    • one year ago
  10. zzr0ck3r Group Title
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    the solution looks fine

    • one year ago
  11. Christos Group Title
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    3^2 = 9*2 = 18

    • one year ago
  12. zzr0ck3r Group Title
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    show us what you did, did u change your bounds when you substituted?

    • one year ago
  13. zzr0ck3r Group Title
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    3^2 = 3*3 = 9

    • one year ago
  14. satellite73 Group Title
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    three squared is not equal to nine squared

    • one year ago
  15. Christos Group Title
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    9*2(denominator) = 18

    • one year ago
  16. zzr0ck3r Group Title
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    18 = 2*3^2

    • one year ago
  17. Christos Group Title
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    Right

    • one year ago
  18. zzr0ck3r Group Title
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    I m confused:)

    • one year ago
  19. Christos Group Title
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    ;p

    • one year ago
  20. satellite73 Group Title
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    \[F(u)=-\frac{1}{4u^2}\] \[F(3)-F(6)=-\frac{1}{4}\left(\frac{1}{9}-\frac{1}{36}\right)\]

    • one year ago
  21. Christos Group Title
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    where did the 1/4 come from

    • one year ago
  22. Christos Group Title
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    there might be a probability that my solution and the other one are equal idk

    • one year ago
  23. Christos Group Title
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    :D

    • one year ago
  24. satellite73 Group Title
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    the u - sub gave a factor of \(\frac{1}{2}\) and the anti derivative gave another \(-\frac{1}{2}\)

    • one year ago
  25. Christos Group Title
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    aah!

    • one year ago
  26. Christos Group Title
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    hold on

    • one year ago
  27. Christos Group Title
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    That was the trick, thank you

    • one year ago
  28. satellite73 Group Title
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    yw

    • one year ago
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