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Christos Group Title

f(x) = (2x +1)^3 f'(x) = 6(2x + 1)^2 f''(x) = 48x + 24 I need to know when its concave up/down increasing /decreasing and the inflection points I am new to this kind of stuff

  • one year ago
  • one year ago

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  1. rulnick Group Title
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    First derivative is nonnegative for all real x, so f is non-decreasing. Second derivative is everywhere matching the sign of x+1/2, so there is an inflection point at x=-1/2. The function is concave down on x<-1/2 and concave up on x>-1/2.

    • one year ago
  2. Christos Group Title
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    how did you find the -1/2

    • one year ago
  3. rulnick Group Title
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    f''(x)=0 at x=-1/2

    • one year ago
  4. Christos Group Title
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    Ok and something more are my derivative calculations correct? f(x) = (2x +1)^3 f'(x) = 6(2x + 1)^2

    • one year ago
  5. rulnick Group Title
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    Yes, all were perfect!

    • one year ago
  6. Christos Group Title
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    so its not decreasing that means its always increasing? Kinda what's the interval?

    • one year ago
  7. Christos Group Title
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    (0,infinity) increasing?

    • one year ago
  8. rulnick Group Title
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    non-decreasing means increasing or flat. it is flat at the inflection point, increasing everywhere else

    • one year ago
  9. rulnick Group Title
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    so increasing on the entire real line except at -1/2, where it is flat (deriv=0)

    • one year ago
  10. Christos Group Title
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    here it asks me the open interval on which f is increasing what should I put? (-inf,-1/2)U(-1/2,int) ?

    • one year ago
  11. rulnick Group Title
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    yes, very nicely done

    • one year ago
  12. Christos Group Title
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    and decreasing interval*

    • one year ago
  13. rulnick Group Title
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    empty set

    • one year ago
  14. Christos Group Title
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    like I just say "it's not decreasing anywhere" ?

    • one year ago
  15. rulnick Group Title
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    yes

    • one year ago
  16. Christos Group Title
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    Alright, thank you!

    • one year ago
  17. rulnick Group Title
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    welcome

    • one year ago
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