A community for students.
Here's the question you clicked on:
 0 viewing
Christos
 2 years ago
Graphs and functions/derivatives,
Hey can you help me with this?
http://screencast.com/t/MVj3e9Ok2Yg0
Christos
 2 years ago
Graphs and functions/derivatives, Hey can you help me with this? http://screencast.com/t/MVj3e9Ok2Yg0

This Question is Closed

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3\[p(x)=(x+1)^2(2xx^2)\] From there, you can tell that (x+1)=0, x=1 is a zero of p(x) Then factor this \((2xx^2)\) and set the brackets equals zero and find the other 2 zeros

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0Oh so thats the first step

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Yup dw:1369655367345:dw

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Now, differentiate p(x), set it equals to zero to find the maximum and minimum points

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0its 4x^3+6x+2 if I am not mistaken we take x=0 and x=+sqrt(3)/sqrt(2)

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah, set 4x^3+6x+2 equals zero and solve for x

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0yea I solved for x and I got 3 roots x=0 and x=+sqrt(3)/sqrt(2) are my calculations correct??

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Hmm, \[4x^3+6x+2 \\ \\ 2(2x^33x1) \\ \\ 2(x+1)(2x^22x1)\] Factoring \(2x^22x1\) you get \[x=\frac{1}{2} \left(1\sqrt{3}\right)~~~~~,~~~~~\frac{1}{2} \left(1+\sqrt{3}\right)\] These x are the max and min points of the graph, then use these x substitute into \[y=(x+1)^2(2xx^2)\] Find the y's

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0hmm how did you get from line 2 to line 3?

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0http://screencast.com/t/yNU8TQxrMkn this here

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3I used trial an error with calculator, when \[p(1)=2(2(1)^33(1)1)=0\] Then (x+1) is a factor of p(x), then use (x+1) divide \((2x^33x1)\)

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0oh ok lets find the ys

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0I subtitute with 0 or the roots?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Substitute these \(x=\frac{1}{2} \left(1\sqrt{3}\right)~~~~~,~~~~~\frac{1}{2} \left(1+\sqrt{3}\right)\) into \(y=(x+1)^2(2xx^2)\)

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Then that's the coordinates of max and minimum points

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0that was really long to find wasnt it? I tried to find the first one and I found (2 + sqrt(3))/2 which seems to be wrong here

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah It's abit long For \(x=\frac{1}{2} \left(1\sqrt{3}\right)\) or 0.3660, \[y=(x+1)^2(2xx^2)\] \[y=(\frac{1\sqrt3}{2} +1)^2(2(\frac{1\sqrt3}{2})(\frac{1\sqrt3}{2})^2)\] \[y=\frac{96\sqrt{3}}{4}~~or0.348\]

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3(0.3660,0.3481) Then for the other coordinate is (1.366,4.848)

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0Now that we know those coordinates how can we use them?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Yup dw:1369657703814:dw

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3Then the coefficient of highest degree is negative so the graph curves downdw:1369657774047:dw

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3And yeah, zeros are 1 0 and 2, why am I plotting 1 for.

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0hmm are you plotting it to get an estimation of the infliction point?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.3or else you won't know where it changes it's direction

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0I see , is there anything else left for this graph/exersise?

Christos
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks :) I will try to solve some on my own now, if I have any problem can I tell you?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.