AO=12 and BC=25. What is AB?
I think it's 37, but I'm not sure.

- anonymous

AO=12 and BC=25. What is AB?
I think it's 37, but I'm not sure.

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- anonymous

##### 1 Attachment

- whpalmer4

Close...

- whpalmer4

What is the length of the hypotenuse (OB)?

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## More answers

- ParthKohli

|dw:1369717643930:dw|

- ParthKohli

\(OC = OA = 12\) because they are the radii of the same circle.

- ParthKohli

Also, as whpalmer asked, what is the hypotenuse, or \(OB\)? A good start might be noticing that \(OB = OC + CB\).

- whpalmer4

or, just tell us how you came up with 37...then we can see if it is a simple arithmetic error, or how you approached the problem, or whatever...

- KenLJW

OB^2=OA^2+AB^2 if angle A = 90
37^2=12^2+AB^2
other wise you have the sine angle formula

- whpalmer4

I assumed (and ParthKohli too, I'm sure) that because only one intersection point is shown, AB is tangent to the circle, which means that OAB is a right angle.

- KenLJW

imagine A approaching C

- KenLJW

Not enough information given without assumption angle A = pi/2

- KenLJW

When you assume you make a retriceof u and me

- KenLJW

retriceof u and me

- KenLJW

I guess it doesn't like that word

- anonymous

That didn't help at all. You never even told me how to get that answer....

- whpalmer4

you also didn't tell us how you got your answer...

- anonymous

adding them...Duh..

- whpalmer4

adding what, exactly, duh?

- KenLJW

Solve 37^2=12^2+AB^2

- anonymous

The numbers..DUH

- anonymous

And uh...I need to know AB to do that. DUH!!

- anonymous

emily the ans for ab is 35. its a right angle triangle

- anonymous

Now wait...you're going "duh" at everyone else and yet you can't figure out what AB is from the equation 37^2=12^2+AB^2 ???

- KenLJW

I used the Pythagorean theorem
a^2+b^2=h^2
h = sqrt(a^2+b^2)
or in out case b=sqrt(h^2-a^2)

- anonymous

@Kapt_Crazy So I was right? The answer is 35? :)

- KenLJW

Generally you shouldn't just give quantity but show all work so it's easy checked or to show how it's done

- KenLJW

not give

- anonymous

yeah u right
:)

- anonymous

No, you didn't say 35. You said "I think it's 37" which you absurdly arrived at by adding AO and BC together.
Also, 35 is only correct if AB is tangent to the circle at A. But since that information isn't given, then its only an assumption.

- anonymous

qweqwe if it was not a right angle triangle they would give u more info, like one of the angles or sumthing

- anonymous

Oh, thankyou for going back and checking if I said 35. :) @qweqwe123123123123111

- KenLJW

Yes they would have to give 2 angles to solve

- anonymous

The assumption is probably a safe one, @Kapt_Crazy, But UNLESS THAT INFO IS GIVEN EXPLICITLY, it's still just an assumption.
And the number of poorly formed and incomplete problems that are posted here every single day are legion, so there's no good reason to assume that this problem is stated any better than any other.

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