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AO=12 and BC=25. What is AB?
I think it's 37, but I'm not sure.
 10 months ago
 10 months ago
AO=12 and BC=25. What is AB? I think it's 37, but I'm not sure.
 10 months ago
 10 months ago

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whpalmer4Best ResponseYou've already chosen the best response.0
What is the length of the hypotenuse (OB)?
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
dw:1369717643930:dw
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
\(OC = OA = 12\) because they are the radii of the same circle.
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
Also, as whpalmer asked, what is the hypotenuse, or \(OB\)? A good start might be noticing that \(OB = OC + CB\).
 10 months ago

whpalmer4Best ResponseYou've already chosen the best response.0
or, just tell us how you came up with 37...then we can see if it is a simple arithmetic error, or how you approached the problem, or whatever...
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
OB^2=OA^2+AB^2 if angle A = 90 37^2=12^2+AB^2 other wise you have the sine angle formula
 10 months ago

whpalmer4Best ResponseYou've already chosen the best response.0
I assumed (and ParthKohli too, I'm sure) that because only one intersection point is shown, AB is tangent to the circle, which means that OAB is a right angle.
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
imagine A approaching C
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
Not enough information given without assumption angle A = pi/2
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
When you assume you make a retriceof u and me
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
I guess it doesn't like that word
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
That didn't help at all. You never even told me how to get that answer....
 10 months ago

whpalmer4Best ResponseYou've already chosen the best response.0
you also didn't tell us how you got your answer...
 10 months ago

whpalmer4Best ResponseYou've already chosen the best response.0
adding what, exactly, duh?
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
And uh...I need to know AB to do that. DUH!!
 10 months ago

Kapt_CrazyBest ResponseYou've already chosen the best response.1
emily the ans for ab is 35. its a right angle triangle
 10 months ago

qweqwe123123123123111Best ResponseYou've already chosen the best response.0
Now wait...you're going "duh" at everyone else and yet you can't figure out what AB is from the equation 37^2=12^2+AB^2 ???
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
I used the Pythagorean theorem a^2+b^2=h^2 h = sqrt(a^2+b^2) or in out case b=sqrt(h^2a^2)
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
@Kapt_Crazy So I was right? The answer is 35? :)
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
Generally you shouldn't just give quantity but show all work so it's easy checked or to show how it's done
 10 months ago

qweqwe123123123123111Best ResponseYou've already chosen the best response.0
No, you didn't say 35. You said "I think it's 37" which you absurdly arrived at by adding AO and BC together. Also, 35 is only correct if AB is tangent to the circle at A. But since that information isn't given, then its only an assumption.
 10 months ago

Kapt_CrazyBest ResponseYou've already chosen the best response.1
qweqwe if it was not a right angle triangle they would give u more info, like one of the angles or sumthing
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
Oh, thankyou for going back and checking if I said 35. :) @qweqwe123123123123111
 10 months ago

KenLJWBest ResponseYou've already chosen the best response.0
Yes they would have to give 2 angles to solve
 10 months ago

qweqwe123123123123111Best ResponseYou've already chosen the best response.0
The assumption is probably a safe one, @Kapt_Crazy, But UNLESS THAT INFO IS GIVEN EXPLICITLY, it's still just an assumption. And the number of poorly formed and incomplete problems that are posted here every single day are legion, so there's no good reason to assume that this problem is stated any better than any other.
 10 months ago
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