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Emily778

  • one year ago

AO=12 and BC=25. What is AB? I think it's 37, but I'm not sure.

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  1. Emily778
    • one year ago
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  2. whpalmer4
    • one year ago
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    Close...

  3. whpalmer4
    • one year ago
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    What is the length of the hypotenuse (OB)?

  4. ParthKohli
    • one year ago
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    |dw:1369717643930:dw|

  5. ParthKohli
    • one year ago
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    \(OC = OA = 12\) because they are the radii of the same circle.

  6. ParthKohli
    • one year ago
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    Also, as whpalmer asked, what is the hypotenuse, or \(OB\)? A good start might be noticing that \(OB = OC + CB\).

  7. whpalmer4
    • one year ago
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    or, just tell us how you came up with 37...then we can see if it is a simple arithmetic error, or how you approached the problem, or whatever...

  8. KenLJW
    • one year ago
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    OB^2=OA^2+AB^2 if angle A = 90 37^2=12^2+AB^2 other wise you have the sine angle formula

  9. whpalmer4
    • one year ago
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    I assumed (and ParthKohli too, I'm sure) that because only one intersection point is shown, AB is tangent to the circle, which means that OAB is a right angle.

  10. KenLJW
    • one year ago
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    imagine A approaching C

  11. KenLJW
    • one year ago
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    Not enough information given without assumption angle A = pi/2

  12. KenLJW
    • one year ago
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    When you assume you make a retriceof u and me

  13. KenLJW
    • one year ago
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    retriceof u and me

  14. KenLJW
    • one year ago
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    I guess it doesn't like that word

  15. Emily778
    • one year ago
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    That didn't help at all. You never even told me how to get that answer....

  16. whpalmer4
    • one year ago
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    you also didn't tell us how you got your answer...

  17. Emily778
    • one year ago
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    adding them...Duh..

  18. whpalmer4
    • one year ago
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    adding what, exactly, duh?

  19. KenLJW
    • one year ago
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    Solve 37^2=12^2+AB^2

  20. Emily778
    • one year ago
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    The numbers..DUH

  21. Emily778
    • one year ago
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    And uh...I need to know AB to do that. DUH!!

  22. Kapt_Crazy
    • one year ago
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    emily the ans for ab is 35. its a right angle triangle

  23. qweqwe123123123123111
    • one year ago
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    Now wait...you're going "duh" at everyone else and yet you can't figure out what AB is from the equation 37^2=12^2+AB^2 ???

  24. KenLJW
    • one year ago
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    I used the Pythagorean theorem a^2+b^2=h^2 h = sqrt(a^2+b^2) or in out case b=sqrt(h^2-a^2)

  25. Emily778
    • one year ago
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    @Kapt_Crazy So I was right? The answer is 35? :)

  26. KenLJW
    • one year ago
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    Generally you shouldn't just give quantity but show all work so it's easy checked or to show how it's done

  27. KenLJW
    • one year ago
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    not give

  28. Kapt_Crazy
    • one year ago
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    yeah u right :)

  29. qweqwe123123123123111
    • one year ago
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    No, you didn't say 35. You said "I think it's 37" which you absurdly arrived at by adding AO and BC together. Also, 35 is only correct if AB is tangent to the circle at A. But since that information isn't given, then its only an assumption.

  30. Kapt_Crazy
    • one year ago
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    qweqwe if it was not a right angle triangle they would give u more info, like one of the angles or sumthing

  31. Emily778
    • one year ago
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    Oh, thankyou for going back and checking if I said 35. :) @qweqwe123123123123111

  32. KenLJW
    • one year ago
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    Yes they would have to give 2 angles to solve

  33. qweqwe123123123123111
    • one year ago
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    The assumption is probably a safe one, @Kapt_Crazy, But UNLESS THAT INFO IS GIVEN EXPLICITLY, it's still just an assumption. And the number of poorly formed and incomplete problems that are posted here every single day are legion, so there's no good reason to assume that this problem is stated any better than any other.

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