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Emily778

AO=12 and BC=25. What is AB? I think it's 37, but I'm not sure.

  • 10 months ago
  • 10 months ago

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  1. Emily778
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    • 10 months ago
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  2. whpalmer4
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    Close...

    • 10 months ago
  3. whpalmer4
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    What is the length of the hypotenuse (OB)?

    • 10 months ago
  4. ParthKohli
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    |dw:1369717643930:dw|

    • 10 months ago
  5. ParthKohli
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    \(OC = OA = 12\) because they are the radii of the same circle.

    • 10 months ago
  6. ParthKohli
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    Also, as whpalmer asked, what is the hypotenuse, or \(OB\)? A good start might be noticing that \(OB = OC + CB\).

    • 10 months ago
  7. whpalmer4
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    or, just tell us how you came up with 37...then we can see if it is a simple arithmetic error, or how you approached the problem, or whatever...

    • 10 months ago
  8. KenLJW
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    OB^2=OA^2+AB^2 if angle A = 90 37^2=12^2+AB^2 other wise you have the sine angle formula

    • 10 months ago
  9. whpalmer4
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    I assumed (and ParthKohli too, I'm sure) that because only one intersection point is shown, AB is tangent to the circle, which means that OAB is a right angle.

    • 10 months ago
  10. KenLJW
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    imagine A approaching C

    • 10 months ago
  11. KenLJW
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    Not enough information given without assumption angle A = pi/2

    • 10 months ago
  12. KenLJW
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    When you assume you make a retriceof u and me

    • 10 months ago
  13. KenLJW
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    retriceof u and me

    • 10 months ago
  14. KenLJW
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    I guess it doesn't like that word

    • 10 months ago
  15. Emily778
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    That didn't help at all. You never even told me how to get that answer....

    • 10 months ago
  16. whpalmer4
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    you also didn't tell us how you got your answer...

    • 10 months ago
  17. Emily778
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    adding them...Duh..

    • 10 months ago
  18. whpalmer4
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    adding what, exactly, duh?

    • 10 months ago
  19. KenLJW
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    Solve 37^2=12^2+AB^2

    • 10 months ago
  20. Emily778
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    The numbers..DUH

    • 10 months ago
  21. Emily778
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    And uh...I need to know AB to do that. DUH!!

    • 10 months ago
  22. Kapt_Crazy
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    emily the ans for ab is 35. its a right angle triangle

    • 10 months ago
  23. qweqwe123123123123111
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    Now wait...you're going "duh" at everyone else and yet you can't figure out what AB is from the equation 37^2=12^2+AB^2 ???

    • 10 months ago
  24. KenLJW
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    I used the Pythagorean theorem a^2+b^2=h^2 h = sqrt(a^2+b^2) or in out case b=sqrt(h^2-a^2)

    • 10 months ago
  25. Emily778
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    @Kapt_Crazy So I was right? The answer is 35? :)

    • 10 months ago
  26. KenLJW
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    Generally you shouldn't just give quantity but show all work so it's easy checked or to show how it's done

    • 10 months ago
  27. KenLJW
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    not give

    • 10 months ago
  28. Kapt_Crazy
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    yeah u right :)

    • 10 months ago
  29. qweqwe123123123123111
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    No, you didn't say 35. You said "I think it's 37" which you absurdly arrived at by adding AO and BC together. Also, 35 is only correct if AB is tangent to the circle at A. But since that information isn't given, then its only an assumption.

    • 10 months ago
  30. Kapt_Crazy
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    qweqwe if it was not a right angle triangle they would give u more info, like one of the angles or sumthing

    • 10 months ago
  31. Emily778
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    Oh, thankyou for going back and checking if I said 35. :) @qweqwe123123123123111

    • 10 months ago
  32. KenLJW
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    Yes they would have to give 2 angles to solve

    • 10 months ago
  33. qweqwe123123123123111
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    The assumption is probably a safe one, @Kapt_Crazy, But UNLESS THAT INFO IS GIVEN EXPLICITLY, it's still just an assumption. And the number of poorly formed and incomplete problems that are posted here every single day are legion, so there's no good reason to assume that this problem is stated any better than any other.

    • 10 months ago
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