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Emily778
 2 years ago
AO=12 and BC=25. What is AB?
I think it's 37, but I'm not sure.
Emily778
 2 years ago
AO=12 and BC=25. What is AB? I think it's 37, but I'm not sure.

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whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0What is the length of the hypotenuse (OB)?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1369717643930:dw

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0\(OC = OA = 12\) because they are the radii of the same circle.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Also, as whpalmer asked, what is the hypotenuse, or \(OB\)? A good start might be noticing that \(OB = OC + CB\).

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0or, just tell us how you came up with 37...then we can see if it is a simple arithmetic error, or how you approached the problem, or whatever...

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0OB^2=OA^2+AB^2 if angle A = 90 37^2=12^2+AB^2 other wise you have the sine angle formula

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0I assumed (and ParthKohli too, I'm sure) that because only one intersection point is shown, AB is tangent to the circle, which means that OAB is a right angle.

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0Not enough information given without assumption angle A = pi/2

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0When you assume you make a retriceof u and me

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0I guess it doesn't like that word

Emily778
 2 years ago
Best ResponseYou've already chosen the best response.0That didn't help at all. You never even told me how to get that answer....

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0you also didn't tell us how you got your answer...

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0adding what, exactly, duh?

Emily778
 2 years ago
Best ResponseYou've already chosen the best response.0And uh...I need to know AB to do that. DUH!!

Kapt_Crazy
 2 years ago
Best ResponseYou've already chosen the best response.1emily the ans for ab is 35. its a right angle triangle

qweqwe123123123123111
 2 years ago
Best ResponseYou've already chosen the best response.0Now wait...you're going "duh" at everyone else and yet you can't figure out what AB is from the equation 37^2=12^2+AB^2 ???

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0I used the Pythagorean theorem a^2+b^2=h^2 h = sqrt(a^2+b^2) or in out case b=sqrt(h^2a^2)

Emily778
 2 years ago
Best ResponseYou've already chosen the best response.0@Kapt_Crazy So I was right? The answer is 35? :)

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0Generally you shouldn't just give quantity but show all work so it's easy checked or to show how it's done

qweqwe123123123123111
 2 years ago
Best ResponseYou've already chosen the best response.0No, you didn't say 35. You said "I think it's 37" which you absurdly arrived at by adding AO and BC together. Also, 35 is only correct if AB is tangent to the circle at A. But since that information isn't given, then its only an assumption.

Kapt_Crazy
 2 years ago
Best ResponseYou've already chosen the best response.1qweqwe if it was not a right angle triangle they would give u more info, like one of the angles or sumthing

Emily778
 2 years ago
Best ResponseYou've already chosen the best response.0Oh, thankyou for going back and checking if I said 35. :) @qweqwe123123123123111

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0Yes they would have to give 2 angles to solve

qweqwe123123123123111
 2 years ago
Best ResponseYou've already chosen the best response.0The assumption is probably a safe one, @Kapt_Crazy, But UNLESS THAT INFO IS GIVEN EXPLICITLY, it's still just an assumption. And the number of poorly formed and incomplete problems that are posted here every single day are legion, so there's no good reason to assume that this problem is stated any better than any other.
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