## SephI 2 years ago Rectangle A has an area of 4 - x2. Rectangle B has an area of x2 + 2x - 8. In simplest form, what is the ratio of the area of Rectangle A to the area of Rectangle B? Show your work.

1. SephI

@Hero

2. mayankdevnani

$\huge \frac{rect.A}{rect.B}=\frac{4-x^2}{x^2+2x-8}$

3. mayankdevnani

|dw:1369724169976:dw|

4. mayankdevnani

$\huge \frac{4-x^2}{(x+4)(x-2)}$

5. SephI

Thank you! :) I knew it was something like that

6. mayankdevnani

can you solve it??? @SephI

7. SephI

Yes, I would expand 4 - x^2 and cancel the x + 4

8. mayankdevnani

correct

9. mayankdevnani

plz show your work how would you expand $$\large 4-x^2$$

10. mayankdevnani

@SephI

11. SephI

Okay Okay 4 - x^2 -(x - 2)(x + 2) Then my negative xs cancel

12. SephI

Would this be correct? http://prntscr.com/171rge

13. mayankdevnani

@SephI $\huge 4-x^2=2^2-x^2=a^2-b^2=(a+b)(a-b)$ $\huge (2+x)(2-x)$

14. mayankdevnani

$\huge \frac{(2+x)(2-x)}{(x+4)(x-2)}$