SephI
Rectangle A has an area of 4 - x2. Rectangle B has an area of x2 + 2x - 8. In simplest form, what is the ratio of the area of Rectangle A to the area of Rectangle B? Show your work.
Delete
Share
This Question is Closed
SephI
Best Response
You've already chosen the best response.
1
@Hero
mayankdevnani
Best Response
You've already chosen the best response.
1
\[\huge \frac{rect.A}{rect.B}=\frac{4-x^2}{x^2+2x-8}\]
mayankdevnani
Best Response
You've already chosen the best response.
1
|dw:1369724169976:dw|
mayankdevnani
Best Response
You've already chosen the best response.
1
\[\huge \frac{4-x^2}{(x+4)(x-2)}\]
SephI
Best Response
You've already chosen the best response.
1
Thank you! :) I knew it was something like that
mayankdevnani
Best Response
You've already chosen the best response.
1
can you solve it??? @SephI
SephI
Best Response
You've already chosen the best response.
1
Yes, I would expand 4 - x^2 and cancel the x + 4
mayankdevnani
Best Response
You've already chosen the best response.
1
correct
mayankdevnani
Best Response
You've already chosen the best response.
1
plz show your work how would you expand \(\large 4-x^2\)
mayankdevnani
Best Response
You've already chosen the best response.
1
@SephI
SephI
Best Response
You've already chosen the best response.
1
Okay
Okay
4 - x^2
-(x - 2)(x + 2) Then my negative xs cancel
mayankdevnani
Best Response
You've already chosen the best response.
1
@SephI \[\huge 4-x^2=2^2-x^2=a^2-b^2=(a+b)(a-b)\]
\[\huge (2+x)(2-x)\]
mayankdevnani
Best Response
You've already chosen the best response.
1
\[\huge \frac{(2+x)(2-x)}{(x+4)(x-2)}\]