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Find the value of x.

Mathematics
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1 Attachment
:P :P :P
Not the greatest picture in the world.

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Other answers:

not hd, huh
What do you think it is?
but it looks cool, white crystals, me and my uncle went crystal picking and we also found some cool ones... but mine were purple
i have not idea, a crystal lol
they're a pale pink, actually.
rock
ok emily this is another simple one. x is the radius of the circle right.
yep
what do I do?
is the 12 the length of the whole line or just up the the point where the line of 9 meets it
I think it's just where the 9 meets
|dw:1369728122034:dw|
u see the kind of dotted line right. that makes ur triangle and the raduis. so the ans for the dotted line is = x
do u understand
yes
so what ans did u get
15.
yeah u right
ok :) thanks.
What about this one?
1 Attachment
The answer to the first problem is not 15.
i think it's 40.
do u need to calculate the angle
prove it.
lol what a challenge
It's an easy one, actually. Since the "9" line is right to the "12" line, you know that it also bisects the "12". Which means that you have a right triangle with a long leg of 9, a short leg of 6, and the hypotenuse of that triangle would be the radius of the circle - which also just happens to be what "x" is.
those angles well be equal because
so it's 12?
|dw:1369728687803:dw|
|dw:1369728693846:dw|
|dw:1369728808616:dw|
is the first one actually 15?
and if the lines are the same length rhss then the angles are the sme
is the entire line 12, or is half the line 12?
- "is the first one actually 15?" Which part of "The answer to the first problem is not 15" is giving you problems? Look at my diagram and all will be clear - IF you THINK about it.
qweqwe is right if the line full length is 12. but if it was the full length the would have centerewd the 12 and not had it ofcentered
off centered
it goes out from the radius perpendicularly, it cant be off-center
|dw:1369729065516:dw|
|dw:1369729144486:dw|
i still believe the ans is 15
Yes, I see what you're saying, and you may have a valid point. And if the picture is drawn to scale, then your argument is further supported. So if the long leg is 12, then the radius is indeed a nice, neat 15.
yeah else it would be 10. sumthing
sqrt117 36+81=117
Yeah, a far less than neat 10.82 or so. :-)
are there any details aabout the length AB and CD are they given equal in question
I'm gonna go with Kapt_Crazy on this one and say that the radius IS 15 for the first problem, based on the offset "12". But it sure would help if the producers of these diagrams would make things unambiguous for the viewers. On the last problem a leg was found based on the assumption that a particular line was tangent, without the problem giving any clues that it was. And as for the second problem, the 2 chords have hash marks which means they're congruent. If the 2 chords are congruent, then so are the angles they subtend, so x=40
  • phi
**. If the 2 chords are congruent, then so are the angles they subtend, so x=40 this follows from the two triangles being congruent by side-side-side: (radius, radius, = chord). therefore by corresponding parts of congruent triangles, the central angles are congruent.
Thanks y'all

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