A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Find the value of x.
anonymous
 3 years ago
Find the value of x.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Not the greatest picture in the world.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you think it is?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but it looks cool, white crystals, me and my uncle went crystal picking and we also found some cool ones... but mine were purple

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have not idea, a crystal lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0they're a pale pink, actually.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok emily this is another simple one. x is the radius of the circle right.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the 12 the length of the whole line or just up the the point where the line of 9 meets it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think it's just where the 9 meets

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369728122034:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u see the kind of dotted line right. that makes ur triangle and the raduis. so the ans for the dotted line is = x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what ans did u get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The answer to the first problem is not 15.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do u need to calculate the angle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's an easy one, actually. Since the "9" line is right to the "12" line, you know that it also bisects the "12". Which means that you have a right triangle with a long leg of 9, a short leg of 6, and the hypotenuse of that triangle would be the radius of the circle  which also just happens to be what "x" is.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0those angles well be equal because

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369728687803:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369728693846:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369728808616:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the first one actually 15?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and if the lines are the same length rhss then the angles are the sme

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the entire line 12, or is half the line 12?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0 "is the first one actually 15?" Which part of "The answer to the first problem is not 15" is giving you problems? Look at my diagram and all will be clear  IF you THINK about it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0qweqwe is right if the line full length is 12. but if it was the full length the would have centerewd the 12 and not had it ofcentered

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it goes out from the radius perpendicularly, it cant be offcenter

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369729065516:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1369729144486:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i still believe the ans is 15

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I see what you're saying, and you may have a valid point. And if the picture is drawn to scale, then your argument is further supported. So if the long leg is 12, then the radius is indeed a nice, neat 15.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah else it would be 10. sumthing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, a far less than neat 10.82 or so. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are there any details aabout the length AB and CD are they given equal in question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm gonna go with Kapt_Crazy on this one and say that the radius IS 15 for the first problem, based on the offset "12". But it sure would help if the producers of these diagrams would make things unambiguous for the viewers. On the last problem a leg was found based on the assumption that a particular line was tangent, without the problem giving any clues that it was. And as for the second problem, the 2 chords have hash marks which means they're congruent. If the 2 chords are congruent, then so are the angles they subtend, so x=40

phi
 3 years ago
Best ResponseYou've already chosen the best response.1**. If the 2 chords are congruent, then so are the angles they subtend, so x=40 this follows from the two triangles being congruent by sidesideside: (radius, radius, = chord). therefore by corresponding parts of congruent triangles, the central angles are congruent.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.