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allie_bear22

  • one year ago

check my answer! Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)

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  1. allie_bear22
    • one year ago
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  2. allie_bear22
    • one year ago
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    i got 1/4(x+2)

  3. whpalmer4
    • one year ago
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    That's correct.

  4. allie_bear22
    • one year ago
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    thnk u

  5. Luigi0210
    • one year ago
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    You sure it's not 4/x+2?

  6. allie_bear22
    • one year ago
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    hmm thats not an option but 4x(x+2) is

  7. Luigi0210
    • one year ago
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    \[\frac{ x }{ x+5 }=\frac{ 4*(x) }{ (x+2)*(x+5) }\]

  8. allie_bear22
    • one year ago
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    is it x/x+2?

  9. Luigi0210
    • one year ago
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    Hm, actually nevermind sorry.

  10. allie_bear22
    • one year ago
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    lol okay so the other guy was right?

  11. Luigi0210
    • one year ago
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    I'm not 100% sure but I'll have to take his word for it

  12. allie_bear22
    • one year ago
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    ok thnk u

  13. whpalmer4
    • one year ago
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    Area of the smaller rectangle = \(x(x+5)\) Area of the larger rectangle = \(4x(x^2+7x+10) = 4x(x+2)(x+5)\) Ratio of areas (smaller to larger) = \[\frac{x(x+5)}{4x(x+2)(x+5)} = \frac{x}{4x(x+2)} = \frac{1}{4(x+2)}\]

  14. whpalmer4
    • one year ago
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    @Luigi0210 was taking the ratio of the sides of the small rectangle and comparing it to the ratio of the sides of the large rectangle, which is not what problem asks....that would be the right setup for determining if the rectangles were proportional in shape, however.

  15. whpalmer4
    • one year ago
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    Gotta watch out, multiple-choice questions often have wrong answers that represent results you could get if you set up the problem incorrectly. Don't assume the answer is right just because it is one of the choices :-)

  16. Luigi0210
    • one year ago
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    Yup, I realized that right when I lef

  17. Luigi0210
    • one year ago
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    *left

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