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anonymous
 3 years ago
check my answer!
Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)
anonymous
 3 years ago
check my answer! Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)

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Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0You sure it's not 4/x+2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm thats not an option but 4x(x+2) is

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x }{ x+5 }=\frac{ 4*(x) }{ (x+2)*(x+5) }\]

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Hm, actually nevermind sorry.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol okay so the other guy was right?

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not 100% sure but I'll have to take his word for it

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1Area of the smaller rectangle = \(x(x+5)\) Area of the larger rectangle = \(4x(x^2+7x+10) = 4x(x+2)(x+5)\) Ratio of areas (smaller to larger) = \[\frac{x(x+5)}{4x(x+2)(x+5)} = \frac{x}{4x(x+2)} = \frac{1}{4(x+2)}\]

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1@Luigi0210 was taking the ratio of the sides of the small rectangle and comparing it to the ratio of the sides of the large rectangle, which is not what problem asks....that would be the right setup for determining if the rectangles were proportional in shape, however.

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1Gotta watch out, multiplechoice questions often have wrong answers that represent results you could get if you set up the problem incorrectly. Don't assume the answer is right just because it is one of the choices :)

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Yup, I realized that right when I lef
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