## allie_bear22 Group Title check my answer! Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale) one year ago one year ago

1. allie_bear22 Group Title

2. allie_bear22 Group Title

i got 1/4(x+2)

3. whpalmer4 Group Title

That's correct.

4. allie_bear22 Group Title

thnk u

5. Luigi0210 Group Title

You sure it's not 4/x+2?

6. allie_bear22 Group Title

hmm thats not an option but 4x(x+2) is

7. Luigi0210 Group Title

$\frac{ x }{ x+5 }=\frac{ 4*(x) }{ (x+2)*(x+5) }$

8. allie_bear22 Group Title

is it x/x+2?

9. Luigi0210 Group Title

Hm, actually nevermind sorry.

10. allie_bear22 Group Title

lol okay so the other guy was right?

11. Luigi0210 Group Title

I'm not 100% sure but I'll have to take his word for it

12. allie_bear22 Group Title

ok thnk u

13. whpalmer4 Group Title

Area of the smaller rectangle = $$x(x+5)$$ Area of the larger rectangle = $$4x(x^2+7x+10) = 4x(x+2)(x+5)$$ Ratio of areas (smaller to larger) = $\frac{x(x+5)}{4x(x+2)(x+5)} = \frac{x}{4x(x+2)} = \frac{1}{4(x+2)}$

14. whpalmer4 Group Title

@Luigi0210 was taking the ratio of the sides of the small rectangle and comparing it to the ratio of the sides of the large rectangle, which is not what problem asks....that would be the right setup for determining if the rectangles were proportional in shape, however.

15. whpalmer4 Group Title

Gotta watch out, multiple-choice questions often have wrong answers that represent results you could get if you set up the problem incorrectly. Don't assume the answer is right just because it is one of the choices :-)

16. Luigi0210 Group Title

Yup, I realized that right when I lef

17. Luigi0210 Group Title

*left