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allie_bear22

check my answer! Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)

  • 11 months ago
  • 11 months ago

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  1. allie_bear22
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    • 11 months ago
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  2. allie_bear22
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    i got 1/4(x+2)

    • 11 months ago
  3. whpalmer4
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    That's correct.

    • 11 months ago
  4. allie_bear22
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    thnk u

    • 11 months ago
  5. Luigi0210
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    You sure it's not 4/x+2?

    • 11 months ago
  6. allie_bear22
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    hmm thats not an option but 4x(x+2) is

    • 11 months ago
  7. Luigi0210
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    \[\frac{ x }{ x+5 }=\frac{ 4*(x) }{ (x+2)*(x+5) }\]

    • 11 months ago
  8. allie_bear22
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    is it x/x+2?

    • 11 months ago
  9. Luigi0210
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    Hm, actually nevermind sorry.

    • 11 months ago
  10. allie_bear22
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    lol okay so the other guy was right?

    • 11 months ago
  11. Luigi0210
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    I'm not 100% sure but I'll have to take his word for it

    • 11 months ago
  12. allie_bear22
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    ok thnk u

    • 11 months ago
  13. whpalmer4
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    Area of the smaller rectangle = \(x(x+5)\) Area of the larger rectangle = \(4x(x^2+7x+10) = 4x(x+2)(x+5)\) Ratio of areas (smaller to larger) = \[\frac{x(x+5)}{4x(x+2)(x+5)} = \frac{x}{4x(x+2)} = \frac{1}{4(x+2)}\]

    • 11 months ago
  14. whpalmer4
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    @Luigi0210 was taking the ratio of the sides of the small rectangle and comparing it to the ratio of the sides of the large rectangle, which is not what problem asks....that would be the right setup for determining if the rectangles were proportional in shape, however.

    • 11 months ago
  15. whpalmer4
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    Gotta watch out, multiple-choice questions often have wrong answers that represent results you could get if you set up the problem incorrectly. Don't assume the answer is right just because it is one of the choices :-)

    • 11 months ago
  16. Luigi0210
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    Yup, I realized that right when I lef

    • 11 months ago
  17. Luigi0210
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    *left

    • 11 months ago
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