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allie_bear22
Group Title
check my answer!
Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)
 one year ago
 one year ago
allie_bear22 Group Title
check my answer! Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)
 one year ago
 one year ago

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allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
i got 1/4(x+2)
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
That's correct.
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
thnk u
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
You sure it's not 4/x+2?
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
hmm thats not an option but 4x(x+2) is
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ x+5 }=\frac{ 4*(x) }{ (x+2)*(x+5) }\]
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
is it x/x+2?
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
Hm, actually nevermind sorry.
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
lol okay so the other guy was right?
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
I'm not 100% sure but I'll have to take his word for it
 one year ago

allie_bear22 Group TitleBest ResponseYou've already chosen the best response.1
ok thnk u
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Area of the smaller rectangle = \(x(x+5)\) Area of the larger rectangle = \(4x(x^2+7x+10) = 4x(x+2)(x+5)\) Ratio of areas (smaller to larger) = \[\frac{x(x+5)}{4x(x+2)(x+5)} = \frac{x}{4x(x+2)} = \frac{1}{4(x+2)}\]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
@Luigi0210 was taking the ratio of the sides of the small rectangle and comparing it to the ratio of the sides of the large rectangle, which is not what problem asks....that would be the right setup for determining if the rectangles were proportional in shape, however.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Gotta watch out, multiplechoice questions often have wrong answers that represent results you could get if you set up the problem incorrectly. Don't assume the answer is right just because it is one of the choices :)
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
Yup, I realized that right when I lef
 one year ago
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