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satellite73Best ResponseYou've already chosen the best response.2
the square root of 16 is 4 is a start
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
and half of 10 is 5, giving you \[\sqrt{16g^{10}}=4g^5\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
man they really reach for these word problems, don't they?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
perimeter is \[\sqrt{13}+\sqrt{13}+7\sqrt{13}+7\sqrt{13}\] add to get \(16\sqrt{13}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
\(\sqrt{20}+\sqrt{40}\sqrt{5}\) you have to write the first two in simplest radical form do you know how to do that?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
ok look to factor the number inside the radical as a perfect square, times something for example \(20=4\times 5\) and \(4\) is a square you get \[\sqrt{20}=\sqrt{4\times 5}=\sqrt{4}\sqrt{5}=2\sqrt{5}\] you don't need to write all those steps, that is only my explanation
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
see if you can try that with \(\sqrt{45}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
if you get stuck let me know, but it is not too bad for \(45\)
 10 months ago

tmybbyBest ResponseYou've already chosen the best response.1
\[\sqrt{45}=\sqrt{9x5}=\sqrt{9}\sqrt{5}\]?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
so finish with \(\sqrt{9}\sqrt{5}=3\sqrt{5}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
now the whole problem is a matter of combining like terms for \[2\sqrt{5}+3\sqrt{5}\sqrt{5}\] which is identical to \[2+31\] really, just stick a \(\sqrt{5}\) next to the answer
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
how about the last one \[9^{\frac{1}{3}}\times 81^{\frac{1}{3}}\]? you got that?
 10 months ago

tmybbyBest ResponseYou've already chosen the best response.1
I got 9 for the last one
 10 months ago

tmybbyBest ResponseYou've already chosen the best response.1
could you still help me?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
for a rational exponent, the power is the numerator and the root is the denominator
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
your exponent will be negative, since the variable is in the denominator
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
should get \[\large 8x^{\frac{15}{7}}\] yes, C
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
for the second one i can't really read the exponents
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
is the exponent in the numerator a 3 or an 8 ?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
oh, then \(\sqrt[3]{x^3}=x\) and you have \[\frac{x}{\sqrt[5]{x^2}}\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
you can write this as \[\frac{x}{x^{\frac{2}{5}}}\] and then subtract the exponents
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
\[\large x^{1\frac{2}{5}}=x^{\frac{3}{5}}\]
 10 months ago

tmybbyBest ResponseYou've already chosen the best response.1
i have 3 more problems /:
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
i am ready if you are
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
just like the previous one, multiply top and bottom by \(\sqrt{2}+\sqrt{5}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
\[\frac{\sqrt{2}+\sqrt{5}}{\sqrt2\sqrt5}\times\frac{\sqrt{2}+\sqrt{5}}{\sqrt2+\sqrt5} \]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
\[\frac{2+2\sqrt{10}+5}{25}\] \[\frac{7+2\sqrt{10}}{3}\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
any ideas for this one?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
one think should be ok, that \[\large (a^{3})^{\frac{2}{3}}=a^{3\times \frac{2}{3}}=a^2\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
for \(8^{\frac{2}{3}}\) you have an exponent with a a) three in the deminator b) 2 in the numerator and c) a minus sign they mean a) take the cube root b) square c) take the reciprocal
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
therefore you get the cubed root of 8 is 2 2 squared is 4 the reciprocal of 4 is \(\frac{1}{4}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
final answer is therefor \[\frac{x^2}{4}\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
that is an easier one multiply top and bottom by \(\sqrt3\) to get \[\frac{5\sqrt{3}+\sqrt{6}}{3}\]
 10 months ago

satellite73Best ResponseYou've already chosen the best response.2
typo there ! \[\frac{5\sqrt{3}\sqrt{6}}{3}\]
 10 months ago

tmybbyBest ResponseYou've already chosen the best response.1
Thank you so much I really appreciate it!!
 10 months ago
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