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This Question is Closed

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0Where Lenz's law is applied, when a magnet passes through a copper pipe, current is induced, and a magnetic field is created to oppose the magnet that created it.However, in a open circuit I = 0, thus there is no magnetic field, thus the magnet passes through it with no resistance. The only resistance acting on the magnet is friction?

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0Im guessing since a copper pipe is closed... Current can flow. And it cylinder shaped... Lenz law is effective and eddy current are generated to oppose the magnet. But in a coil that's circuit is open current can't flow, thus there is no magnetic field.

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0@VincentLyon.Fr @Jemurray3 @ghazi @Shane_B @TuringTest

Eleven17
 one year ago
Best ResponseYou've already chosen the best response.0All you have to know that is that current will flow at all. If it down then there must be a "closed" circuit.

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0@Eleven17 so, a copper pipe is indeed a "closed" circuit. But if it was "open" like a coil in a "opened" circuit there will be no flow of current.

ghazi
 one year ago
Best ResponseYou've already chosen the best response.1first of all i would suggest you to think of circuit, what exactly circuit means then i am sure you wont think of copper pipe as circuit anymore :), if you think of it as a circuit can you state how?? it is not a circuit , current will flow from a low potential end to the high potential end across the pipe but , if you just think of pipe then its not a circuit. by the way its good to know you wonder about things and never let this thing go, keep wondering keep finding :D dw:1369860572793:dw current will flow across the surface from the terminals of potential difference

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0@ghazi thanks for the encouragement. But I think you did not understand my point... If we have coil like soi in a "closed" circuit: dw:1369948755802:dw No, if a magnet passes through that coil, lenz law will not be in effect. Because, I = 0, there is not magnetic field to oppose the magnet. Now in a copper pipe, if you drop a magnet through it, the magnet slows down because of the induced current's that created a magnet field opposing the magnet: dw:1369948928253:dw

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0sorry for using he "term" circuit it was wrongly used indeed! My question is, why does currrent flow through a copper pipe? Is it considered to be like a "cosed" loop? A coil in a circuit and a magnet passing through it has no current flowing because the circuit is "opened".

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0I think I've figured it out! Copper pipe is like a HUGE thick loop! so THERE INDEED is a path for current to flow! However, a loop that is opened will not have current flowing through it because of it not being closed!

Visionary01
 one year ago
Best ResponseYou've already chosen the best response.0Um... Am I right? @ghazi @Eleven17 ?
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