Is a copper pipe consider to be a "closed" circuit?

Is a copper pipe consider to be a "closed" circuit?

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Where Lenz's law is applied, when a magnet passes through a copper pipe, current is induced, and a magnetic field is created to oppose the magnet that created it.However, in a open circuit I = 0, thus there is no magnetic field, thus the magnet passes through it with no resistance. The only resistance acting on the magnet is friction?

Im guessing since a copper pipe is closed... Current can flow. And it cylinder shaped... Lenz law is effective and eddy current are generated to oppose the magnet. But in a coil that's circuit is open current can't flow, thus there is no magnetic field.

@Vincent-Lyon.Fr @Jemurray3 @ghazi @Shane_B @TuringTest

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