Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Visionary01
Group Title
Is a copper pipe consider to be a "closed" circuit?
 one year ago
 one year ago
Visionary01 Group Title
Is a copper pipe consider to be a "closed" circuit?
 one year ago
 one year ago

This Question is Closed

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
Where Lenz's law is applied, when a magnet passes through a copper pipe, current is induced, and a magnetic field is created to oppose the magnet that created it.However, in a open circuit I = 0, thus there is no magnetic field, thus the magnet passes through it with no resistance. The only resistance acting on the magnet is friction?
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
Im guessing since a copper pipe is closed... Current can flow. And it cylinder shaped... Lenz law is effective and eddy current are generated to oppose the magnet. But in a coil that's circuit is open current can't flow, thus there is no magnetic field.
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr @Jemurray3 @ghazi @Shane_B @TuringTest
 one year ago

Eleven17 Group TitleBest ResponseYou've already chosen the best response.0
All you have to know that is that current will flow at all. If it down then there must be a "closed" circuit.
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
@Eleven17 so, a copper pipe is indeed a "closed" circuit. But if it was "open" like a coil in a "opened" circuit there will be no flow of current.
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
first of all i would suggest you to think of circuit, what exactly circuit means then i am sure you wont think of copper pipe as circuit anymore :), if you think of it as a circuit can you state how?? it is not a circuit , current will flow from a low potential end to the high potential end across the pipe but , if you just think of pipe then its not a circuit. by the way its good to know you wonder about things and never let this thing go, keep wondering keep finding :D dw:1369860572793:dw current will flow across the surface from the terminals of potential difference
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
@ghazi thanks for the encouragement. But I think you did not understand my point... If we have coil like soi in a "closed" circuit: dw:1369948755802:dw No, if a magnet passes through that coil, lenz law will not be in effect. Because, I = 0, there is not magnetic field to oppose the magnet. Now in a copper pipe, if you drop a magnet through it, the magnet slows down because of the induced current's that created a magnet field opposing the magnet: dw:1369948928253:dw
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
sorry for using he "term" circuit it was wrongly used indeed! My question is, why does currrent flow through a copper pipe? Is it considered to be like a "cosed" loop? A coil in a circuit and a magnet passing through it has no current flowing because the circuit is "opened".
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
I think I've figured it out! Copper pipe is like a HUGE thick loop! so THERE INDEED is a path for current to flow! However, a loop that is opened will not have current flowing through it because of it not being closed!
 one year ago

Visionary01 Group TitleBest ResponseYou've already chosen the best response.0
Um... Am I right? @ghazi @Eleven17 ?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.