Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Emily778 Group Title

Find the measure of angle BAC.

  • one year ago
  • one year ago

  • This Question is Closed
  1. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  2. FutureMathProfessor Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    It will be 1/2 of the angle that's listed at the center. So: 57/2 = 28.5 degrees

    • one year ago
  3. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Whattabout this one? Find angle BAC

    • one year ago
    1 Attachment
  4. FutureMathProfessor Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The supplement of angle AOB which is 66 degrees (AOC) is 114 degrees. 114/2 = 57 degrees

    • one year ago
  5. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks. :) one more?

    • one year ago
  6. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    m<R=22 degrees. Find m<O.

    • one year ago
    1 Attachment
  7. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @FutureMathProfessor

    • one year ago
  8. FutureMathProfessor Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    22x2=44 degrees

    • one year ago
  9. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    THANKYOU SO MUCH

    • one year ago
  10. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Can you help me on 5 more? :D

    • one year ago
  11. FutureMathProfessor Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Is it getting easier? :D Just know that the angle from the center will be twice the angle from the other side

    • one year ago
  12. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    1.) m<S=36 degrees, mRS=118 degrees, and RU is tangent to the circle at R. Find m<U.

    • one year ago
    1 Attachment
  13. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Lol. I dunno, you tell me. :D

    • one year ago
  14. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2.) mDE=128 degrees and mBC= 63 degrees. Find m<4

    • one year ago
  15. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @FutureMathProfessor

    • one year ago
  16. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2.) FORGOT PICTURE..

    • one year ago
  17. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  18. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Hello? @FutureMathProfessor

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.