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anonymous
 3 years ago
Who wants an easy medal!
anonymous
 3 years ago
Who wants an easy medal!

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Loser66
 3 years ago
Best ResponseYou've already chosen the best response.0the question is unclear. and I give you medal for free. heheh, I don't know how to solve

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Trig identities,\[\cos^2\theta1=\sin^2\theta\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it wants me to simpify

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Why not? and that is simplified

GoldPhenoix
 3 years ago
Best ResponseYou've already chosen the best response.0\[\cos^2(aht^2e)\]

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Oh I see my mistake.. again

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0yea \[\cos^2\theta \] sorry about that :/

Loser66
 3 years ago
Best ResponseYou've already chosen the best response.0@lala2 he gave you the formula, you replace and figure out the answer. 1= sin^2 +cos^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what about this one sec(theta)sin(theta)cot(theta)

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sec \theta*\sin \theta*\cot \theta=\frac{ 1 }{ \cos \theta }*\sin \theta*\frac{ \cos \theta }{ \sin \theta }=\frac{ \sin \theta }{ \cos \theta }*\frac{ \cos \theta }{ \sin }\]
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