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lala2

  • 2 years ago

Who wants an easy medal!

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  1. lala2
    • 2 years ago
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    cos^2(theta) -1

  2. lala2
    • 2 years ago
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    @Zarkon

  3. Loser66
    • 2 years ago
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    the question is unclear. and I give you medal for free. heheh, I don't know how to solve

  4. lala2
    • 2 years ago
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    oh thanks!

  5. lala2
    • 2 years ago
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    oh thanks!

  6. Luigi0210
    • 2 years ago
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    Trig identities,\[\cos^2\theta-1=\sin^2\theta\]

  7. Loser66
    • 2 years ago
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    nope

  8. lala2
    • 2 years ago
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    it wants me to simpify

  9. Luigi0210
    • 2 years ago
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    Why not? and that is simplified

  10. GoldPhenoix
    • 2 years ago
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    \[-\cos^2(aht^2e)\]

  11. Luigi0210
    • 2 years ago
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    Oh I see my mistake.. again

  12. Luigi0210
    • 2 years ago
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    yea \[-\cos^2\theta \] sorry about that :/

  13. Loser66
    • 2 years ago
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    redo

  14. Loser66
    • 2 years ago
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    @Luigi0210

  15. Loser66
    • 2 years ago
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    @lala2 he gave you the formula, you replace and figure out the answer. 1= sin^2 +cos^2

  16. lala2
    • 2 years ago
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    what about this one sec(theta)sin(theta)cot(theta)

  17. Luigi0210
    • 2 years ago
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    \[\sec \theta*\sin \theta*\cot \theta=\frac{ 1 }{ \cos \theta }*\sin \theta*\frac{ \cos \theta }{ \sin \theta }=\frac{ \sin \theta }{ \cos \theta }*\frac{ \cos \theta }{ \sin }\]

  18. Luigi0210
    • 2 years ago
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    *sin(theta)

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