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lala2 Group TitleBest ResponseYou've already chosen the best response.1
cos^2(theta) 1
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
the question is unclear. and I give you medal for free. heheh, I don't know how to solve
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
Trig identities,\[\cos^2\theta1=\sin^2\theta\]
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.1
it wants me to simpify
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
Why not? and that is simplified
 one year ago

GoldPhenoix Group TitleBest ResponseYou've already chosen the best response.0
\[\cos^2(aht^2e)\]
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
Oh I see my mistake.. again
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
yea \[\cos^2\theta \] sorry about that :/
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
@Luigi0210
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
@lala2 he gave you the formula, you replace and figure out the answer. 1= sin^2 +cos^2
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.1
what about this one sec(theta)sin(theta)cot(theta)
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
\[\sec \theta*\sin \theta*\cot \theta=\frac{ 1 }{ \cos \theta }*\sin \theta*\frac{ \cos \theta }{ \sin \theta }=\frac{ \sin \theta }{ \cos \theta }*\frac{ \cos \theta }{ \sin }\]
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.0
*sin(theta)
 one year ago
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