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GoldPhenoix
 one year ago
Best ResponseYou've already chosen the best response.0Hello. Do you need help?

lala2
 one year ago
Best ResponseYou've already chosen the best response.0use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^1 sqrt 3

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0look on the unit circle to find where the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0oops sorry, should be second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)

lala2
 one year ago
Best ResponseYou've already chosen the best response.0what does that look like?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you will find it on the last page of the attached cheat sheet

lala2
 one year ago
Best ResponseYou've already chosen the best response.0dw:1369791474788:dwif you have a unit circle like this

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0unit blob? look at the cheat sheet i sent, on the last page you see the unit circle

lala2
 one year ago
Best ResponseYou've already chosen the best response.0ok ... but where exaclty is it?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so \[\tan(\frac{\pi}{3})=\sqrt3\]

lala2
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand all of the symbols

lala2
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 what do i do next

lala2
 one year ago
Best ResponseYou've already chosen the best response.0but it says to use 30 60 90 triangle

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0oh you are working in degrees. not problem since \(\tan(60)=\sqrt3\) you know \(\tan^{1}(\sqrt3)=60\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0dw:1369791928159:dw

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0tangent is opposite over adjacent is \(\sqrt3\)

lala2
 one year ago
Best ResponseYou've already chosen the best response.0what about cos^1 (sqrt3)/2
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