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GoldPhenoix
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Hello. Do you need help?
lala2
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use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^-1 sqrt 3
lala2
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|dw:1369790876325:dw|
lala2
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can someone help
lala2
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@onedirection822
lala2
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@arykk
anonymous
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look on the unit circle to find where the second coordinate is \(-\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)
anonymous
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oops sorry, should be
second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)
lala2
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what does that look like?
anonymous
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you will find it on the last page of the attached cheat sheet
lala2
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|dw:1369791474788:dw|if you have a unit circle like this
anonymous
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unit blob?
look at the cheat sheet i sent, on the last page you see the unit circle
lala2
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haah! thats mean!
lala2
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ok ... but where exaclty is it?
anonymous
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look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so
\[\tan(\frac{\pi}{3})=\sqrt3\]
lala2
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i dont understand all of the symbols
lala2
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@satellite73 right here
lala2
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@satellite73 what do i do next
anonymous
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that is all
lala2
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but it says to use 30 60 90 triangle
anonymous
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oh you are working in degrees. not problem
since \(\tan(60)=\sqrt3\) you know \(\tan^{-1}(\sqrt3)=60\)
anonymous
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|dw:1369791928159:dw|
anonymous
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tangent is opposite over adjacent is \(\sqrt3\)
lala2
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what about cos^-1 (sqrt3)/2
lala2
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@satellite73