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Hello. Do you need help?
use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^-1 sqrt 3
|dw:1369790876325:dw|

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Other answers:

can someone help
look on the unit circle to find where the second coordinate is \(-\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)
oops sorry, should be second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)
what does that look like?
you will find it on the last page of the attached cheat sheet
|dw:1369791474788:dw|if you have a unit circle like this
unit blob? look at the cheat sheet i sent, on the last page you see the unit circle
haah! thats mean!
ok ... but where exaclty is it?
look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so \[\tan(\frac{\pi}{3})=\sqrt3\]
i dont understand all of the symbols
@satellite73 right here
1 Attachment
@satellite73 what do i do next
that is all
but it says to use 30 60 90 triangle
oh you are working in degrees. not problem since \(\tan(60)=\sqrt3\) you know \(\tan^{-1}(\sqrt3)=60\)
|dw:1369791928159:dw|
tangent is opposite over adjacent is \(\sqrt3\)
what about cos^-1 (sqrt3)/2

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