## lala2 Group Title Hello? one year ago one year ago

1. GoldPhenoix Group Title

Hello. Do you need help?

2. lala2 Group Title

use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^-1 sqrt 3

3. lala2 Group Title

|dw:1369790876325:dw|

4. lala2 Group Title

can someone help

5. lala2 Group Title

@onedirection822

6. lala2 Group Title

@arykk

7. satellite73 Group Title

look on the unit circle to find where the second coordinate is $$-\frac{\sqrt{3}}{2}$$ and the first coordinate is $$\frac{1}{2}$$

8. satellite73 Group Title

oops sorry, should be second coordinate is $$\frac{\sqrt{3}}{2}$$ and first coordinate is $$\frac{1}{2}$$

9. lala2 Group Title

what does that look like?

10. satellite73 Group Title

you will find it on the last page of the attached cheat sheet

11. lala2 Group Title

|dw:1369791474788:dw|if you have a unit circle like this

12. satellite73 Group Title

unit blob? look at the cheat sheet i sent, on the last page you see the unit circle

13. lala2 Group Title

haah! thats mean!

14. lala2 Group Title

ok ... but where exaclty is it?

15. satellite73 Group Title

look at the angle of $$\frac{\pi}{3}$$ and you will see that the second coordinate is $$\frac{\sqrt{3}}{2}$$ and the first coordinate is $$\frac{1}{2}$$ and so $\tan(\frac{\pi}{3})=\sqrt3$

16. lala2 Group Title

i dont understand all of the symbols

17. lala2 Group Title

@satellite73 right here

18. lala2 Group Title

@satellite73 what do i do next

19. satellite73 Group Title

that is all

20. lala2 Group Title

but it says to use 30 60 90 triangle

21. satellite73 Group Title

oh you are working in degrees. not problem since $$\tan(60)=\sqrt3$$ you know $$\tan^{-1}(\sqrt3)=60$$

22. satellite73 Group Title

|dw:1369791928159:dw|

23. satellite73 Group Title

tangent is opposite over adjacent is $$\sqrt3$$

24. lala2 Group Title