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GoldPhenoixBest ResponseYou've already chosen the best response.0
Hello. Do you need help?
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^1 sqrt 3
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
look on the unit circle to find where the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
oops sorry, should be second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
what does that look like?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
you will find it on the last page of the attached cheat sheet
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
dw:1369791474788:dwif you have a unit circle like this
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
unit blob? look at the cheat sheet i sent, on the last page you see the unit circle
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
ok ... but where exaclty is it?
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so \[\tan(\frac{\pi}{3})=\sqrt3\]
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
i dont understand all of the symbols
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
@satellite73 right here
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
@satellite73 what do i do next
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
but it says to use 30 60 90 triangle
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
oh you are working in degrees. not problem since \(\tan(60)=\sqrt3\) you know \(\tan^{1}(\sqrt3)=60\)
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
dw:1369791928159:dw
 10 months ago

satellite73Best ResponseYou've already chosen the best response.0
tangent is opposite over adjacent is \(\sqrt3\)
 10 months ago

lala2Best ResponseYou've already chosen the best response.0
what about cos^1 (sqrt3)/2
 10 months ago
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