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lala2
 2 years ago
Hello?
lala2
 2 years ago
Hello?

This Question is Closed

GoldPhenoix
 2 years ago
Best ResponseYou've already chosen the best response.0Hello. Do you need help?

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^1 sqrt 3

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0look on the unit circle to find where the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0oops sorry, should be second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0what does that look like?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you will find it on the last page of the attached cheat sheet

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1369791474788:dwif you have a unit circle like this

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0unit blob? look at the cheat sheet i sent, on the last page you see the unit circle

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0ok ... but where exaclty is it?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so \[\tan(\frac{\pi}{3})=\sqrt3\]

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0i dont understand all of the symbols

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0@satellite73 what do i do next

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0but it says to use 30 60 90 triangle

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0oh you are working in degrees. not problem since \(\tan(60)=\sqrt3\) you know \(\tan^{1}(\sqrt3)=60\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1369791928159:dw

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0tangent is opposite over adjacent is \(\sqrt3\)

lala2
 2 years ago
Best ResponseYou've already chosen the best response.0what about cos^1 (sqrt3)/2
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