anonymous
  • anonymous
Hello?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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GoldPhenoix
  • GoldPhenoix
Hello. Do you need help?
anonymous
  • anonymous
use a unit circle and 30 60 90 triangle to find value in degrees.. tan ^-1 sqrt 3
anonymous
  • anonymous
|dw:1369790876325:dw|

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anonymous
  • anonymous
can someone help
anonymous
  • anonymous
@onedirection822
anonymous
  • anonymous
@arykk
anonymous
  • anonymous
look on the unit circle to find where the second coordinate is \(-\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\)
anonymous
  • anonymous
oops sorry, should be second coordinate is \(\frac{\sqrt{3}}{2}\) and first coordinate is \(\frac{1}{2}\)
anonymous
  • anonymous
what does that look like?
anonymous
  • anonymous
you will find it on the last page of the attached cheat sheet
anonymous
  • anonymous
|dw:1369791474788:dw|if you have a unit circle like this
anonymous
  • anonymous
unit blob? look at the cheat sheet i sent, on the last page you see the unit circle
anonymous
  • anonymous
haah! thats mean!
anonymous
  • anonymous
ok ... but where exaclty is it?
anonymous
  • anonymous
look at the angle of \(\frac{\pi}{3}\) and you will see that the second coordinate is \(\frac{\sqrt{3}}{2}\) and the first coordinate is \(\frac{1}{2}\) and so \[\tan(\frac{\pi}{3})=\sqrt3\]
anonymous
  • anonymous
i dont understand all of the symbols
anonymous
  • anonymous
@satellite73 right here
1 Attachment
anonymous
  • anonymous
@satellite73 what do i do next
anonymous
  • anonymous
that is all
anonymous
  • anonymous
but it says to use 30 60 90 triangle
anonymous
  • anonymous
oh you are working in degrees. not problem since \(\tan(60)=\sqrt3\) you know \(\tan^{-1}(\sqrt3)=60\)
anonymous
  • anonymous
|dw:1369791928159:dw|
anonymous
  • anonymous
tangent is opposite over adjacent is \(\sqrt3\)
anonymous
  • anonymous
what about cos^-1 (sqrt3)/2
anonymous
  • anonymous
@satellite73

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