lala2
help!!!!!!!!!!!!!!!!!!!!!
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lala2
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use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2
lala2
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@chrisplusian help me please
anonymous
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do you have a copy of the triangle?
lala2
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no i dont
anonymous
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then you need one !
lala2
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how do i get it
lala2
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do you mean the sheet you gave me
lala2
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i have that
chrisplusian
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I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees
lala2
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thank you!