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lala2 Group TitleBest ResponseYou've already chosen the best response.0
use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^1 (sqrt3)/2
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
@chrisplusian help me please
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
do you have a copy of the triangle?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
then you need one !
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
how do i get it
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
do you mean the sheet you gave me
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
http://www.freemathhelp.com/triangle306090.html
 one year ago

chrisplusian Group TitleBest ResponseYou've already chosen the best response.1
I would set \[y=\cos^{1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees
 one year ago
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