## anonymous 3 years ago help!!!!!!!!!!!!!!!!!!!!!

1. anonymous

use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

2. anonymous

3. anonymous

do you have a copy of the triangle?

4. anonymous

no i dont

5. anonymous

then you need one !

6. anonymous

how do i get it

7. anonymous

do you mean the sheet you gave me

8. anonymous

i have that

9. anonymous
10. anonymous

I would set $y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })$ if you take the cosine of both sides you get $\cos(y)=\frac{ \sqrt{3} }{ 2 }$ cos is the x value in the unit circle.so the cosine value =$\frac{ \sqrt{3} }{ 2 }$ at $\frac{ \pi }{ 6 }$ or 30 degrees

11. anonymous

thank you!

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