lala2 Group Title help!!!!!!!!!!!!!!!!!!!!! one year ago one year ago

1. lala2

use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

2. lala2

@chrisplusian help me please

3. satellite73

do you have a copy of the triangle?

4. lala2

no i dont

5. satellite73

then you need one !

6. lala2

how do i get it

7. lala2

do you mean the sheet you gave me

8. lala2

i have that

9. satellite73
10. chrisplusian

I would set $y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })$ if you take the cosine of both sides you get $\cos(y)=\frac{ \sqrt{3} }{ 2 }$ cos is the x value in the unit circle.so the cosine value =$\frac{ \sqrt{3} }{ 2 }$ at $\frac{ \pi }{ 6 }$ or 30 degrees

11. lala2

thank you!