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lala2

help!!!!!!!!!!!!!!!!!!!!!

  • 10 months ago
  • 10 months ago

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  1. lala2
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    use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

    • 10 months ago
  2. lala2
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    @chrisplusian help me please

    • 10 months ago
  3. satellite73
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    do you have a copy of the triangle?

    • 10 months ago
  4. lala2
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    no i dont

    • 10 months ago
  5. satellite73
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    then you need one !

    • 10 months ago
  6. lala2
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    how do i get it

    • 10 months ago
  7. lala2
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    do you mean the sheet you gave me

    • 10 months ago
  8. lala2
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    i have that

    • 10 months ago
  9. satellite73
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    http://www.freemathhelp.com/triangle-30-60-90.html

    • 10 months ago
  10. chrisplusian
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    I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees

    • 10 months ago
  11. lala2
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    thank you!

    • 10 months ago
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