## lala2 Group Title help!!!!!!!!!!!!!!!!!!!!! one year ago one year ago

1. lala2 Group Title

use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

2. lala2 Group Title

3. satellite73 Group Title

do you have a copy of the triangle?

4. lala2 Group Title

no i dont

5. satellite73 Group Title

then you need one !

6. lala2 Group Title

how do i get it

7. lala2 Group Title

do you mean the sheet you gave me

8. lala2 Group Title

i have that

9. satellite73 Group Title
10. chrisplusian Group Title

I would set $y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })$ if you take the cosine of both sides you get $\cos(y)=\frac{ \sqrt{3} }{ 2 }$ cos is the x value in the unit circle.so the cosine value =$\frac{ \sqrt{3} }{ 2 }$ at $\frac{ \pi }{ 6 }$ or 30 degrees

11. lala2 Group Title

thank you!