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lala2

  • one year ago

help!!!!!!!!!!!!!!!!!!!!!

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  1. lala2
    • one year ago
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    use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

  2. lala2
    • one year ago
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    @chrisplusian help me please

  3. satellite73
    • one year ago
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    do you have a copy of the triangle?

  4. lala2
    • one year ago
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    no i dont

  5. satellite73
    • one year ago
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    then you need one !

  6. lala2
    • one year ago
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    how do i get it

  7. lala2
    • one year ago
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    do you mean the sheet you gave me

  8. lala2
    • one year ago
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    i have that

  9. satellite73
    • one year ago
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    http://www.freemathhelp.com/triangle-30-60-90.html

  10. chrisplusian
    • one year ago
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    I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees

  11. lala2
    • one year ago
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    thank you!

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