Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

lala2 Group Title

help!!!!!!!!!!!!!!!!!!!!!

  • one year ago
  • one year ago

  • This Question is Closed
  1. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

    • one year ago
  2. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @chrisplusian help me please

    • one year ago
  3. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    do you have a copy of the triangle?

    • one year ago
  4. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    no i dont

    • one year ago
  5. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    then you need one !

    • one year ago
  6. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how do i get it

    • one year ago
  7. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    do you mean the sheet you gave me

    • one year ago
  8. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i have that

    • one year ago
  9. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.freemathhelp.com/triangle-30-60-90.html

    • one year ago
  10. chrisplusian Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees

    • one year ago
  11. lala2 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you!

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.