help!!!!!!!!!!!!!!!!!!!!!

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help!!!!!!!!!!!!!!!!!!!!!

Mathematics
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use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2
@chrisplusian help me please
do you have a copy of the triangle?

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no i dont
then you need one !
how do i get it
do you mean the sheet you gave me
i have that
http://www.freemathhelp.com/triangle-30-60-90.html
I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees
thank you!

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