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lala2

  • one year ago

just a quick question!

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  1. lala2
    • one year ago
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    in triangle ABC , angle B is a right angle. AB+30 and Sec A=5/3. find each value in fraction and decimal form

  2. lala2
    • one year ago
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    sin A

  3. lala2
    • one year ago
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    someone??

  4. aditya96
    • one year ago
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    sin a =4/5

  5. lala2
    • one year ago
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    ok but how did you get that

  6. aditya96
    • one year ago
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    |dw:1369794012893:dw| here sec a=hyppoteneus/adjacent so hp=5 and adj=3 so opposite side =4 by pythagorus thm so sin a=opposite/hypp=4/5

  7. lala2
    • one year ago
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    its sin A

  8. lala2
    • one year ago
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    isnt sin opposite/ hypotenuse

  9. aditya96
    • one year ago
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    no sinA=opposite/hyp

  10. chrisplusian
    • one year ago
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    you said sec A=5/3 so the sec=hyp/adj. the hyp=5 and the side adjacent to angle A would be adjacent. Through pythagorean theorem you can find the other value because it is a right triangle

  11. lala2
    • one year ago
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    in the pathagorema theorem what values go with what is a=5 and c=3?

  12. lala2
    • one year ago
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    @chrisplusian @aditya96

  13. aditya96
    • one year ago
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    b=4

  14. lala2
    • one year ago
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    i know that but i need to show work so what goes where

  15. lala2
    • one year ago
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    does a=3 c=5?

  16. aditya96
    • one year ago
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    (hypo)^2=(side 1)^2 +(side 2)^2

  17. lala2
    • one year ago
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    @chrisplusian can you help me with one more

  18. lala2
    • one year ago
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    csc C

  19. lala2
    • one year ago
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    sam thing but with these values

  20. chrisplusian
    • one year ago
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    The trick with pythagorean theorem is that the "c" is always the hypotenuse

  21. lala2
    • one year ago
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    ohh

  22. chrisplusian
    • one year ago
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    Csc=Hyp/opp so the opposite side from angle C is =3 and the hypotenuse is =5. so csc C =5/3

  23. chrisplusian
    • one year ago
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    Hope that helps @lala2

  24. lala2
    • one year ago
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    yes it does alot! thanks soo much!

  25. chrisplusian
    • one year ago
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    no problem I have to do some studying now so good luck

  26. lala2
    • one year ago
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    ok thanks again!

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