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lala2

  • one year ago

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  1. Euler271
    • one year ago
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    law of cosines: \[c^2 = a^2 + b^2 - 2abcos(\theta)\] c is the longest side, notice that pythagoras' is the special case of law of cosines, where theta = 90. \[165^2 = 83^2 + 111^2 - 2(83)(111)\cos(\theta)\]

  2. Euler271
    • one year ago
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    you end up with: cos(theta) = 0.434983175 so with your calculator, use the cos^(-1) button on 0.434983175 (cos inverse) to get the obtuse angle: 64.2 degrees the direction north of west would be 180 degrees - 64.2 degrees

  3. lala2
    • one year ago
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    @Euler271 ??

  4. lala2
    • one year ago
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    @phi ?

  5. phi
    • one year ago
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    yes

  6. phi
    • one year ago
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    Re-reading the question, they want the angle "degrees North of West"

  7. phi
    • one year ago
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    |dw:1369857679392:dw|

  8. phi
    • one year ago
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    Euler lost a minus sign the angle you want plus 115.8 add up to a straight line

  9. phi
    • one year ago
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    answer + 115.8 =180 solve for answer

  10. phi
    • one year ago
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    I would add -115.8 to both sides

  11. phi
    • one year ago
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    yes, the ship was heading west (270 degrees) and it turned 64.2º toward the north.

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