lala2
Can some one help me!



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jim_thompson5910
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part a)
solve for x
sin(30)/x = sin(120)/22

jim_thompson5910
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part b)
A = (1/2)*b*c*sin(theta)
A = (1/2)*x*x*sin(120) < you're using the result you got for x from part a)

jim_thompson5910
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part a) is correct

jim_thompson5910
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i didn't say B was wrong, still checking

jim_thompson5910
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for part B, I'm getting 69.859382571945, so that's pretty close to what you got

lala2
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oh ok!

lala2
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Great! Thanks! Can i tag you in one more!
