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lala2

  • one year ago

Can some one help me!

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  1. jim_thompson5910
    • one year ago
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    part a) solve for x sin(30)/x = sin(120)/22

  2. jim_thompson5910
    • one year ago
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    part b) A = (1/2)*b*c*sin(theta) A = (1/2)*x*x*sin(120) <--- you're using the result you got for x from part a)

  3. jim_thompson5910
    • one year ago
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    part a) is correct

  4. jim_thompson5910
    • one year ago
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    i didn't say B was wrong, still checking

  5. jim_thompson5910
    • one year ago
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    for part B, I'm getting 69.859382571945, so that's pretty close to what you got

  6. lala2
    • one year ago
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    oh ok!

  7. lala2
    • one year ago
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    Great! Thanks! Can i tag you in one more!

  8. jim_thompson5910
    • one year ago
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    ok

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spraguer (Moderator)
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