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lala2 Group Title

Help please!!!

  • one year ago
  • one year ago

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  1. Viper_Feronzie Group Title
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    With?

    • one year ago
  2. Viper_Feronzie Group Title
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    No, sorry. The fact that it IS an identity makes it a bit difficult to verify any other way.

    • one year ago
  3. lala2 Group Title
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    @phi

    • one year ago
  4. lala2 Group Title
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    @tcarroll010

    • one year ago
  5. juanse254 Group Title
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    sure

    • one year ago
  6. tcarroll010 Group Title
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    I can do this, hold on, @lala2

    • one year ago
  7. lala2 Group Title
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    ok :)

    • one year ago
  8. tcarroll010 Group Title
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    \[1 + \frac{ \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]\[\frac{ \sin ^{2}\theta + \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]

    • one year ago
  9. tcarroll010 Group Title
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    The first equation shows the left side = right side The second equation shows the left side. What I did was show that the left side equals the right side.

    • one year ago
  10. lala2 Group Title
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    oh ok!

    • one year ago
  11. tcarroll010 Group Title
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    In other words, I showed that: 1/sin^2 = 1/sin^2

    • one year ago
  12. lala2 Group Title
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    thats clear!

    • one year ago
  13. tcarroll010 Group Title
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    All good now? I gotta go eat! @lala2

    • one year ago
  14. lala2 Group Title
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    yeah! Thanks!:)

    • one year ago
  15. lala2 Group Title
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    im no longer typing have no idea why it says that!

    • one year ago
  16. tcarroll010 Group Title
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    Good luck to you in all of your studies, and thx for the recognition! @lala2

    • one year ago
  17. lala2 Group Title
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    Thanks!

    • one year ago
  18. tcarroll010 Group Title
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    uw!

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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