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Viper_Feronzie
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With?
Viper_Feronzie
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No, sorry. The fact that it IS an identity makes it a bit difficult to verify any other way.
lala2
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@phi
lala2
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@tcarroll010
juanse254
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sure
tcarroll010
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I can do this, hold on, @lala2
lala2
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ok :)
tcarroll010
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\[1 + \frac{ \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]\[\frac{ \sin ^{2}\theta + \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]
tcarroll010
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The first equation shows the left side = right side
The second equation shows the left side.
What I did was show that the left side equals the right side.
lala2
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oh ok!
tcarroll010
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In other words, I showed that:
1/sin^2 = 1/sin^2
lala2
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thats clear!
tcarroll010
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All good now? I gotta go eat! @lala2
lala2
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yeah! Thanks!:)
lala2
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im no longer typing have no idea why it says that!
tcarroll010
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Good luck to you in all of your studies, and thx for the recognition! @lala2
lala2
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Thanks!
tcarroll010
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uw!