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lala2

HELP!

  • 11 months ago
  • 11 months ago

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  1. lala2
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    @satellite73 please help

    • 11 months ago
  2. jkristia
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    if you know SOH CAH TOA, and you have cos given, then you can fill in the remaining legs and angle of the triangle using 'sin' and Pythagorean theorem. It might help if you start by drawing a right angled triangle. Call one of the angles for theta, and then fill in the one leg and the hypotenuse using the values given by cos (theta)

    • 11 months ago
  3. lala2
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    im really new to this think you give give me step by step instructions

    • 11 months ago
  4. jkristia
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    |dw:1369876988964:dw| Now to find the 'vertical' side of the triangle you can use Pythagorean. And once you have that length you can fill in the other trig ratios sin, cos, tan tan = sin / cos csc = 1/sin sec = 1 / cos cot = 1 / tan

    • 11 months ago
  5. jkristia
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    you are given cos (x) = 2/5, and you know cos (x) = adjacent / hyp, so there you are given 2 sides

    • 11 months ago
  6. jkristia
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    Think of trig functions as ratios. Cos (x) gives you a ratio of the adjacent (horz) side divided by the hyp side

    • 11 months ago
  7. jkristia
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    correct, so you found the 'opposite side' (I have to run, so I don't have time to double check right now)

    • 11 months ago
  8. jkristia
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    on the vertical side, that is the length you just found

    • 11 months ago
  9. jkristia
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    have to run - sorry

    • 11 months ago
  10. lala2
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    befor you leave whats the next step?

    • 11 months ago
  11. lala2
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    @satellite73 can you help me finish this?

    • 11 months ago
  12. lala2
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    @timo86m how do i finish this??

    • 11 months ago
  13. DEVESHkishore
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    sin= opp/hyp cos=adj/hyp tan=opp/adj cosec=hyp/opp sec=hyp/adj cot=adj/opp put the values you will get all the 6 quantities

    • 10 months ago
  14. lala2
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    Thanks @DEVESHkishore

    • 10 months ago
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