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lala2

  • one year ago

HELP!

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  1. lala2
    • one year ago
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    @satellite73 please help

  2. jkristia
    • one year ago
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    if you know SOH CAH TOA, and you have cos given, then you can fill in the remaining legs and angle of the triangle using 'sin' and Pythagorean theorem. It might help if you start by drawing a right angled triangle. Call one of the angles for theta, and then fill in the one leg and the hypotenuse using the values given by cos (theta)

  3. lala2
    • one year ago
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    im really new to this think you give give me step by step instructions

  4. jkristia
    • one year ago
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    |dw:1369876988964:dw| Now to find the 'vertical' side of the triangle you can use Pythagorean. And once you have that length you can fill in the other trig ratios sin, cos, tan tan = sin / cos csc = 1/sin sec = 1 / cos cot = 1 / tan

  5. jkristia
    • one year ago
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    you are given cos (x) = 2/5, and you know cos (x) = adjacent / hyp, so there you are given 2 sides

  6. jkristia
    • one year ago
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    Think of trig functions as ratios. Cos (x) gives you a ratio of the adjacent (horz) side divided by the hyp side

  7. jkristia
    • one year ago
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    correct, so you found the 'opposite side' (I have to run, so I don't have time to double check right now)

  8. jkristia
    • one year ago
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    on the vertical side, that is the length you just found

  9. jkristia
    • one year ago
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    have to run - sorry

  10. lala2
    • one year ago
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    befor you leave whats the next step?

  11. lala2
    • one year ago
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    @satellite73 can you help me finish this?

  12. lala2
    • one year ago
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    @timo86m how do i finish this??

  13. DEVESHkishore
    • one year ago
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    sin= opp/hyp cos=adj/hyp tan=opp/adj cosec=hyp/opp sec=hyp/adj cot=adj/opp put the values you will get all the 6 quantities

  14. lala2
    • one year ago
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    Thanks @DEVESHkishore

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