Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
sasogeek
Group Title
if i add (x to one) and subtract one from (x plus root of one squared), i get a number twice as big as (x minus itself), what is x?
 one year ago
 one year ago
sasogeek Group Title
if i add (x to one) and subtract one from (x plus root of one squared), i get a number twice as big as (x minus itself), what is x?
 one year ago
 one year ago

This Question is Closed

AravindG Group TitleBest ResponseYou've already chosen the best response.3
First form the equation using the info given
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
go right ahead :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
lol why not you try first :)
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
alright... this is what i get :P lol uhmm... add x to one, so, x+1 and subtract one from x plus root of one squared, (x+1)+(x+1^21) that's equal to a number twice as big as x minus itself, so (x+1)+(x+1^21)=2*(xx) correct?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
(Hey, congrads!)
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
nope! LOOOL, look at this line :P and subtract one from x plus root of one squared, (x+1)+(x+1^21) where's the root of one squared? it's only one squared, there's no root :P
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
\[\sqrt{1^2}=1\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
No difference :)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
The question is kinda confusing. What does it exactly say? What are you doing with \(x + 1\) and \((x + \sqrt{1})^2  1\)?
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
that makes all the difference in the initial equation. i think it matters though result may be the same, lol
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
@ParthKohli the full equation is what i have written down, (x+1)+(x+1^21)=2*(xx) but then this part is supposed to be \(\large (x+ \sqrt{1^2}1) \) :)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Is the question this?\[(x + 1) + (x + \sqrt{1})^2  1 = 2(x  x)\]If so, you have \((x + 1) + (x + \sqrt{1})^2  1 = 0\)
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
tbh though i shouldn't have let that one out lol, it was supposed to be left for you to figure out :P
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
actually When you frame the equation it should be important \[(x+1)+(x+\sqrt{1}^21)=2 * (xx)\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Hmm, but I don't think that it'd be \(\sqrt{1}^2\), but if you insist so...
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
root of 1 squared has only 1 meaning lol, \(\sqrt{1^2} \)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
No... this can't be
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
You will have two solutions then, I guess.
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
nope, just one
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
\[\sqrt{1^2}=1\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
Okay so why not solve it straight away @sasogeek ?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Since \(\sqrt{1^2} = \sqrt{1} = \pm 1\) you may have to solve both equations\[(x + 1) +(x  1)1 = 0\]\[(x+1) + (x + 1) 1 =0\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
omg \[\sqrt{1} \neq \pm 1\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@AravindG Why not?
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
\(\large \sqrt{1^2}=1^{2*\frac{1}{2}}=1 \)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
Because square root is a function having range as positive real numbers
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[(1)^2 = 1 \Rightarrow 1 = \sqrt{1}\]\[(1)^2 = 1 \Rightarrow 1 = \sqrt{1}\]\[\therefore \sqrt{1} = \pm 1\]@AravindG The domain is positive real number, not the range
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Or actually, the domain is nonnegative real numbers.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
@ParthKohli you are having a serious misconception on square roots .
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
you don't have to spam
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@AravindG Wasn't my demonstration enough?
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
can we just solve my problem and take this to another thread, lol
 one year ago

Peter14 Group TitleBest ResponseYou've already chosen the best response.0
so where was this problem from?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
I can explain it to you separately not here
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
my head, @Peter14
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
Lets finish this problem first
 one year ago

Peter14 Group TitleBest ResponseYou've already chosen the best response.0
you have an interesting head.
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
lol why thank you :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
ok @sasogeek proceed :)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
If you want to neglect one root of \(1\), you may. Just consider \(1\) as the root of 1 if you want to. But seriously, this equation has two possible solutions.
 one year ago

dumbsearch2 Group TitleBest ResponseYou've already chosen the best response.0
LOL @Peter14
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.3
@ParthKohli I can make a separate thread for your query .
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
it's not that hard u guys _, it boils down to 2x+1=0, hard? i don't think so xD
 one year ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
x=\(\frac{1}{2} \)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.