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allie_bear22

  • 2 years ago

iumuikm

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  1. .Sam.
    • 2 years ago
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    Is the denominator x^2-9?

  2. .Sam.
    • 2 years ago
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    Try factor x^2-9 again, you factored it wrong

  3. .Sam.
    • 2 years ago
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    Nope

  4. .Sam.
    • 2 years ago
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    \[x^2-9=(x-3)(x+3)\]

  5. .Sam.
    • 2 years ago
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    No, we gotta factorize it, \[\frac{x^2-5x+6}{x^2-9}= \frac{(x-2)(x-3)}{(x-3)(x+3)}=\frac{(x-2)\cancel{(x-3)}}{\cancel{(x-3)}(x+3)}=\frac{x-2}{x+3}\]

  6. .Sam.
    • 2 years ago
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    Oh, from step 1 to 2, you factor both denominator and numerator, then cancel like terms from step 2 to 3, leaving x-2/x+3

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