## allie_bear22 Group Title iumuikm one year ago one year ago

1. .Sam.

Is the denominator x^2-9?

2. .Sam.

Try factor x^2-9 again, you factored it wrong

3. .Sam.

Nope

4. .Sam.

$x^2-9=(x-3)(x+3)$

5. .Sam.

No, we gotta factorize it, $\frac{x^2-5x+6}{x^2-9}= \frac{(x-2)(x-3)}{(x-3)(x+3)}=\frac{(x-2)\cancel{(x-3)}}{\cancel{(x-3)}(x+3)}=\frac{x-2}{x+3}$

6. .Sam.

Oh, from step 1 to 2, you factor both denominator and numerator, then cancel like terms from step 2 to 3, leaving x-2/x+3