Here's the question you clicked on:
allie_bear22
iumuikm
Is the denominator x^2-9?
Try factor x^2-9 again, you factored it wrong
No, we gotta factorize it, \[\frac{x^2-5x+6}{x^2-9}= \frac{(x-2)(x-3)}{(x-3)(x+3)}=\frac{(x-2)\cancel{(x-3)}}{\cancel{(x-3)}(x+3)}=\frac{x-2}{x+3}\]
Oh, from step 1 to 2, you factor both denominator and numerator, then cancel like terms from step 2 to 3, leaving x-2/x+3